[ad_1] Step 1: Combine all the arrays Step 2: Sort arrays using Arrays.sort(array); Step 3: Remove the duplicates. int[] a = {1,2,3,4,5}; int[] b = {1,2,3,4,5,6}; int[] c = {1,3,7}; int[] d = {2,3,4,8,9,10}; int[] resultArray1 = new int[a.length+b.length+c.length+d.length]; int arrayIndex = 0; for (int i=0; i< a.length ; i++, arrayIndex++ ) { resultArray1[arrayIndex] = … Read more
[ad_1] Your data model should be as follows: public class Info { public string prop1 {get;set;} public string prop2 {get;set;} public int prop3 {get;set;} // Modified from //public Dictionary<string, List<int>> prop4 {get;set} public List<Dictionary<string, int>> prop4 {get;set;} } public class Response { // Modified from //public class Dictionary<string, List<Info>> Item {get;set;} public Dictionary<string, Info> Items … Read more
[ad_1] The command for this is ATND. Just send the packet 0x7E 0x00 0x06 0x08 0x01 0x41 0x54 0x4E 0x44 0xCF to the coordinator. 0 [ad_2] solved Zigbee Network in API mode
[ad_1] No, and for a good reason: users should always have control over what’s executed in their user agents. Why don’t you just minify and obfuscate the code? 3 [ad_2] solved Protect javascript code from copying [duplicate]
[ad_1] Throughout this post let’s assume numbers are one hex digit, just for simplicity. “>>” is the bit shift operator. For example: 8 >> 1 == 8 / 2 == 4; Which in binary is equivalent to b1000 >> 1 == b0100; Adding the third “>” into the operator inserts a 0 into the now … Read more
[ad_1] Nested* Nested_create(List list) { Nested* new = malloc(sizeof(Nested)); new->list = list; new->next = NULL; return new; } void Nested_add(Nested** proot, Nested* node) { if (*proot == NULL) { *proot = node; } else { Nested* cur = *proot; while (cur->next) cur = cur->next; cur->next = node; } } void createlistoflists(Nested **LIST, List list1, List … Read more
[ad_1] Your for loop is shorthand for the following code: int i = start; if (i <= end) { /* loop body */ i += step; } To answer your question, it will run ceiling((end – start + 1) / step) times. Walk through the logic on paper to see if you come to the … Read more
[ad_1] The framework is still free and available (Click Free Download, sign in, and you will be given the option to download the free version). What Telerik (we) are selling is derived from the Design canvas, which was commercial before the merge. 2 [ad_2] solved Looking for WebAii Framework free edition online – before the … Read more
[ad_1] You could pass a pointer and de-reference it in the function: int num5(int* pnum) { *pnum = 5; // you may want to check that pnum is not NULL return 0; // presumably you don’t always return 0 in real code } Then int number = 42; printf(“%d”, number); // prints 42 int ret … Read more
[ad_1] Well designed test shows that first function is slowest on Python 2.x (mostly because two lists have to be created, first one as a increasing range, second one as a reverted first one). I also included a demo using reversed. from __future__ import print_function import sys import timeit def iterate_through_list_1(arr): lala = None for … Read more
[ad_1] How about this: String greetings = “Hello” + “,” + ” how are you”; Or this: String greetings = “Hello how are you”; greetings = greetings.substring(0, 5) + “,” + greetings.substring(5); Or this: String greetings = “Hello how are you”; greetings = new StringBuilder(greetings).insert(5, “,”).toString(); Inserting a punctuation mark is trivial if you know … Read more
[ad_1] Your test annotations does not belongs to TestNG. Replace @Before with @BeforeTest @After with @AfterTest @Test should point TestNG library 1 [ad_2] solved Selenium TestNG – java.lang.NullPointerException
[ad_1] It looks like you do not want to print boolean array: it’s of little use. You need to print the primes from the Sieve of Eratosthenes, which can be done by enumerating the indexes, checking if primes[i] is true, and printing the index if it is. boolean primes = sieve(100); for (int i = … Read more
[ad_1] You can flatten the internal dict and update it back to the original dict. Eg., product = d.pop(“product”)[0] flattened = {f”product.{key}”: value for key, value in product.items()} d.update(flattened) This should do the trick. 1 [ad_2] solved Flat a list of containing only one dict
[ad_1] I think this example would help: http://gianlucaguarini.com/canvas-experiments/jQuery.BlackAndWhite/ 1 [ad_2] solved Responsive Photo gallery JQuery [closed]