Kirat Getters and setters are used in order to prevent code outwith the class from accessing implementation details. Maybe today some piece of data is just a string, but tomorrow it has be created by joining two other strings together and also keeping a count of the number of times the string is retrieved (OK, contrived … Read more
With this code you are doing linear probing index = hash(entry.key); while (!is_vacant(index)) index = next_index(index); template <class RecordType> inline std::size_t table<RecordType>::next_index(std::size_t index) const // Library facilities used: cstdlib { return ((index+1) % CAPACITY); } Say your map is nearly full and hash returns 23, then the next slots you are going to test will … Read more
You are returning an array. The salary is in the the first position of you array. If you want to see the salary you would need to use return salary[0]; in your method. or System.out.println(calculateSalary(salary,riseRate)[0]); in the main. What you’re trying to print right now is the actual array, not a value. I am not … Read more
I assume that the isHttps variable check is there for a reason(?) and therefore the second cast should actually be HttpURLConnection, meaning there is a typo in the question? If so the most methods used in the question are available in the parent class URLConnection without a cast, but not all. Fortunately HttpsURLConnection is a … Read more
You could get the length of the list of items after splitting: len(my_long_string.split(‘;’)) Alternatively, count the number of semicolons and add one: my_long_string.count(‘;’) + 1 The latter is probably faster if you don’t need to know what the items are, but only how many items there are. len is a function that returns the number … Read more
document.getElementById(“test”).innerHTML = “Who”; NOT document.getElementIdBy(“test”).innerHTML = “Who”; 0 solved Javascript code will not run at all
Here you go: jsFiddle You just needed to place the content in a <div> and add the following CSS to it. .container { width:40%; text-align:right; } 0 solved Setting text at right side of screen
Since your tuples are just repeating the same number, just use a range loop and create the tuple from scratch: for i in range(256): rgb = (i, i, i) There is no need to add up here. Alternatively, calculate i from the frame. 30 frames in a second? Divide 256 by 30 to get a … Read more
Here is a version of your code which doesn’t break aliasing rules: class Foo { public: Foo() : userData(0L) { } long userData; }; void Destroy(Foo* pFoo) { if (–pFoo->userData <= 0) { delete pFoo; } } int main() { int i = 0; while (i < 10) { Foo* pFoo = new Foo(); pFoo->userData … Read more
This can be modelled as a graph problem. Create a graph node for each row and column where there’s a monster. Connect the nodes if a monster is on that row and that column. This is a bipartite graph, and you want to do minimum vertex cover. König’s theorem shows that for bipartite graphs the … Read more
If you’re simply looking for its index in the loop: <textarea name=”description{{ loop.index }}”> Here’s the docs. 1 solved How to attach counter variable on field in twig file?
What is the difference between char *exp=”a+b” and char exp[]=”a+b”? Are they stored the same way in memory or they differ? solved What is the difference between char *exp=”a+b” and char exp[]=”a+b”? Are they stored the same way in memory or they differ?
This issue was only present in the PyPI distribution of PyPDF2==2.3.0 for a couple of hours. It was fixed with release 2.3.1. See #1011 for more details I’m the maintainer of PyPDF2. I’m sorry I caused some headaches. You can update PyPDF2 via: pip install PyPDF2 –upgrade solved No module named ‘PyPDF2._codecs’, even after already … Read more
Remove the last word from success and assign to failure: import re success = “Today’s day is Wednesday”; failure = re.sub(r’\w+$’, ”, success) solved How to make sure the beginning of two strings match until the last word(s)? [closed]
You can use glob for get all files with pattern coord.* in your path and rename them with os.rename. import os import glob path=”Files/” for file in glob.glob(path+’coord.*’): f,s = file.split(‘.’,1) file_new = f+’N.’+s os.rename(file, file_new) First filenames: coord.1.txt coord.1.png After renaming: coordN.1.txt coordN.1.png 0 solved Renaming files that have specific format like text.* [closed]