[Solved] php function is not working? [closed]

[ad_1] In your case there are too many unknowns. First of all you must enable a proper error reporting level and – only for development – let the errors be displayed on screen. Second, there are important error/failure situations which you are not covering with your exception handling code. Also, I would use bindValue() instead … Read more

[Solved] Python and curl equivalent

[ad_1] Solved mydata = {’email’: form.vars.email, ‘password’:form.vars.password} resp= requests.post(‘url’, json = mydata) I don’t know why but I had already tried it and it didn’t work [ad_2] solved Python and curl equivalent

[Solved] show title of the page in tab of browser

[ad_1] you can follow default routine for displaying title in ASP.NET MVC. in _Layout.cshtml <html lang=”en”> <head> <meta charset=”utf-8″ /> <title>Your SiteName | @ViewBag.Title</title> . . in other pages just set ViewBag.Title. for example login page @model LoginModel @{ ViewBag.Title = “Login page”; } 0 [ad_2] solved show title of the page in tab of … Read more

[Solved] PHP – Why there is a difference in the output of the echo statement and the print_r() function when viewed in a browser? Please explain

[ad_1] PHP – Why there is a difference in the output of the echo statement and the print_r() function when viewed in a browser? Please explain [ad_2] solved PHP – Why there is a difference in the output of the echo statement and the print_r() function when viewed in a browser? Please explain

[Solved] How I Add Button Go To The Instagram? [duplicate]

[ad_1] I believe this is what you’re looking for (not entirely sure since your question wasn’t very descriptive). NSURL *url = [NSURL URLWithString:@”instagram://user?username=USERNAME”]; if ([[UIApplication sharedApplication] url]) { [[UIApplication sharedApplication] url]; } else { // handle the issue } Otherwise, see the instagram api here. [ad_2] solved How I Add Button Go To The Instagram? … Read more

[Solved] You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ”’)

[ad_1] No need to use single quote with table name(‘operations’) & specify table name with row like groupName.operations, group_ID.operations. 2 [ad_2] solved You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ”’)

[Solved] Similarity measure in classification algorithm

[ad_1] There a number of possible measures of similarity. Ideally, you should derive one yourself that takes account of the reason why you are doing this classification, so that good similarity scores amount to something that performs well when you use it in practice. Here are a few examples. 1) Cosine similarity. Treat the two … Read more

[Solved] Cell Value Increment and Offset

[ad_1] Try using Public Variable like this: Public n As Long ‘~~> Declare a public variable at the top of the module Then in your sub try something like this: With Sheets(“Sheet1”).Range(“A6”).Offset(n, 0) ‘~~> change to suit If n = 0 Then .Value = 1 Else .Value = .Parent.Range(.Address).Offset(-1, 0) + 1 End If n … Read more

[Solved] Passing a variable from parent to child class in Java

[ad_1] The variable firstname1 is a local variable. You can’t access it outside its scope – the method. What you can do is pass a copy of the reference to your subclass. Since you’re calling a static method, the easiest way is to pass the reference as an argument to the method call: @Test public … Read more

[Solved] Laravel check if user exists

[ad_1] User with the same name, surname, and birthday $duplicate_user = \DB::table(‘users’) ->where(‘name’, ‘LIKE’, $new_name) ->where(‘surname’, ‘LIKE’, $new_surname) ->where(‘birthday’, ‘=’, $new_birthday) ->first(); if($duplicate_user) { return response(‘This user already exists’, 422); } [ad_2] solved Laravel check if user exists