Kirat[ad_1] You need a timer that each time it runs, either update the list view’s current items or just clear and re-add new items: Timer timer = new Timer{ Interval = 60000, Enabled = true }; //every minute timer.Tick += (s, e) => { chatverlauf.Items.Clear(); var StatusList = … // get the list of servers … Read more
[ad_1] Your issue is with this line: NSURL *U1 =[NSURL URLWithString:[dict objectForKey:@”img”]]; The problem is caused by the fact that you assume: [dict objectForKey:@”img”] is returning an NSString when in fact it is returning an NSNumber representing a boolean value. You need to either figure out why the data in the dictionary is incorrect or … Read more
[ad_1] This code returns ordered names of all men in collection: public static IEnumerable<string> OrderedMales(IEnumerable<Person> persons) { return persons.Where(p => p.Sex == Gender.Male).OrderBy(p => p.Name).Select(p => p.Name); } 0 [ad_2] solved How do I import data from a class C#
[ad_1] You may use a BackgroundWorker to do the operation that you need in different thread like the following : BackgroundWorker bgw; public Form1() { InitializeComponent(); bgw = new BackgroundWorker(); bgw.DoWork += bgw_DoWork; } private void Form1_DragDrop(object sender, DragEventArgs e) { if (e.Data.GetDataPresent(DataFormats.FileDrop)) { string[] s = (string[])e.Data.GetData(DataFormats.FileDrop, false); bgw.RunWorkerAsync(s); } } Also for your … Read more
[ad_1] You have different indexes in the loops: for(int k = j+1; k < n; ++k) for(int l = k+1; l < n; ++l) and for k in range(i+2, n): for l in range(i+3, n): Basically, the indexes in the inner loops in your C++ code change accordingly to the loop that is one line … Read more
[ad_1] The image I need has to move around the screen An important piece of information missing in the original question. I don’t have a problem using a null layout for this. I wanted to move around with arrow keys on the screen? And don’t use a KeyListener for this. Instead you should be using … Read more
[ad_1] If you get the same values for every pixel there are several possible reasons. a) your image has the same values in every pixel b) you do not change x and y between your calls to getRGB c) you read something else but the return value of getRGB [ad_2] solved getRGB(x,y) in Java awt … Read more
[ad_1] Finally i got the solution : <vector xmlns:android=”http://schemas.android.com/apk/res/android” android:viewportWidth=”500″ android:viewportHeight=”749″ android:width=”625dp” android:height=”936.25dp”> <group android:scaleX=”0.1″ android:scaleY=”-0.1″ android:translateY=”749″> <path android:pathData=”M439 7416C282 7361 169 7248 113 7090l-23 -65 0 -1751c0 -1693 1 -1753 19 -1806 35 -101 99 -185 184 -241 57 -38 90 -50 442 -162 132 -42 701 -224 1265 -405 564 -180 1084 -346 … Read more
[ad_1] Store all of your developer infrastructure (developer workstations, TFS infrastructure, etc) in an isolated building. This building should have no internet access whatsoever. Post security guards outside the building. Armed is preferable, but not strictly necessary. Each person entering the building should be stopped by the security guards and forced to surrender all personal … Read more
[ad_1] Using html, css and jQuery you can get your desired output. Please check below code. function getHtml() { var test = $(“#input”).text(); $(“#output”).show(); $(“#remove”).show(); $(“#output”).text(test); } function remove() { $(“#output”).hide(); $(“#remove”).hide(); } #output { display: none; } #remove { display: none; } <script src=”https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js”></script> <div id=”input”> Input: welcome </div> <button onClick=”getHtml()”>Click</button> <div id=”output”> </div> … Read more
[ad_1] Another approach is through bsxfun and unique. Assuming that A is a row vector, you would do the following: un = unique(A.’, ‘stable’); out = bsxfun(@times, bsxfun(@eq, A, un), un); out contains your desired result. This code deserves some explanation. The first line of code determines all unique entries in A stored in un, … Read more
[ad_1] def map(func, values): rest = values[1:] if rest: yield from map(func, rest) else: yield func(values[0]) It’s a generator so you can iterate over it: for result in map(int, ‘1234’): print(result + 10) Gives: 11 12 13 14 4 [ad_2] solved how to implement map and reduce function from scratch as recursive function in python? … Read more
[ad_1] In your EntityTypeConfiguration you can do something like this: Property(m => m.CompanyId) .HasColumnAnnotation(“Index”, new IndexAnnotation(new IndexAttribute(“IX_YourUniqueIndexName”, 1) { IsUnique = true })); Property(m => m.Code) .HasColumnAnnotation(“Index”, new IndexAnnotation(new IndexAttribute(“IX_YourUniqueIndexName”, 2) { IsUnique = true })); This will create a unique index on those 2 columns. Make sure you use the same name for the … Read more
[ad_1] You can use a regular expression to look for _cell_length_a (or any other key), followed by some spaces, and then capture whatever comes after that until the end of that line. >>> import re >>> re.findall(r”_cell_length_a\s+([0-9.]+)”, metadatastructure) [‘2.51636378’, ‘2.51636378’] Or using a list-comprehension with splitlines, startswith and split: >>> [line.split()[-1] for line in metadatastructure.splitlines() … Read more
[ad_1] The first issue is that you have conflicting CNAME entries. Start by removing all CNAME entries where the hostname is “www”. Then create one new CNAME entry. The hostname field should be “www” and the Destination CNAME should be your Heroku app hostname “rainbow-mutiny-636.herokuapp.com”. Now go to your Rails app directory and run heroku … Read more