[Solved] Android Application Compatibility [closed]

I think you are looking for this <supports-screens android:resizeable=[“true”| “false”] android:smallScreens=[“true” | “false”] android:normalScreens=[“true” | “false”] android:largeScreens=[“true” | “false”] android:xlargeScreens=[“true” | “false”] android:anyDensity=[“true” | “false”] android:requiresSmallestWidthDp=”integer” android:compatibleWidthLimitDp=”integer” android:largestWidthLimitDp=”integer”/> But Seriously By giving this you can not achieve what you are looking for Read this from developer site also an example 2 solved Android Application Compatibility … Read more

[Solved] SQL querying – Doctors and Hospitals [closed]

I’ll help you with your first question, and I’ll leave to you the second. Display doctorid, dname, total fees received by the doctor(s) who have treated more than one patient? Let’s split this problem in pieces: So you need first to know which doctors have treated more than one patient. That information is in the … Read more

[Solved] SQL querying – Doctors and Hospitals [closed]

Introduction SQL querying is a powerful tool for managing data in a database. It is used to retrieve, manipulate, and store data in a database. In this article, we will discuss how to use SQL querying to manage data related to doctors and hospitals. We will look at how to query data related to doctors, … Read more

[Solved] How can I extract a string using C# Substring [closed]

Instead of splitting the useragent, you should use the properties already supplied the Asp.net Framework to detect the browser/os. Use this to get the browser name Request.Browser.Browser and browser version Request.Browser.MajorVersion to get the Os name Request.Browser.Platform and os version Request.UserAgent 1 solved How can I extract a string using C# Substring [closed]

[Solved] If in Array on PHP [closed]

I’m guessing you’re trying to find out if $catId is in the $result_2 array. If so, then you’ve already answered your question with your title here.. in_array if(in_array($catId,$result_2)) solved If in Array on PHP [closed]

[Solved] No Visible @interface for ‘MLVPieChartView’ declares the selector ‘tick’ [closed]

I’m looking at your MLVPieChartView.h file and I don’t see a method named “tick” in there. You need to change that call to the object that has a “tick” method. From what I can tell from your GitHub project, there is no “tick” method declared anywhere (in which case you have to create it). 4 … Read more

[Solved] No Visible @interface for ‘MLVPieChartView’ declares the selector ‘tick’ [closed]

Introduction The error “No Visible @interface for ‘MLVPieChartView’ declares the selector ‘tick’” is a common issue encountered when developing applications using the MLVPieChartView library. This error occurs when the code attempts to call a method (in this case, the ‘tick’ method) that is not declared in the MLVPieChartView interface. In this article, we will discuss … Read more

[Solved] C# get position of a character from string

string aS = “ABCDEFGHI”; char ch=”C”; int idx = aS.IndexOf(ch); MessageBox.Show(string.Format(“{0} is in position {1} and between {2} and {3}”, ch.ToString(), idx + 1, aS[idx – 1], aS[idx + 1])); This wont handle if your character is at position zero and some other conditions, you’ll have to figure them out. 2 solved C# get position … Read more

[Solved] How does #define carries the function name in c?

C preprocessor macros simply do text replacement. They have no semantic awareness of your program. This: #include <stdio.h> #define x printf(“%s”, f); int main() { char* f = “MAIN”; printf (“Hello World”); x; return 0; } Becomes: #include <stdio.h> int main() { char* f = “MAIN”; printf (“Hello World”); printf(“%s”, f);; return 0; } Please … Read more

[Solved] How can I convert my for loop into a recursive algorithm?

You do it by actually using the i parameter. private static final String ALPHABET = “abcdefghijklmnopqrstuvwxyz”; public static void binary(int n, String str, int i) { if (i == ALPHABET.length()) return; if (n == 0) { System.out.println(str); return; } binary(n – 1, str + ALPHABET.charAt(i), 0); // next letter starts at beginning of alphabet binary(n, … Read more