jQuery can be useful as any other javascript frameworks, how ever the major point of jQuery is huge amount of contributors and plugins made based on it. If you are looking for already build plugins have a look here ajaxrain.com there is about 500 of them. solved Looking for Inspiration: How can jQuery be truly … Read more
Try this code : int main() { if(printf(“%c”,59)) //59 is ascii value of semicolon {} } 0 solved How to print a semicolon (;) without using a semicolon in the program? [closed]
When averaging speeds, the harmonic mean is in need. The straight forward AVG() approach is wrong, the arithmetic mean yields the wrong result for average velocity. There is no predefined function for the harmonic mean, but it could be achieved with this query: SELECT segment, COUNT(*)/SUM(1e0/speed) AS avg_speed FROM T GROUP BY segment SQL Fiddle … Read more
You’re comparing a string and a number. You’re concatenating the result of indexOf (which I assume is -1) to a string before you do your > comparison. This is equivalent to NaN > -1. “1b-1” > -1 // => false 0 solved JavaScript indexOf greater than -1 false when it’s clearly not?
There are many options, I describe some of them for you use Dictionary<int, string>Pros: very fast lookupCons: you can not have two string with same number, you don’t have a List var list2d = new Dictionary<int, string>(); list2d[1] = “hello”; list2d[2] = “world!”; foreach (var item in list2d) { Console.WriteLine(string.Format(“{0}: {1}”, item.Key, item.Value); } use … Read more
This is normally solved with just a String#replaceAll, but since you have a custom, dynamic replacement string, you can to use a Matcher to efficiently and concisely do the string replacement. public static String parse(String command, String… args) { StringBuffer sb = new StringBuffer(); Matcher m = Pattern.compile(“\\$(\\d+)”).matcher(command); while (m.find()) { int num = Integer.parseInt(m.group(1)); … Read more
I found easy solution. You could just write it instead of complain that there is no code in the question. string expression;//my calculator expression string[] operators;//array that contains both unary and binary operators. for(int i=0;i<operators.length;i++) { expression = expression.replace(operators[i],” “+operators[i]+ ” “); } string[] Values= expression.split(” “); solved Split calculator expression with binary and unary … Read more
use JSON_ENCODE first before saving the array to DB ,then use JSON_DECODE if you want to get again the contents $arr = array( “item_number1” => “1”, “payment_date” => “04:21:34 Dec 06, 2014 PST”, “payment_status” => “Completed”, “first_name” => “sdfsd”, “last_name” => “parsdfsdandekar”, “quantity1” => “1” ); echo json_encode($arr); Result after JSON_ENCODE (Array to JSON String): … Read more
you can try this $config[‘enable_query_strings’] = TRUE; solved How to use query string in Codeigniter?
I tried to understand your question but it is hard to visualize exactly what you want. So I’ll just clean and update your code (i.e. bring it into the 21st Century). Please don’t use the <font> tag or the align attribute anymore. It’s 2016. If this is a heading, use <h1>, not <p>. Tags work … Read more
This is quite easy to o actually. Requirement #1 and #3 are the easiest. To test for whether a string contains two words and are separated by exactly one space, just use the split method. For requirement #2, test if the strings have a length that is larger than 2. Let’s say your string to … Read more
Then create a hashmap and whenever updation takes place save the data in hashmap. Inherit getItem(int index) method in adapter with HashMap as return type & and return the data in that method for corresponding index. HashMap<String, Object> hashMap = new HashMap<String, Object>(); @Override public HashMap getItem(int i) { return hashMap.get(i); } Like if user … Read more
Though, the question is not very clear, but here is my attempt to give you initials, as per my understanding. var sentence = $(‘div#content’).text(); var words = sentence.split(‘ ‘); var spanWords = []; $(words).each(function(i,word){ if($.trim(word).length) { var span = $(‘<span>’); span.text(word); spanWords.push(span) spanWords.push(‘ ’) } }); $(‘div#content’).html(spanWords) var start = function(element){ if(element.next().length){ setTimeout(function(){ element.css({color: “#000”}); start(element.next()) … Read more
Use below method public static void openFragment(FragmentManager manager, Fragment targetFragment) { try { String fragmentName = targetFragment.getClass().getName(); manager.popBackStack(); manager.beginTransaction() .replace(R.id.frameLayout, targetFragment, fragmentName) .addToBackStack(fragmentName) .commit(); } catch (Exception e) { e.printStackTrace(); } } call this method each time when you are opening your fragment. You have to pass two params to this method. targetFragment is the … Read more
As you now accepted to use RegEx, I adapted the solution based on this post https://stackoverflow.com/a/16707675/4339170: function validate() { var p = document.getElementById(‘pass’).value var errors = [] //if (p.length < 8) { // errors.push(“Your password must be at least 8 characters”) //} if (p.search(/[a-z]/) < 0) { errors.push(“Your password must contain at least one lowercase … Read more