try this IdAccess = from x in OffAcs where x.AccessDeccription == Combobox.SelectedText select x.IdAccess; or this: IdAccess = OffAcs.First(x=>x.AccessDeccription == Combobox.SelectedText).IdAccess; 3 solved how to point to a number that correspond value of this number is selected by user?
There are a few primary reasons to use a custom icon font over SVGs: An icon font lets you resize the icons simply by setting the font-size. An SVG is set with the width/height. An icon font is easier to colorize with the color property. It is possible to color an SVG with CSS as … Read more
var drops = []; var raindropSize = 1; var droplets = 3000; var maxDrops = 3000; var thue; var flig = 0; var thickness = 9; var tx; var ty = 10; var loc = 0; var direct = -1; var trail = 0.1; var fade = 1; var ms; var distancy; var mob = … Read more
It is because [12, 2] is a list, and next notation: [0] or [1] is indexing. You can test it if you try to print: print([12, 2][2]) you should get index out of range error. EDIT: to answer your second question: It is hard to say. target_f = self.model.predict(state) – it is some kind of … Read more
This really shouldn’t be done in jQuery, and you could still use a few lessons in being clear with what you’re looking for, but a question is a question, and here is my answer: $(‘th’).hide(); var $titlerow = $(‘tr td:first’), $yearrow = $(‘tr:eq(1) td:first’), title = $titlerow.text(), year = $yearrow.text(); $titlerow.text(title + ‘ – ‘ … Read more
Try the following code var userComment = [“Time these make me.jenny is “,”I can’t she did it.”, “Hey! what a great play made by brad”, “I can’t she .”, “Time like make is a badass”, “I can’t it.”, “She is a mean chose to place”,”Time me a badass”, “Wow! I am just like jenny.I would … Read more
month_name‘ “helpfully” pads the list with an empty string so that the list indices match up with the normal 1-based counting of the months. To work around this, I would slice the list and enumerate it with an explicit starting point of 1. for i, m in enumerate(calendar.month_name[1:], 1): Another, more cumbersome but possibly useful, … Read more
As per the Swift Programming Language you do not need to define the Data Type before the variable name as per other OOP languages like Java. The following is how you create a variable in Swift. var name = “Name” The var keywords takes your data which is “Name” and automatically assign a data type … Read more
Taking the initial code in the link, and adding parentheses helps to break down the If and Else structure: @Echo Off For %%Z In (“%ATTR%”) Do ( If “%%~aZ” GEq “d” ( Echo Directory ) Else ( If “%%~aZ” GEq “-” ( Echo File ) Else ( Echo Inaccessible ) ) ) Pause So to … Read more
The main problem here is that you are calling functions as they were variables Here is your code with the functions being called correctly: import math print(‘input your height and weight to find BMI.’) num_a = int(input(“feet==”)) num_b = int(input(“inches==”)) num_c = int(input(“weight(lbs)==”)) def weight(): return int(num_c) * 2.2 def height(): return (int(num_a)) * 12 … Read more
As @BigBen said in the comments, it is down to your use of If…Else…If twice. The first correction is: If Result = True And Worksheets(“Sheet3”).Range(“C4”, Range(“C4”).End(xlDown)) <> “” Then Worksheets(“Sheet1”).Range(“C4”, Range(“C4”).End(xlDown)).Value = Worksheets(“Sheet1”).Range(“C4”, Range(“C4”).End(xlDown)). _ Value + Worksheets(“Sheet3”).Range(“C4”, Range(“C4”).End(xlDown)).Value ElseIf Result = True And Worksheets(“Sheet3”).Range(“D4”, Range(“D4”).End(xlDown)) <> “” Then Worksheets(“Sheet1”).Range(“D4”, Range(“D4”).End(xlDown)).Value = Worksheets(“Sheet1”).Range(“D4”, Range(“D4”).End(xlDown)). _ … Read more
Thanks for all responses The Lambda expression query is correct only. db.Companies.where(Company => (Compare(Convert(Company.Name), “Test”) > 0)) db.Companies.where(Company => (Compare(Convert(Company.Name), “Test”) >= 0)) I changed the “right arg” value to “Test”. I have one record ‘Name’ with Test. executed the following query. db.Companies.where(Company => (Compare(Convert(Company.Name), “Test”) > 0)) and shown the results 105(here Name with … Read more
I believe you want a dictionary with a single key and a list: l = [1,2,3,4,5] d = {l[0]:l[1:]} Output: {1: [2, 3, 4, 5]} 0 solved Turning a list into a dictionary?
It’s null coalesce operator. It will return $_GET[‘page’] unless it’s null. In case it’s null it would return default value ‘home’. It has same meaning as: !is_null($_GET[‘page’]) ? $_GET[‘page’] : ‘home’ 1 solved PHP syntax ?? meaning,can somebody explain? [duplicate]
If you are trying to parse single or double quoted strings, it should be done in two steps. Validation, then parse for values. You could probably do both in a single regex with the use of a \G anchor, validating with \A\G and parsing with just the \G. If you are sure its valid, you … Read more