Swap the arguments to the phonebook constructor public static void main(String[] args) { Scanner input = new Scanner(System.in); String area, inStr; //there is no need of inStr as you are not using it so remove it if not used int pages; System.out.println(“Please enter your city”); area = input.nextLine(); System.out.println(“Please enter page number ” + area … Read more
You should be checking if a session variable exists to grant access to users. To log out from your site, simply destroy the session, this will prevent access effectively ‘logging’ the user out: session_start() session_destroy(); //destroy sessions but session data will still be avail on same page so redirect is needed after this header(‘location:index.php’); // … Read more
I think you are confusing lists with dicts. The keys of your items dict are ‘coke’, ‘mars’, ‘fanta’, etc. and that is how you access it like items[‘coke’]. To iterate the items, something like this is more usual: >>> def list_items(): … for k,v in items.items(): … print(“{}: {}”.format(k, v)) … >>> list_items() coke: 1.50 … Read more
Explanation about the error: WebClient.DownloadFileAsync public void DownloadFileAsync( Uri address, string fileName ) It doesn’t return anything (void) and you are passing this to listsext! Ofcourse you will get an Exception: Cannot implicitly convert type ‘void’ to ‘string’ What you want to achieve: (my guess, not much information given) You want to have the filename, … Read more
For security reason an app cannot control another one. You cannot do it. 2 solved Close another iOS app through a button [closed]
Because push returns the size of the array: The push() method adds new items to the end of an array, and returns the new length. It does execute the push function, it’s just not returning what you were expecting. JavaScript was written in only 10 days so we are stuck with some design decisions. It’s … Read more
You can use the :t command in ghci to find out the type of any expression. GHCi, version 7.10.3: http://www.haskell.org/ghc/ 😕 for help Prelude> :t flip foldr id flip foldr id :: Foldable t => (a -> (a1 -> a1) -> a1 -> a1) -> t a -> a1 -> a1 solved Get the type … Read more
function doSomething(a) { b = a + doSomethingElse(a * 2); console.log(b * 3); } function doSomethingElse(a) { return a – 1; } var b; doSomething(2); //15 When you call doSomething(2); you pass value 2 to your function doSomething(a) so value of a inside this function is a = 2. Now you have b = a … Read more
you cannot save all the file extension into one single file. Css is .css, Javascript is .js. but you can link all those files into your html <link rel=”stylesheet” type=”text/css” href=”https://stackoverflow.com/questions/47306539/yourcssfile.css”> for javascript <script src=”https://stackoverflow.com/questions/47306539/yourjsfile.js”></script> solved How to put HTML, CSS and JS in one single file
As suggested in comments, you could use itertools.groupby to subdivide the tuple into “not a separator” and “separator” groups and then pick those groups that are not separators. This works for arbitrary numbers of segments, but can also be unpacked into two variables if you know to have exactly two groups. >>> a = (‘a’, … Read more
Presumably you have something along the lines of: if (condition) { Awesome } The Form Change it to if (condition) { Awesome } else { The Form } 7 solved How to – Go Dynamic with PHP [closed]
try this: PHP Base32 Decoder: http://php-classes.de/class/base32/ this would generate only lowercase letter. 1 solved I have a string which I want to encrypt/decrypt using php but the output of the encryption should be lower case alphanumeric only [closed]
$(function() { $(‘#loginBtn, #loginArea’).on(‘click’, function(e) { $(‘#loginArea’).show(); e.stopPropagation(); }); $(‘body’).on(‘click’, function() { $(‘#loginArea’).hide(); }); }); If the click is within the login area or on the button, then the event will not make it to the second handler to hide the login area. solved Click outside of div and more [duplicate]
Your back button closes the activity because that’s the normal behaviour. What you need to do if you want to use the back button to act as a Go back button for your WebView is: @Override public boolean onKeyDown(int keyCode, KeyEvent event) { if (keyCode == KeyEvent.KEYCODE_BACK) { yourWebView.goBack(); return true; } return super.onKeyDown(keyCode, event); … Read more
No need to change any tags. This is what Media queries are for. 9 solved how to make a current website responsive? [closed]