I understand this is more a conceptual question. Two simplest methods that come into mind are: 1) Use a “flag file” that you create from the shell script. When the file exists, it means the script is done. When there’s no file, the script still runs. Or other way around. That’s common method for shell … Read more
You will have to hook your application to somehow track all outgoing requests over port 80 and 443 1 solved How to get URL hit by browser in C# application [closed]
This will not visit all indexes of the array because array indexes begin at 0, not 1. In other words, the first element of the 2D array would be adjacencyMatrix[0][0] so you should start both of your iterations from 0. If the array has a length of 5, the largest index would therefore be four … Read more
You simply need to realize that a ‘relative’ sets the base of two property sets, 1: zIndex and 2: positions. Make ‘front’ a high zindex and position it relatively. Wrapping the elements with the relative block-div, makes the width of children calculate via the width of said block-div – and also positions them with the … Read more
here’s how I would implement it: window.onload=function(){ var array1 = [1, 2, 3, 4, 5, 6] var array2 = [3, 4, 5, 6, 7, 8] var result = [] var resultCount=0; for (var i1 = 0; i1 < array1.length; i1++) { var comparedElement = array1[i1]; var isUnique = true; for (var i2 = 0; i2 … Read more
It seems that when you don’t select a color from the colorpicker, that the colorpicker.SelectedColor is null, and causing your error. You can check for this in your code, like so: private void btnreturn_Click(object sender, RoutedEventArgs e) { int gettext; int.TryParse(txtcount.Text, out gettext); Color Colorpicker; // Check if the SelectedColor is not null, and do … Read more
The first <ifModule> is not closed, this: RewriteRule ^(.*)$ index.php?/$1 [L] <IfModule> has to be RewriteRule ^(.*)$ index.php?/$1 [L] </IfModule> #^ solved 500 error thrown due to .htaccess bug [duplicate]
You can use the following to match: .*?\s*\|\s*(.*?)\s*\|.* And replace with $1 See DEMO 0 solved how to clean detail mass on regex
The velocityThreashold variable in your example is not final, nor is it an instance variable and therefore cannot technically be overridden. What you can do is set the value of velocityThreashold to any value you want since it’s public. I think what you’re going to want to do is something like the following: public static … Read more
The problem has nothing to do with gmail integration. The problem is with eclipse “Unable to execute dex: Java heap space” and “Conversion to Dalvik format failed: Unable to execute dex: Java heap space” This comes when the eclipse has memory related issues. Try restarting eclipse and/or your system. It should work. Also you might … Read more
I didnt test it, but from a quick look it seems you named the property incorrectly. It should be ‘templateUrl’, NOT ‘templateURL’ (only the ‘U’ is uppercase). 1 solved Angular directive templateURL not being loaded. Why? [closed]
First of all you have to “Setting up an Access Database for Your Hosting Account” for online availability of “Access Database” as a centralized. If your hosting is with godaddy then visit this Link Here is a sample code of access online “Access Database” string connectionString = @”Provider=Microsoft.Jet.OLEDB.4.0;” + @”Data Source=”Path of you hosting provider … Read more
I’ll help you with closures as I expect they are the most hard part of the code. Rest of the stuff is pretty similar to Java and other OOP languages. You can check closure syntax here. Correct me if my syntax is wrong: picker.finalizationBlock = {(picker, info) in //Your code here… } picker.failureBlock = {(picker, … Read more
One of the most common misconceptions of beginner programmers about Javascript and AJAX is to treat the AJAX request as a “normal” function, doing variable assignments or expecting to use immediately the AJAX response in their code. That’s not how it works though; let’s try to understand how a correct implementation works. AJAX stands for … Read more
Yes, you are correct. By calling new you are creating a reference to an object, you are doing a similar operation when you declare a new String. 5 solved What is the error in each Java Statement?