[Solved] Need to understand printf functioning deeply
[ad_1] Would make sense if you knew a li’l bit about awk. Anyways what happens here is that the * is replaced by the numbers you’ve given (-5 and 4 respectively), which means printf(“%*.*s”,-5, 4, s+3); would change to printf(“%-5.4s”, s+3); 0 [ad_2] solved Need to understand printf functioning deeply