Month: December 2022

[Solved] Next permutation algorithm c# and linq [closed]

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You could try following code, it uses private field to stroe all permutations generated by methods finding permutations: private static List<string> _permutations = new List<string>(); public static Main(string[] args) { string testString = “abc”; TestMethod(testString); // You need to handle case when you have last permuation in a list string nextPermutation = _permutations[_permutations.IndexOf(testString) + 1]; … Read more

[Solved] Can someone help me for convert this c# recursive function to java [closed]

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public final boolean ParantezKontrol(String input) { return ParantezKontrol(input, 0); } //Java does not support optional parameters. So you can overload this method //ORIGINAL public bool ParantezKontrol(string input, int numOpen = 0) public final boolean ParantezKontrol(String input, int numOpen) { if (numOpen < 0) { return false; } if (isNullOrEmpty(input)) { return numOpen == 0; } … Read more

[Solved] Take one sample per row at a time, compute mean, loop [closed]

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First lets make so data to experiment with set.seed(100) example <- matrix(runif(47*30), nrow = 47) example[sample(length(example), 250)] <- NA Now we can calculate our means. The apply function samples a random value from each row (!is.na excludes NA values), mean gets the mean, and replicate repeats this 10000 times. exmeans <- replicate(10000, mean(apply(example, 1, function(x) … Read more

[Solved] JavaScript taking information from a email address

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First get the email address to parse. You’ve already done that. Here, x contains the email address. var x = document.getElementById(“myText”).value; Now you can use x.indexOf(“.”) to get the position of the first period. Likewise, use x.indexOf(“@”) to get the position of the “@” symbol. These two values are passed to x.substring() to get the … Read more

[Solved] C++ : Mini Project on Cryptography

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There is a quite simple answer to how to encrypt files. This script uses the XOR encryption to encrypt files. Encrypt the file a second time to decrypt it. #include <iostream> #include <fstream> #include <string> using namespace std; void encrypt (string &key,string &data){ float percent; for (int i = 0;i < data.size();i++){ percent = (100*i)/key.size(); … Read more

[Solved] Get String between two strings with length 10 when you have more occurance of inbetween [closed]

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Try using regular expressions: String source = “Invoice No:< 12345sd ) <1234567890>”; // {10} 10 characters exactly // {10,} 10 characters or more // {,10} 10 characters or few // {5,10} from 5 up to 10 characters var matches = Regex .Matches(source, @”<([^<]{10})>”) .OfType<Match>() .Select(match => match.Groups[1].Value) .ToArray(); // Or FirstOrDefault(); if you want just … Read more