The two classes are certainly related i.e. they have an Association. But, the nature of their relationship could either be an Aggregation or Composition. To give you an example and thereby explain how it’s different than Inheritance; consider the following classes: Shape (Base class; can be abstract) Circle, Triangle, Square etc. (Derived classes) Line, Colour … Read more
– (int) GetCount :(NSString *)UserID { [self createEditableCopyOfDatabaseIfNeeded]; [self initializeDatabase]; int count = 0; NSArray *paths = NSSearchPathForDirectoriesInDomains(NSDocumentDirectory, NSUserDomainMask, YES); NSString *documentsDirectory = [paths objectAtIndex:0]; NSString *path = [documentsDirectory stringByAppendingPathComponent:@”dbfav2table.sqlite”]; if (sqlite3_open([path UTF8String], &database) == SQLITE_OK) { sqlite3_stmt *statement; NSString *sql_str = [NSString stringWithFormat:@”SELECT count(*) FROM tablename WHERE userID=’%@'”, UserID]; const char *sqlStatement = (char … Read more
This is example in the purest, basic, sugar-less form public string GetDelimited(int numberOfLoops, string delimiter) { var builder = new StringBuilder(); for (int i= 1; i < numberOfLoops + 1; i++) { if (i > 1) builder.Append(delimiter); builder.Append(i.ToString()); } return builder.ToString(); } 0 solved How do I build a function in C# that returns a … Read more
You want to use a form item rather than a list if you want them selectable; like so: <div class=”box” style=”display: inline-block;margin-left: -330px;”> <select multiple=”multiple”> <option value=”0″>mumbai</option> <option value=”1″>bangalore</option> <option value=”2″>hyderabad</option> <option value=”3″>chennai</option> </select> HTH; 2 solved How to make a List items to select
You were close to getting there. This is easiest if you use the System.Linq namespace: string[] txt = i.Split(new char[] { ‘.’, ‘?’, ‘!’, ‘,’ }); //this part you had correct var stringsOrderedByLargest = txt.OrderByDescending(s => s.length); stringsorderedByLargest will now contain be sorted from longest to shortest. If you want to count how many words … Read more
Ok, as now we have seen your attempt, I would suggest you to grasp some concepts of Python and get an understanding of Python’s libraries and builtins, esp, in this case, you need to understand zip and all. You also need to understand about iterable and List Comprehension. Zip is a wonderful function, and comes … Read more
Index out of bounds exception means that you are trying to access a index that doesn’t exists. Say that you have an array with 9 elements. array[9] will be the 10th and it wont exists. 2 solved Array Index out of Bounds, not sure what’s going on (JAVA)
In C++, you split files by reading the master and writing to one or more new files. This technique works with the C language also. Joining files depends if you want to merge or append. In the append case, the destination file is opened with the “append” and write attribute. The file pointer is set … Read more
You can use sortBy function of lodash. var users = [ { ‘user’: ‘fred’, ‘age’: 48 }, { ‘user’: ‘barney’, ‘age’: 36 }, { ‘user’: ‘fred’, ‘age’: 40 }, { ‘user’: ‘barney’, ‘age’: 34 } ]; _.sortBy(users, [function(o) { return o.user; }]); // => objects for [[‘barney’, 36], [‘barney’, 34], [‘fred’, 48], [‘fred’, 40]] solved … Read more
If you’re using python, os.walk can help you. Simple code like this can work: import os for data in os.walk(‘d:\\music’): # where to start searching dir_path, folders, files = data for f in files: if f.lower().endswith(‘.mp3’): print(os.path.join(dir_path, f)) 0 solved How Can I Find For Example *.mp3 Files From All Directories Of My System? [closed]
Use min(list) to get the minimum value across a list use max(list) to get maximum value across a list data = [ [30, 30, 20], [10, 5, 10], [20, 20, 30], [8, 20, 10] ] new_list = [] for i in range(4): if i < 2: new_list.append(min(data[i])) else: new_list.append(max(data[i])) print(new_list) # Output # [20, 5, … Read more
if it’s only words you can split the strings to string[] that each cell will contain 1 word only and then compare those words. Goes as follows: String one = “this is first text example”; String two = “this is next text example”; String[] oneVals = one.split(“\\ “); String[] twoVals = two.split(“\\ “); int i … Read more
Use groupby df.groupby(“ID”)[“Cluster”].sum().reset_index() 1 solved How to sum some columns in a row [duplicate]
Just a simple and quick answer, maybe there is easier way. fullName = input(“Hello there, what is your name?”) fName, sName = fullName.split() print(“So, your first name is”, fName) print(“and your second name is”, sName) answer = input(“Is this correct?”) while not (answer == “Yes” or answer == “yes”): fullName = input(“Hello there, what is … Read more
Try looking at * not as being in front of function name, but rather as being behind TreeNode. In other words, that * changes function return type from structure to pointer to a structure. & in front of variables means that they are, essentially, still pointers, but they can’t be NULL (there are ways to … Read more