[ad_1] The default recursion limit is 1000. >>> sys.getrecursionlimit() 1000 A program with a single recursive function will reach 999: start = 0 try: def recursion(): global start start += 1 recursion() recursion() except RecursionError: print(‘recursion :’, start, ‘times’) prints out recursion : 999 times Your program is creating a stack that has recursion(), then … Read more
[ad_1] I hope this answer is what you are looking for: You can make an array with your answers, and then check to see if the given answer is inside the array. const array = [‘test’, ‘test2’, ‘test3’]; if (array.includes(an.value.toLowerCase() ) ) … Something else, you are missing a semicolon in your else { … … Read more
[ad_1] Your pattern requires one character of each type, in order. If you want to match all the characters, put them in a single character class, and quantify it with * pattern=”[a-ZA-Z0-9._]*” [ad_2] solved Check if input field can only consist of lower and uppercase letters, numbers and the characters . and _
[ad_1] This is an interesting problem, In javascript we dont have any straight approach with which we can detect the type or attribute change in javascript. I had same kind of problem and then after some studies, I found that this could be done with Mutation observer. In this code I have created an extension … Read more
[ad_1] One simple solution would be to use a List instead of an array. List<string> temp = new List<string>(); It will need some tweaks but it will not limit you to 100 actions. In any other case, you should decide the strategy. Do you want to delete the initial items? Then remove your first X … Read more
[ad_1] No doubt your code works even without the interface at this moment, but. Implementing an interface allows a class to become more formal about the behavior it promises to provide. Interfaces form a contract between the class and the outside world, and this contract is enforced at build time by the compiler. If your … Read more
[ad_1] So there are two things: The assignment of s should be either with escaped back-slashes or as a raw string. I prefer the latter: s = r”C:\x\xxx\temp\downloads\test_dir\sql\my-ee.sql” you should use the search method instead of match to be content with a partial match. Then, you can use \\\\ in the regular expression, or – … Read more
[ad_1] First sort the data and then distribute values into a new array, in zigzag order: function spread(data) { let n = data.length; // First sort let sorted = […data].sort((a, b) => a – b); // Then spread let result = Array(n); for (let i = 0, j = 0; j < n; i++, j … Read more
[ad_1] Using substr: declare l_start number := DBMS_UTILITY.get_cpu_time; begin for i in ( with t as ( select ‘Chapter ‘ || level || ‘ Unit ‘ || level || ‘ Sect ‘ || level d from dual connect by rownum < 100000 ) select substr(d, 1, instr(d, ‘ ‘, 1, 2) – 1) chapter , … Read more
[ad_1] You’re returning early in the loop, you need to build up a string and return that. Either just return a joint string or build it up “”.join(chr(ord(s)+4) for s in pas) def cip(pas): ret_val = “” for i in pas: asci = ord(i) encryption = asci + 4 ret_val += chr(encryption) return ret_val [ad_2] … Read more
[ad_1] To learn more about text processing in Python3 I recommend training on codingame.com. def removeDuplicates(inp): output =”” lastCharacter=”” for character in inp: output+=character*(character!=lastCharacter) lastCharacter=character return output inpTest =”AAABBCCDDAA” print(removeDuplicates(inpTest)) ABCDA 0 [ad_2] solved HOW TO REMOVE DUPLICATES IN A ROW IN PYTHON [closed]
[ad_1] crke[b] = ugib[b]; This line should be: crke[b] = ugib[z]; You might want to consider investing some time in learning how to use a debugger, which would’ve helped you figure it out. [ad_2] solved C++ Word guessing game [closed]
[ad_1] Here’s how I would do it without the use of the deep extend module. First rearrange JSON1 so that the name property of each object becomes an object key: var obj1 = Object.keys(obj).reduce(function (p, c) { var o = obj[c], name = o.name; p[o.name] = JSON.parse(JSON.stringify(o)); return p; }, {}); OUTPUT { Car: {…} … Read more
[ad_1] You’ve already answered your question…. “no updates installed” means that you don’t have update 1 installed. Select that you want to keep your registry entries during uninstall, then you don’t need to reinstall your components. 5 [ad_2] solved delphi 10 seattle update installed? [closed]
[ad_1] Here’s a query that will include the row for today and the rows for the last three days: SELECT * FROM ALLRESULTDATA WHERE `date` = CURDATE() OR `date` >= DATE_ADD(CURDATE(), INTERVAL -3 DAY) ORDER BY `date` DESC LIMIT 4 SQL Fiddle: http://sqlfiddle.com/#!9/88561/3 I think you also mean to only include the result for today … Read more