OP has done a significant edit a 2nd time – better to start a new question. @J.Selva, do not change the question again. In this version, the below code does not check the return value of fgets() (which is an exploit opening) and yet uses password. This creates a problem that may be used to … Read more
Project -> Clean seems to be the only solution to me. Trying cleaning your project a few times and then build it. 0 solved Why does my app crash in the emulator?
The regular expression is: ^((?!(?<ch>.)\k<ch>\k<ch>)(?!012|123|234|345|456|567|678|789|890)[0-9]){8,}$ The (?!(?<ch>.)\k<ch>\k<ch>) will check for the same character repeated thrice. Note that for the various contiguous sequences I had to put them in a list of possible sequences, (?!012|123|234|345|456|567|678|789|890). [0-9] is the character that will be accepted as valid. The {8,} is for the minimum length. 1 solved Numbers only … Read more
This looks like a homework question so I won’t solve it directly. However here are some steps you could take: Create a method to validate the input (public static boolean isValid(String str)) Convert the String to a character Array. (There’s a method for that!) Iterate over the letters and keep track of how many upper … Read more
First of all, you only have to use “WHERE username =”. You don’t have to check the password when you do the request. Secondly, you have to verify the password. Finally, you should also used prepared statements, it’s more secure. So, your code should look like this (the code provided may not be usable as … Read more
This is an interesting problem, In javascript we dont have any straight approach with which we can detect the type or attribute change in javascript. I had same kind of problem and then after some studies, I found that this could be done with Mutation observer. In this code I have created an extension method … Read more
In future, I’d suggest you refrain from begging for answers without first showing some code you’ve tried. That being said, I’ll bite. import java.security.MessageDigest; import java.security.NoSuchAlgorithmException; import java.security.NoSuchProviderException; import java.security.SecureRandom; public class EncryptHelper { public static String ehashAndSalt(String passedpass) throws NoSuchAlgorithmException, NoSuchProviderException { String passwordToHash = “password”; String salt = getSalt(); String securePassword = getSecurePassword(passwordToHash, … Read more
^(?=.*[A-Z]{1,})(?=.*[a-z]{1,})(?=.*[0-9]{1,})(?=.*[!@#\$%\^&\*()_\+\-={}\[\]\\:;”‘<>,./]{1,}).{4,}$ should do it. Explaination: ^ start (?=.*[A-Z]{1,}) at least one upper (?=.*[a-z]{1,}) at least one lower (?=.*[0-9]{1,}) at least one digit (?=.*[!@#\$%\^&\*()_\+\-={}\[\]\\:;”‘<>,./]{1,}) at least one of the mentioned chars .{4,} min length 4 $ end solved Password RegExpression [closed]
As i said in my comment its never a good idea to role your own security functions as security is a complex space and should be left to professionals. however you said this is just for your own training / learning so below is an example of your code but modified to work. This is … Read more
Don’t put the / around the expression. Then you can convert it to a regular expression with new RegExp, and test the password with it. You can loop with .every(), which will perform tests as long as they’re successful. var pwdarray = { “pwd”: [{ “TEXT”: “Password must be at least 6 character(s) long.”, “EXPRESSION”: … Read more
password_verify matches your plain password against hashed version of your given password while you’re checking with plain password in both parameter. password_verify works like this: password_verify($plainPassword, $hashedPassword) <?php // See the password_hash() example to see where this came from. $hash=”$2y$07$BCryptRequires22Chrcte/VlQH0piJtjXl.0t1XkA8pw9dMXTpOq”; if (password_verify(‘rasmuslerdorf’, $hash)) { echo ‘Password is valid!’; } else { echo ‘Invalid password.’; } … Read more
//… generate(apple,i); //… you have to specify the arguments in the signature of your function ‘generate’ like: void generate( string apple, int it ) { And the error: size_t i; //… for(i=0; i <= pear.length(); i++) { //logic here?! } you add an element to a string using: string.push_back( ‘a’ ); solved C++ Error: ‘no … Read more
more simple way use TextInputLayout compile design library to your dependecies compile “com.android.support:design:26.0.+” TextInputLayout Layout which wraps an EditText (or descendant) to show a floating label when the hint is hidden due to the user inputting text. <android.support.design.widget.TextInputLayout xmlns:app=”http://schemas.android.com/apk/res-auto” android:layout_width=”match_parent” android:layout_height=”wrap_content” app:passwordToggleEnabled=”true”> <android.support.design.widget.TextInputEditText android:layout_width=”match_parent” android:layout_height=”wrap_content” android:hint=”Enter EMail Address” android:inputType=”textPassword”/> </android.support.design.widget.TextInputLayout> 0 solved I am using … Read more