[ad_1] *x = 1; means that x contains a memory address, assign 1 to that memory address. x = 1; means assign 1 to the variable x. [ad_2] solved What is the difference between “*x = 1” and “x = 1” in C?
[ad_1] All depend on the situation in hand. Both are valid but for multiple scenarios this one is quicker and much more efficient $a = $b == “” ? “default” : $b; [ad_2] solved Which is the most efficient way to work around the first one or the next one?
[ad_1] You can use datetime to perform the necessary calculations. In this example, the target time is parsed using strptime but the date is not supplied so the time part is correct but the date part is wrong. The first three fields (year, month, day) are then replaced with today’s date to produce a datetime … Read more
[ad_1] You need to create a function and then return the output of the addition. A function which takes two arguments. def addition(number1, number2): return number1 + number2 number1 and number2 are the 2 arguments. Since you already have 2 numbers in your list you can pass them like this. print(addition(*randomlist)) The * unpacks the … Read more
[ad_1] Here is an example that does this. Make sure you run it with the sheet you want to use up: Sub DeleteDupes() Dim x For x = Cells(Rows.CountLarge, “D”).End(xlUp).Row To 1 Step -1 If Cells(x, “D”) = Cells(x, “E”) Then ‘This line deletes the row: Cells(x, “D”).EntireRow.Delete xlShiftUp ‘This line highlights the row to … Read more
[ad_1] You can not use target, predicted = pipe.fit_predict(df) with your defined pipeline, because the fit_predict() method can only be used, if the estimator has such a method implemented as well. Reference in documentation Valid only if the final estimator implements fit_predict. Also, it would only return the predictions, so you can not use target,predicted … Read more
[ad_1] Python uses short-circuiting in logical conditions – in simple words if it determines that there is enough info so that the whole condition is True or False it won’t continue executing the rest of the code in the condition statement – so in your case not all code you intended got executed. A simple … Read more
[ad_1] One way to do this might be to do a simple split() on the T character, and only taking the first segment: var dateAndTime = “2020-05-18T10:11:08Z”; var date = dateAndTime.split(‘T’)[0]; console.log(date); In a similar text manipulation vein, it’d also be possible to do something similar using RegExp, which might be helpful if you’d like … Read more
[ad_1] You could use Python f-strings. print(f'{int(seconds / 60):02} mins {int(seconds % 60):02} seconds’) [ad_2] solved How do I convert 62 seconds into string 01 mins 02 secs [duplicate]
[ad_1] It can reference itself. public class Person { public string Name { get; set; } public int Age { get; set; } public List<Person> Children { get; set; } } 3 [ad_2] solved property within a class with the same properties as the parent class [closed]
[ad_1] You need to do it this way, if i am correct to assume this is your purpose: petname = [‘Zophie’, ‘Pooka’, ‘Fat-tail’] print (‘What is your pets name?’) name = input() if name not in petname: print (‘Your pet is not in the list’) else: print (‘Your pet is in the list’) [ad_2] solved … Read more
[ad_1] echo implode(‘<br />’, array_slice(file(‘file/datum2.html’), 0, 6)); OR echo implode(‘\n’, array_slice(file(‘file/datum2.html’), 0, 6)); 7 [ad_2] solved Php – echo line 6 from Text file
[ad_1] When I include brackets in a nested for loop, it doesn’t function correctly but when I take them out it does; why is this? [closed] [ad_2] solved When I include brackets in a nested for loop, it doesn’t function correctly but when I take them out it does; why is this? [closed]
[ad_1] Try this layout. <RelativeLayout xmlns:android=”http://schemas.android.com/apk/res/android” xmlns:app=”http://schemas.android.com/apk/res-auto” android:layout_width=”fill_parent” android:layout_height=”fill_parent”> <ImageView android:id=”@+id/imageView” android:layout_width=”wrap_content” android:layout_height=”wrap_content” android:layout_alignParentEnd=”true” android:layout_alignParentStart=”true” android:layout_alignParentTop=”true” android:src=”https://stackoverflow.com/questions/38821397/@mipmap/ic_launcher” /> <LinearLayout android:layout_width=”match_parent” android:layout_height=”wrap_content” android:layout_centerHorizontal=”true” android:orientation=”horizontal” android:layout_above=”@+id/imageView2″ android:layout_below=”@+id/imageView”></LinearLayout> <ImageView android:id=”@+id/imageView2″ android:layout_width=”wrap_content” android:layout_height=”wrap_content” android:src=”https://stackoverflow.com/questions/38821397/@mipmap/ic_launcher” android:layout_alignParentEnd=”true” android:layout_alignParentStart=”true” android:layout_alignParentBottom=”true” /> </RelativeLayout> [ad_2] solved android ImageView allways top and bottom [closed]
[ad_1] A bit untidy, but does the job: d <- data.frame(a=a[-(1:2)], diff=diff(a, 2)) d$br <- 0 for (i in 1:nrow(d)) { if (i==1 & d$diff[1]==2) { d$br[1] <- 1 } else if (i==2 & d$diff[2]==2 & d$br[1]!=1) { d$br[2] <- 1 } if (d$diff[i]==2 & !any(sum(d$br[c(i-1, i-2)])>0)) d$br[i] <- 1 } t(sapply(d$a[d$br==1], function(x) (x-2):x)) # … Read more