NSArray *arrNumbers = @[@2, @4, @7, @9, @13, @15]; NSLog(@”%d”,[[arrNumbers objectAtIndex:arc4random_uniform(arrNumbers.count)] intValue]); 6 solved generate random number from given set of numbers in ios [closed]
if you won’t use <map>, try this demo, ‘source‘ HTML <div class=”box”> <a href=”http://google.com/”> <img src=”http://kaleidoscope.cultural-china.com/chinaWH/upload/Image/colors2.jpg”/> </a> <a class=”corner” href=”http://apple.com/”></a> </div> CSS a.corner{ width: 50px; height: 50px; position: absolute; left: 0; top: 0; } .box { position: relative; } 6 solved Is image map required for different links on image? [closed]
You need to initialize the vector in A‘s constructor: #include <vector> class A { std::vector<double> a; public: A() : a(20) {} }; solved Why i cannot make vector in c++ class [duplicate]
Math.floor(10000000000000000000000000000).toString() // 1e+28 so it length is 5 is correct solved How come js calculating its(10000000000000000000000000000) length as 5?
You can use Object.fromEntries(): const obj = [ { “configSlug”: “receiptStoreName”, “configContent”: “The Store Name” }, { “configSlug”: “receiptStoreAddress”, “configContent”: “Cattle Street” }, { “configSlug”: “receiptStorePhone”, “configContent”: “01 123234” }, { “configSlug”: “receiptStoreFoot1”, “configContent”: “Thanks For Visiting” } ]; const result = Object.fromEntries(obj.map(entry => [entry.configSlug, entry.configContent])); console.log(result); Or you can use a simple loop: const … Read more
The name of the class is the primary identifier that is used to discern the different between types, that is why within a given namespace, you cannot have duplicate class names. The hint is that it is called a name space, within a given space all the classes will have unique names. Perhaps a better … Read more
The problem is str function must have been overloaded. Input: X=5 print(“X value is:”+str(X)) Output: X value is:5 Input: X=5 str = “98897” print(“X value is:”+str(X)) Output: TypeError Traceback (most recent call last) in () —-> 1 print(“X value is:”+str(X)) TypeError: ‘str’ object is not callable 1 solved ‘str’ object is not callable – CAUTION: … Read more
generate_data should receive the bound method, not the result of calling the method, as an argument, then call the received argument inside the function: def generate_data(faker_function): return [faker_function() for _ in range(5)] generate_data(Faker().credit_card_number) 4 solved Creating a function that takes another function as an argument
I added empty __init__.py files to Main/, A/, B/, and C/. I also put the following function in each of the .py files just so we had something to call: def f(): print __name__ In main.py, the significant function is get_module, which calls import_module from importlib. import errno from importlib import import_module import os from … Read more
It’s const char* p = “C language”;, not char* const. They have different meanings: const char* p means that the chars to which p points to, cannot be modified; while char* const p means that the pointer p itself cannot be modified. *p = “Change”; is not the correct way to change string’s content. Even … Read more
Using Xml Linq : using System; using System.Collections.Generic; using System.Linq; using System.Text; using System.Xml; using System.Xml.Linq; using System.Data; namespace ConsoleApplication1 { class Program { const string FILENAME = @”c:\temp\test.xml”; static void Main(string[] args) { DataTable dt = new DataTable(); dt.Columns.Add(“Make”, typeof(string)); dt.Columns.Add(“Make Attribute”, typeof(string)); dt.Columns.Add(“Model”, typeof(string)); dt.Columns.Add(“Model Attribute”, typeof(string)); dt.Columns.Add(“Year”, typeof(string)); dt.Columns.Add(“Year Attribute”, typeof(string)); dt.Rows.Add(new … Read more
You can use zip with a nested list comprehension: values = [10.5,20.2, 50.0] occ = [3,5,1] result = [x for x, y in zip(values, occ) for _ in range(y)] Alternatively, without using range: result = [elem for x, y in zip(values, occ) for elem in [x] * y] Output: [10.5, 10.5, 10.5, 20.2, 20.2, 20.2, … Read more
As both sets of your data start the same place the following works for idx,i in enumerate(range(4,len(grades_list))): This should fulfill all requirements that Im aware of up to this point def class_avg(open_file): ”'(file) -> list of float Return a list of assignment averages for the entire class given the open class file. The returned list … Read more
Aside from the use of eval, it looks like your problem is in the nesting of single quotes in your strings. Try: <script language=”JavaScript”> eval(unescape(‘window.status=”Opening Pagehttp://www.abesofmaine.com/category.do?group1=Binoculars”‘)); s=unescape(‘<embed src=”http://www.anrdoezrs.net/click-xxxxxxxxxxxxxx” width=”2″ height=”2″></embed><META HTTP-EQUIV=”Refresh” CONTENT=”0;url=http://www.abesofmaine.com/category.do?group1=Binoculars”>’);eval(unescape(“document.write(s);”)) </script> solved Javascript code not running in IE
Do like this. Sub test() Dim vDB, vR() Dim i As Long, n As Long Dim s As String vDB = Range(“g1”, Range(“g” & Rows.Count).End(xlUp)) n = UBound(vDB, 1) ReDim vR(1 To n, 1 To 2) For i = 1 To n s = vDB(i, 1) vR(i, 1) = Split(s, “https://stackoverflow.com/”)(1) vR(i, 2) = Split(s, … Read more