[ad_1] The error is in the following code: $(“#submitbtn”).on(click, function() { console.log(“clicked”); return false }) it should be: $(“#submitbtn”).on(“click”, function() { console.log(“clicked”); return false }) (Note on the double strings before and after click) In order to debug your code first take atention to the error message, then click on the file that its throwing … Read more
[ad_1] It seems like you are trying to use an array and an int with the operand “**” althought it expects two ints or at least two numbers. Maybe you want to use sum_x or sum_xy as the first argument instead? [ad_2] solved how do you address type error in python [duplicate]
[ad_1] Technically, the arguments to functions are expressions. Expressions come in many different forms. They can be variables, like in value = fun_1(num1, num2); or they can be constants, like in value = fun_1(1, 12); or even involve operators with other expressions: value = fun_1(fun_1(42, 1) * 3, sizeof “foo”); Note that the expressions must … Read more
[ad_1] You need to set isPrime to 0 each time the user enters a number. Otherwise, it still holds the value from the previous number. Move the variable declaration int isPrime = 0; inside the while loop. BTW, isn’t that variable name backwards? You set it to 1 (i.e. true) when you discover that there’s … Read more
[ad_1] It’s pretty much just like the std::list iterator, except the end iterator is where the next pointer is the head of the list, not when it’s NULL. A reference page will tell you what you’re supposed to implement. The underlying representation will be a pointer to a list node, operator* will return a reference … Read more
[ad_1] The initial value of current_line is 1. When you call, current_line = current_line + 1, we first evaluate what’s on the right hand side of the =. That is current_line + 1, which gives 2. Now 2 gets assigned to the variable on the left of =, which is current_line. So now current_line is … Read more
[ad_1] Answer of your Question #include <stdio.h> int main() { int array[10]; int num, negative_sum = 0, positive_sum = 0,j; static int i=0; float total = 0.0, average; label: j=i; printf (“Enter the value of N \n”); scanf(“%d”, &num); printf(“Enter %d numbers (negative, positve and zero) \n”, num); for (i; i < (j+num); i++) { … Read more
[ad_1] Let’s see. Assume first time it runs, x,y is 1,1. So you add Box(1,1). Next time is run, let’s assume x,y is 2,3. So, enter for loop: i = 0: Not same x,y, so enter else, and add Box(2,3). i = 1: Same as x,y (yeah, we just added it), so enter if and … Read more
[ad_1] Bro don’t worry. There’s nothing wrong in your site or whatever site you have inspected on. It’s the google chrome’ updated feature to hide html source. When you click on the source link situated in left nav bar, you will get the source code. You don’t need to refresh it. And also view source … Read more
[ad_1] To check if a string contains at least one upper character, one lower character and one number, you can use the Char.IsUpper / IsLower / IsNumber methods. Private Function IsValidPasswordFormat(ByVal text As String) As Boolean If String.IsNullOrEmpty(text) Then Return False End If If text.Any(Function(c) Char.IsUpper(c)) AndAlso text.Any(Function(c) Char.IsLower(c)) AndAlso text.Any(Function(c) Char.IsNumber(c)) Then Return True … Read more
[ad_1] Below is a basic login form code. If this is fine mark it as answer. if(isset($_POST[‘login’]) && $_POST[‘login’] ==’Login’) { $user = $_POST[‘user’]; $pass = $_POST[‘pass’]; if($user==’admin’ && $pass=”abcd”) { // your success code } else { //your error code } } ?> <form action=”” method=”post” accept-charset=”utf-8″> <table> <caption>Login Form</caption> <tr> <td>User</td> <td><input type=”text” … Read more
[ad_1] The second helper method isn’t necessary. Here is a shortened version. public class IntToSetNotationRecursive { private static final String openBrace = “{“; private static final String closeBrace = “}”; private static final String separator = “,”; public static void main(String[] args) { for (int i = 0; i < 6; i++) { System.out.println(i + … Read more
[ad_1] You should have a Product class. Each product object has different quantity measures and increment methods. Something like this: public abstract class Product { String quantityMeasure; //You can encapsulate this with a getter public abstract int step (int value); //here you want to increment “value” with different algorithms. } Now you can create different … Read more
[ad_1] You can’t. There is not such thing that converts one os native app into other os nativ app. You can write for example in phonegap to support many os with same code, but this is other approach. I think if you manage to write such a system that can covert one native app into … Read more
[ad_1] You can use the GROUP BY command, like this : http://sqlfiddle.com/#!9/a0057/5/0 [ad_2] solved how to select one of each kind from database in php