See the reference: template< class Key, class T, class Compare = std::less<Key>, class Allocator = std::allocator<std::pair<const Key, T> > > class map; http://en.cppreference.com/w/cpp/container/map An std::map takes a comparator that tells if the first argument is less than the second. Not if they are equal. Otherwise it could not build a binary tree. You don’t need … Read more
FYI: I gave a detailed answer. So, please read the answer fully and understand what are all the changes I made in your code. Answer in Detail: Give Identification for each fieldset to work as per your requirement. do like below, <fieldset id=”firstField”> <!– First Step –> <fieldset id=”mathsField”> <!– Maths –> <fieldset id=”scienceField”> <!– … Read more
You can try something with 2^N (N can takes as length ). Then convert 0-2^N to binary and use proper binary formating. The you can have what you looking for. First step- get 2^N double twosPow = Math.pow(2, occurrence); Now iterate from 0 up to twosPow. and convert number to binary Second step- how to … Read more
You have the possibility to declare the variable as decimal, like this: decimal caloriesBurned; solved Cannot implicitly convert type ‘decimal’ to ‘int’. An explicit conversion exists (are you missing a cast?)
Step 1: Combine all the arrays Step 2: Sort arrays using Arrays.sort(array); Step 3: Remove the duplicates. int[] a = {1,2,3,4,5}; int[] b = {1,2,3,4,5,6}; int[] c = {1,3,7}; int[] d = {2,3,4,8,9,10}; int[] resultArray1 = new int[a.length+b.length+c.length+d.length]; int arrayIndex = 0; for (int i=0; i< a.length ; i++, arrayIndex++ ) { resultArray1[arrayIndex] = a[i]; … Read more
Your data model should be as follows: public class Info { public string prop1 {get;set;} public string prop2 {get;set;} public int prop3 {get;set;} // Modified from //public Dictionary<string, List<int>> prop4 {get;set} public List<Dictionary<string, int>> prop4 {get;set;} } public class Response { // Modified from //public class Dictionary<string, List<Info>> Item {get;set;} public Dictionary<string, Info> Items {get;set;} … Read more
The command for this is ATND. Just send the packet 0x7E 0x00 0x06 0x08 0x01 0x41 0x54 0x4E 0x44 0xCF to the coordinator. 0 solved Zigbee Network in API mode
No, and for a good reason: users should always have control over what’s executed in their user agents. Why don’t you just minify and obfuscate the code? 3 solved Protect javascript code from copying [duplicate]
Throughout this post let’s assume numbers are one hex digit, just for simplicity. “>>” is the bit shift operator. For example: 8 >> 1 == 8 / 2 == 4; Which in binary is equivalent to b1000 >> 1 == b0100; Adding the third “>” into the operator inserts a 0 into the now far … Read more
Nested* Nested_create(List list) { Nested* new = malloc(sizeof(Nested)); new->list = list; new->next = NULL; return new; } void Nested_add(Nested** proot, Nested* node) { if (*proot == NULL) { *proot = node; } else { Nested* cur = *proot; while (cur->next) cur = cur->next; cur->next = node; } } void createlistoflists(Nested **LIST, List list1, List list2, … Read more
Your for loop is shorthand for the following code: int i = start; if (i <= end) { /* loop body */ i += step; } To answer your question, it will run ceiling((end – start + 1) / step) times. Walk through the logic on paper to see if you come to the same … Read more
The framework is still free and available (Click Free Download, sign in, and you will be given the option to download the free version). What Telerik (we) are selling is derived from the Design canvas, which was commercial before the merge. 2 solved Looking for WebAii Framework free edition online – before the Telerik merge … Read more
You could pass a pointer and de-reference it in the function: int num5(int* pnum) { *pnum = 5; // you may want to check that pnum is not NULL return 0; // presumably you don’t always return 0 in real code } Then int number = 42; printf(“%d”, number); // prints 42 int ret = … Read more
Well designed test shows that first function is slowest on Python 2.x (mostly because two lists have to be created, first one as a increasing range, second one as a reverted first one). I also included a demo using reversed. from __future__ import print_function import sys import timeit def iterate_through_list_1(arr): lala = None for i … Read more
How about this: String greetings = “Hello” + “,” + ” how are you”; Or this: String greetings = “Hello how are you”; greetings = greetings.substring(0, 5) + “,” + greetings.substring(5); Or this: String greetings = “Hello how are you”; greetings = new StringBuilder(greetings).insert(5, “,”).toString(); Inserting a punctuation mark is trivial if you know where … Read more