ids = [int(row[‘id’]) for row in b[‘cricket’][‘Arts & Entertainment’]] will give you a list of the numbers, [6003760631113, 6003350271605, 6003106646578, 6003252371486, 6003370637135] And for your new edits; ids = [int(row[‘id’]) for row in b[‘cricket’][‘Arts & Entertainment’] + b[‘News, Media & Publications’]] 3 solved Parse a nested dictionary [closed]
Split: Now you have obtained the JSON string you can parse with Split function. Here I am reading the JSON in the comments from a cell Option Explicit Public Sub GetExchangeRate() Dim json As String json = [A1] Debug.Print Split(Split(json, “””5. Exchange Rate””: “)(1), “,”)(0) End Sub JSON Parser: Here you can use a JSON … Read more
It’s depends on which developers you are targeting and what you are trying to develop. The majority of developers will probably use native solutions, Objective-C /Swift for iOS and Java/Kotlin for Android and the is no way of creating a single library for both unless you develop C/C++ code but this would probably be problematic … Read more
What you want IMHO @IBAction func didTapPreviousButton(_ sender: UIButton) { currentTrack -= 1 if currentTrack < 0 { currentTrack = (urlPlayerItems.count – 1) < 0 ? 0 : (urlPlayerItems.count – 1) } playTrack() } Correct replacing of POSTFIX as you have it (useless) @IBAction func didTapPreviousButton(_ sender: UIButton) { if currentTrack < 0 { currentTrack … Read more
Use a JSON library for Java. Then serialize your ArrayList to JSON: ArrayList wordslist = new ArrayList(); wordslist.add(“Hello”); wordslist.add(“again”); String json = (new JSONArray(wordslist)).toString(); Echo the JSON text at the appropriate place in your JavaScript code. E.g. $(document).ready(function(){ var arr = <%= json %>; $.each( arr, function(i, l){ alert( “Index #” + i + “: … Read more
Below query should do the job. Names in the ADDED_BY column seem to be the reference for aggregation in both your columns. SELECT A.ADDED_BY, A.TOTAL_RECORDS_ADDED_BY, COUNT(B.UPDATED_BY) AS TOTAL_RECORDS_UPDATED_BY FROM (SELECT ADDED_BY, COUNT(*) AS TOTAL_RECORDS_ADDED_BY FROM YOUR_TABLE GROUP BY ADDED_BY) A LEFT JOIN YOUR_TABLE B ON A.ADDED_BY = B.UPDATED_BY GROUP BY A.ADDED_BY, A.TOTAL_RECORDS_ADDED_BY; solved SQL Query … Read more
You could use the RIGHT() part of the string filtering wher the firts is a number eg: SELECT right(my_column, LENGTH(my_column)-1) FROM my_table WHERE my_column REGEXP ‘^[0-9]’ for update (remove the number ) you could use Update my_table set my_column= right(my_column, LENGTH(my_column)-1) WHERE my_column REGEXP ‘^[0-9]’ 1 solved How to remove first letter if it is … Read more
Assuming that you want to so something(remove Arrival) on each of the values, you can use this: <?php $results = array ( ‘date’ => ’22. jan.’, ‘flightNumber’ => ‘EZY6747’, ‘airline’ => ‘easyJet’, ‘from’ => ‘Belfast International’, ‘plannedArrival’ => ’18:35′, ‘realArrival’ => ‘Estimated Arrival 18:32’ ); $result2 = array_map(function($s) { return str_replace(‘Arrival ‘, ”, $s); }, … Read more
Your problems stem from this statement: scanf(“%c”,&user); The %c conversion specifier only reads a single character from the input stream, not a string. If you entered a username like jbode, only the ‘j’ character is read from the input stream – the remaining characters will be read by the next scanf (or other input) call. … Read more
You can’t fill a list in this way. Because you start with an empty list, Jewels = [], your attempt to assign to Jewels[0] will result in an IndexError. You can instead use the list.append method jewels = [] for i in range(total_jewels): jewels.append(raw_input(‘Please Enter approx price for Jewel #{}: ‘.format(i))) or a list comprehension … Read more
It sounds like you want to create a secondary matrix that displays the information with a different grouping entirely. It is possible to have two matrix/tables that use the same data, and that’s how I would go about solving this. 15 solved Totals in Matrix in SSRS
Solved. The issue was buildRates() not being a proper promises, oops! 2 solved Javascript await object property to be set
CONVERT(CHAR(10), CONVERT(DATETIME, Created), 103) solved SQL date-format conversion ques
You can use time() to get the current time in seconds (UNIX) and add 3600*4. echo date(“F j, Y, g:i a”, time()+3600*4); solved Add +4GMT for php [duplicate]
Duplicate file error comes when you have added the dependency jar to build.gradle file and also you are having same .jar file in your libs folder. To eliminate this error try to have only one thing, either have it in your build.gradle or in locally in your libs folder. 0 solved I am trying to … Read more