Console.ReadLine gives you a string a string is, among other things, a collection of chars try this string number = “”; int numb = 0; Console.WriteLine(“Please enter the telephone number…”); number = Console.ReadLine(); for(int i=0; i<number.Count; i++) { if (number[i] == ‘A’) { //… } } solved Convert string to char error message [closed]
I believe what you are trying to do is to add a value to PizzaPrice, then display it on txtPizzaPrice.Text with the £ sign appended to the front. PizzaPrice should be a property rather than a field. public double PizzaPrice { get; set; } Notice that I += the value to pizza price, then display … Read more
you end the if block in the previous line when put a instruction at the same level indentation that the if statement if condition: stuff something # doing this close the if block and a elif can only happen in a if block and you do that in if row_count == 0: for i in … Read more
My advise: A code at run time cannot be editted! Specially when you’re running the code and a client is using the service. You can edit the code by yourself only. Client would be using if else block statements only. You can edit the code, and add some if else blocks to it, so that … Read more
To toDF(), you must enable implicit conversions: import spark.implicits._ In spark-shell, it is enabled by default and that’s why the code works there. :imports command can be used to see what imports are already present in your shell: scala> :imports 1) import org.apache.spark.SparkContext._ (70 terms, 1 are implicit) 2) import spark.implicits._ (1 types, 67 terms, … Read more
I assume you mean from posting something rather than and posting something. The simple explanation is that on any page that requires authorization, you need to check whether the current user is authorized. The simplest way to do this with a secure cookie and is built into PHP via the Session module. On the login … Read more
Take a look in syscomments for the text and join to sysobjects for the object type and name sysobjects syscomments solved How can I find all occurrences of particular text within all stored procedures in my database? [closed]
Please Refer this MSDN Documentation: Framework Element Margin solved Guidance to solve margin problems in XAML [closed]
This is a generalized solution that works by these principles: Performs linear interpolation It calculates a “floating point index” into the input array This index is used to select 1 (if the fractional parts is very close to 0) or 2 numbers from the input array The integer part of this index is the base … Read more
condition should be incrementing by 10: for (int x = 10; x <= 20; x=x+10) solved Unexpected behavior of a switch statement in a for loop [closed]
I’d use map(), because it’s there for this very purpose (no need for temp array) var textLinks = $(“a”).map(function(){ return $.trim($(this).text()); }); Edit: If I was looking for the fastest solution I’d start with ditching jQuery 😉 var textLinks = (Array.prototype.slice.call(document.links)).map(function(a){ return a.textContent || a.innerText }) Or if you’re concerned about browsers without Array.map use … Read more
Here’s a Working Fiddle Tested on: IE10, IE9, IE8, FF, Chrome, Safari notice: although I’m using absolute positioning, this layout is completely responsive. (resize your browser to see it in action) this solution still has a downside: the left menu width and the main content width are fixed. (I’ll try to remedy that and update … Read more
import re inp = open(‘menu.bak’, “r”) outp = open(‘word.txt’,”w”) for line in inp: for word in line.split(): outp.write(str(word) + “,” + “1” + ‘\n’) inp.close() outp.close() solved How to print each word of a string printed as new record?
First of all you need to examine the structure of the JSON response, using any online JSON viewer (e. g. http://jsonviewer.stack.hu/), where you can see that your JSON object contains atletas array, clubes, posicoes, status, time objects, and several properties with scalar values: Going further there are objects within atletas array, each of them contains … Read more
try this: public String getTestGauge(){ return String.valueOf(<yourdouble>); } –> this is prettier return (new Double(<yourdouble>).toString()); solved Converting double to string with a return