There are a lot of answers to this question in stackoverflow. Next time search before you ask! Here is a simple code which gives what you want: String str= “animal 1 animal”; Pattern p = Pattern.compile(“-?\\d+”); Matcher match = p.matcher(str); while (match.find()) { System.out.println(match.group()); } It is the same with your other Strings.. just change … Read more
Do this and please learn the usage of operators beforehand. if(a<=b && b<c) { //do stuff } solved C++ operator precedence a
Poorly phrased question, but if the values you have as keys (A1, A2, etc…) are String and you want to check by the first letter of the key, you can try something like this: int count = 0; for (String k : myMap.keySet()){ if(k.startsWith(“A”)){ count++; } } 4 solved How to count the number of … Read more
The following method should resolve your problem public boolean isInRange() { Calendar calendar = Calendar.getInstance(); int minute = calendar.get(Calendar.MINUTE); return minute >= 10 && minute < 15; } It simple recoveries the minute from the current time and verifies if it is between 10 and 15 0 solved Using Java, how can i see if … Read more
Strings in C need to be NUL terminated. This means you need to add a zero value byte to the end of the string to indicate the end of the string. Because you have no indication of the end of the string when you view/print the value you are reading on past the end of … Read more
You should declare your variables correctly int z,a,b,c,d,e,f,g; and calculate the max score only after you read in all the values. 1 solved Java compile error: symbol cannot be found [closed]
Yes, for gcc5.x and later specifically, that specific expression is optimized very early to just p, even with optimization disabled, regardless of any possible runtime UB. This happens even with a static array and compile-time constant size. gcc -fsanitize=undefined doesn’t insert any instrumentation to look for it either. Also no warnings at -Wall -Wextra -Wpedantic … Read more
you can try: having a bool property called completed. perform selector after delay //(some selector showBusy, some delay) completed = NO; dispatch_queue_t myqueue = dispatch_queue_create(“queue”, NULL); dispatch_async(myqueue, ^{ //your long time operation (must not do any UI changes here) dispatch_async(dispatch_get_main_queue(), ^{ //UI here completed = YES; hideBusy; }); }); -(void)showBusy{ if(!completed)….. } 2 solved how … Read more
extension Optional { func safeUnwrap(_ defaultValue: Wrapped) -> Wrapped { switch self { case let value?: return value case nil: return defaultValue } } } Or even extension Optional { func safeUnwrap(_ defaultValue: Wrapped) -> Wrapped { self ?? defaultValue } } But as was pointed out, this is more wordy and less idiomatic than … Read more
Simplest solution if all arrays have same length: string rowFormat = “{0,15}|{1,3} {2,3}”; Console.WriteLine(rowFormat, “History”, “B”, “W”); Console.WriteLine(new String(‘=’, 25)); for(int i = 0; i < array1.Length; i++) Console.WriteLine(rowFormat, array1[i], array2[i], array3[i]); But I would suggest to use custom type for your data instead of keeping data in three arrays. E.g. (names according to your … Read more
arguments[0]() is executing in the Window context, but it does not have any object property defined in the name bar (which is a property of foo). This is why you get undefined. To solve the issue, you can bind the object. Change foo.bar To foo.bar.bind(foo) var foo = { bar: function() { return this.baz; }, … Read more
Often you can use a named vector to do these sorts of mapping operations simply: students <- data.frame(name=c(“J. Holly”,”H. Kally”, “P. Spertson”, “A. Hikh”, “R. Wizht”), CRSE_GRADE_OFF=c(“A”,”D”,”E”,”A”,”A”)) scores = c(A=1, B=2, C=3, D=4, E=5, F=6) students$grade <- scores[as.character(students$CRSE_GRADE_OFF)] students # name CRSE_GRADE_OFF grade # 1 J. Holly A 1 # 2 H. Kally D 4 … Read more
How about this solution #include<stdio.h> int main() { int i; int arr[]={ 2, 1 ,4 ,3 ,6 ,5 ,8 ,7 ,9}; int arr_size = sizeof(arr)/sizeof(arr[0]); int sorted[arr_size]; int sp = 0; for(i=0;i<arr_size;i++){ if(arr[i]&1){ sorted[sp++]=arr[i]; } } for(i=0;i<arr_size;i++){ if(!(arr[i]&1)){ sorted[sp++]=arr[i]; } } for(i=0;i< arr_size ;i++) printf(“%d “, sorted[i]); return 0; } the output is 1 3 … Read more
$(‘.album_reviews’).find(‘.recensie:odd’).addClass(‘selected’); DEMO 1 solved How to add class to odd class “recensie” within section with class ‘album_revieuws’
// Allow <p> and <a> echo strip_tags($text, ‘<p><a>’); http://php.net/manual/en/function.strip-tags.php 2 solved Screen HTML in User Input? [closed]