It’s called reflection, you cannot do this with c++. Use another languages like java or c# for that. 6 solved C++ – Programmatically call correct function parameters [duplicate]
I figure out what the error is for those in future who might be banging their head wondering what went wrong. It’s actually really simple. A small typo actually. Too bad M$ have horrible error message that don’t really tell you where the error might have happened: Simply replace this line: public void GetObjectData(SerializationInfo info, … Read more
I recommend for you the SharedPreferences. This is an in Android simple class, that stores you data in Key-Value sets. Here is the code: SharedPreferences prefs = PreferenceManager.getDefaultSharedPreferences(getApplicationContext()); This initialize your SharedPreferences. If you want to write/change a value, do this: SharedPreferences.Editor editor = sharedPref.edit(); editor.putInt(“KEY_TO_VALUE”, 123); editor.commit(); You also can put in there other … Read more
Impossible to answer because you haven’t given us anywhere near enough information. But your code does give one potential clue. use CGI qw/:standard/; use DBI; print “Content-type:text/html\n\n”; print first(); print myform(); print second(); sub myform { return <<B; <form action=” method=’post’> <img src=”https://stackoverflow.com/questions/26614013/images/img0001.gif” id=”Shape1″ align=”top” alt=”” title=”” border=”0″ width=”1344″ height=”126″> … </form> B } You … Read more
You can use either “0|5” or “[05]”. The first is an alternative, the second is a character class. They will behave identically. See the documentation for Pattern for more information on the building blocks for regular expressions. solved Java – Regex only 0 or 5 [closed]
Use sets! static int NumberOfDigits(int a) { return new HashSet<char>(Math.Abs(a).ToString()).Count; } We make a into a string and then turn the string into a set of characters. Since sets cannot contain duplicate values, the count of the set is the number of distinct digits. solved How to count the number of different digits in a … Read more
You could fill the Pits with Box Collidiers wich are marked as Triggers. Then you write a Script with void OnTriggerEnter(Collider other){ if(other.gameobject.tag == “Player”) //do something } Doku OnTrigger Enter That should do the Job 1 solved Unity3d how can i program my game?
.div { position: relative; overflow: hidden; padding: 50px 0; } .div-inner { position: relative; background: black; height: 120px; } .div-inner:before, .div-inner:after { box-shadow: 0 0 0 80px #000; border-radius: 100%; position: absolute; height: 150px; /* You can change it */ content: ”; right: -20%; left: -20%; top: 100%; } <div class=”div”> <div class=”div-inner”></div> </div> 0 … Read more
None of those two cases are right. Case 1 only worked because you got lucky, probably by giving a short string as input. Try something like “bfjabfabjkbfjkasjkvasjkvjksbkjafbskjbfakbsjfbjasbfjasbfkjabsjfkbaksbfjasbfkja” and you’ll suffer a seg fault, most likely. You should have a block of memory associated with str, either on the stack by declaring an array for it … Read more
try this: class CreatePages < ActiveRecord::Migration[5.0] def change create_table :pages do |t| t.string :name t.text :description t.text :address t.text :contact t.string :profile_image t.string :cover_image t.string :look_book t.integer :seller_id t.timestamps end end end solved Error undefined methode ‘interger’ when make migrate [closed]
Try this System.out.println(“originaltext”.replaceAll(“.{1}”,”$0ry”)); The above is using the String replaceAll(String regex, String replacement) method – “Replaces each substring of this string that matches the given regular expression with the given replacement.” “.{1}” – The regular expression used to find exactly one occurrence({1}) of any character(.) “$0ry” – The replacement string with “$0” for the matched … Read more
Lists don’t take name-value pairs. You probably want dictionaries here instead: definitions = { ‘title_label’: { ‘text’: (236, 218, 51), ‘background’: (125, 142, 246) }, ‘start_button’: { ‘text’: (32, 40, 145), ‘background’: (236, 235, 136), ‘pressed’: (44, 51, 112) }, ‘quit_button’: { ‘text’: (166, 21, 13), ‘background’: (48, 61, 188), ‘pressed’: (31, 40, 129) } … Read more
That’s because BufferedReader.readLine() reads only a line not the whole file. I assume that the line break characters \r and \n are not part of the normal content you interested in. Maybe that helps. // … StringBuilder sb = new StringBuilder(); String line; while ((line = inputStream.readLine()) != null) { sb.append(line); // if enough content … Read more
There are many possible solutions to this problem. Here’s a reusable solution that simply decrements from 4 to 1 and adds the expected number of 1’s and 0’s. Loops used : 1 def sequence(n): string = “” for i in range(n): string+=’1’*(n-i) string+=’0’*(n-i) return string print sequence(4) There’s another single-line elegant and more pythonic way … Read more
Think of it as a greedy algorithm, it will take as many characters as possible, if they make sense. Example: i+ // good, keep going i++ // good, keep going i+++ // not good, start new token + // good, keep going +- // not valid, start new token – // good — // good … Read more