[ad_1] This will run forever: for(a;strlen(tab);a++) I think you meant: for(a;a < strlen(tab);a++) Or better (because strlen is O(n)): for(;tab[a];a++) 3 [ad_2] solved tolower() and toupper() aren’t working [closed]
[ad_1] I can spot following problems: The first rewind(fp); is useless and wrong. Useless because after opening the file, the file pointer it is already at the beginning, and wrong because if the file could not be opened for some reason, fp is NULL and rewind(NULL) is undefined behaviour, most likely you’ll get a crash. … Read more
[ad_1] Problem solved! There is no issue within the code, the problem was far more subtle. For reasons unknown and a situation I’ve never seen before, the string that was being passed in (testString), had a byte order mark at the start of it. This was never shown in any text editors, and was only … Read more
[ad_1] You made variable with name that matches type name (string variable, string type?). Plus there is issue that you return pointer to object with local scope of life. That is UB. Using iterators your function would work like this: const string shortest_string(initializer_list<string> strings) { if(!strings.size()) return string(); auto shortest_one = strings.begin(); for (auto it … Read more
[ad_1] Here is a demonstrative program written in C++ that you can use as an algorithm and rewrite it in C #include <iostream> #include <iomanip> #include <stack> #include <cstring> bool balance( const char *s, std::stack<char> &st ) { const char *open = “({[<“; const char *close = “)}]>”; if ( *s == ‘\0’ ) { … Read more
[ad_1] You could try converting double nN to a string and see if your String line contains it with if statement: if (line.contains(Double.toString(nN))) { code… } [ad_2] solved Check if certain numbers are in a string
[ad_1] This statement if(words[j+1].(int)name[0]<words[j].(int)name[0]){ is syntactically invalid. The correct statement will look the following way if( ( int )words[j+1].name[0]<( int )words[j].name[0]){ However there is no any sense to make such a record because (the C++ Standard) The usual arithmetic conversions are performed on operands of arithmetic or enumeration type On the other hand if type … Read more
[ad_1] use cin.ignore(); before using getline() to empty the buffer.Read more here: When and why do I need to use cin.ignore() in C++? 1 [ad_2] solved Why code is jumping while inputting strings?
[ad_1] All you need is $str = “abab cdcd efef”; $list = array_map(function ($v) { $v = str_split($v); shuffle($v); return implode(current(array_chunk($v, 2))); }, explode(” “, $str)); echo “<pre>”; print_r($list); Output Array ( [0] => ab [1] => cd [2] => ef ) Simple Online Demo 1 [ad_2] solved How to randomly select characters from string … Read more
[ad_1] Your task can be effectivelly accomplished using regular expressions. Your regex could look like: (?<=\[“)[^”]+ See it live here. The (?<=\[“) part is so called lookbehind, you say you are looking for anything that follows [“. Then you simply take any characters except ” Extract from .NET Regex Reference: (?<= subexpression) Zero-width positive lookbehind … Read more
[ad_1] Have you tried: std::string one = “stringa”; std::string two = “stringb”; std::string three = “stringa”; std::string four = “stringb”; if( one == three && two == four ) { return true; } else { return false; } 1 [ad_2] solved My loop condition isn’t being met
[ad_1] Basically for each line, compare it with the next line to see if the next line is shorter or if the next line’s substring is not equal to the current line. If this is true, the line is unique. This can be done with a single linear pass because the list is sorted: any … Read more
[ad_1] yshavit: What you’re trying to do isn’t easy/natural to do in Java. You’re basically trying to write an expression which creates and immediately invokes a method, basically as a way of grouping a bunch of statements together (and also providing an enclosed scope) to get a single value. It’s not an unreasonable thing, and … Read more
[ad_1] What are the repercussions of not using null termination in strings? Technically none, because C strings are – by definition – terminated by a null character: A string is a contiguous sequence of characters terminated by and including the first null character. So if it’s not properly terminated, it’s not a string. If you … Read more
[ad_1] Just do str_.equals(“{“); or str_.equals(“}”); We are still not sure which brace EDIT: Ah now we have clarity. Use str_.equals(“}”); 3 [ad_2] solved How to check if a string equals to “}”