[ad_1] I need to replace : with “:” form the string “AAAA:123346hadhdhajkkd890” result like “AAAA”:”123346hadhdhajkkd890″ using Replace functionality in C# [ad_2] solved I need to replace : with “:” form the string “AAAA:123346hadhdhajkkd890” result like “AAAA”:”123346hadhdhajkkd890″ using Replace functionality in C#
[ad_1] string oldValue= “iif([PricingTKt_US]>0,1-([F221-B01]/iif([PricingTKt_US]=0,1, [PricingTKt_US])),0)”; PricingTKt_US Capital K. oldValue=oldValue.Replace(“[PricingTkt_US]”,”[F123]”) PricingTkt_US Small k [ad_2] solved C# String Replacement not working [closed]
[ad_1] If $monster is an array and mysql_real_escape_string as the name implies, takes a string, you must pass it a string. Since the function takes a $monster_name, perhaps you need to take that from the $monster array? Something like (without any idea of your code, just as an example, do not copy and paste 🙂 … Read more
[ad_1] You might want to use use zip functionality to print pairs of values. list1 = [“1”, “2”] list2 = [“3”, “4”] for pair in zip(list1, list2): print i This will print: (‘1’, ‘3’) (‘2’, ‘4’) Please notice that the lists should be at the same size. 2 [ad_2] solved Print a single string from … Read more
[ad_1] Answer 1.Declared a array list. List<String> productPrice = new ArrayList<String>(); 2.Stored a string object in that array list fname = obj1.getPrice(); productPrice.add(fname); 3.And in last used text utils for joining that array list items via comma. android.text.TextUtils.join(“,”, productPrice); [ad_2] solved seprate object data via coma for every item but not last
[ad_1] The for loop actually does loop, it just does do anything unless the answer is correct. you want: while enter!=”off”: if enter == “1”: prefer= input(“enter your preference”) if prefer ==”sports”: print(“Hardcore Sports Podcast”) enter = input(‘Enter 1 – recommendation, 2 – draw, off – exit’) else: print(“Kanye West’s new album”) enter = input(‘Enter … Read more
[ad_1] Try this. static String removeDuplicatePhrase(String s1, String s2) { s1 = s1.trim(); s2 = s2.trim(); List<String> list1 = List.of(s1.split(“\\s+”)); List<String> list2 = List.of(s2.split(“\\s+”)); int size1 = list1.size(), size2 = list2.size(); int i = Math.min(size1, size2); for (; i > 0; –i) if (list1.subList(size1 – i, size1).equals(list2.subList(0, i))) break; return String.join(” “, list1) + ” … Read more
[ad_1] Based on the conditions you mentioned you can do something like below. Find the word count and then check is home available in the string and then find the index of the house . So then you can check does that index match to last index of the word array (count($wordArray)) – 1) $string1 … Read more
[ad_1] You can do something like, NSString *str = @”any string”; NSData *data = [str dataUsingEncoding:NSUTF8StringEncoding]; NSMutableData *mutableData = [data mutableCopy];; Hope this will help 🙂 0 [ad_2] solved Convert string to mutable data – objective c [duplicate]
[ad_1] review String Interning or .Net String Intern table or CLR Intern Pool. Basically, the Common Language Runtime (CLR) maintains a table of [unique] string values, and whenever you manipulate a string in your code, the CLR examines this intern table to see if the new value you are trying to create is already in … Read more
[ad_1] As 4castle suggest, you should really have a custom class – which looking at the properties you are interested in, you might want to name “CallLogEntry” and then have properties for this class. Here is an example of such a custom class. public class CallLogEntry { String number; String type; String date; String duration; … Read more
[ad_1] With java 8 it is much easy. You could use something like this return string.chars().distinct().count(); [ad_2] solved How to find number of distinct characters in a string
[ad_1] From the documentation: A new string made by removing from both ends of the receiver characters contained in set. It does not remove characters within the string. You can replace whitespaces – corresponding to the .whitespaces character set – in the string with regular expression: let _searchStr = searchStr.replacingOccurrences(of: “\\s”, with: “”, options: .regularExpression) … Read more
[ad_1] Similar to previous answer but with the following suggestions Initialize longest and shortest. Ignore case when comparing. Could still do this with SequenceEqual instead of comparing strings. May not be needed if you know you won’t be comparing Anna to annA. When checking if you found the shortest you need to remember that shortest.Length … Read more
[ad_1] If you need to be able to reference lil_patate elsewhere in your code then you can’t make this factorisation at all. If you don’t need to refer to lil_patate elsewhere then get rid of it and initialise patate directly from q_nutrients: string patate(to_string(q_nutriments)); However, while this may improve the readability of the code, it … Read more