$str = “COVId 1234 | SARS 4567 | EBOLA 2332”; preg_replace(‘([a-zA-Z]+ \d+ )’, ‘$0 |’, $str); echo $str; // COVId 1234 | SARS 4567 | EBOLA 2332 [a-ZA-Z]+ matches all alphabetic chars. is just to match a space. \d+ matches digits. Note the plural. 0 solved Find a match pattern of any digit and space … Read more
This operator+ is used here (a pointer to single char that is not null-terminated is not really suitable). Yes, most definitely undefined behavior. lhs – string, character, or pointer to the first character in a null-terminated array Just make std::string the common type to fix it: ((d == ‘\0’) ? std::string(“null character”) : std::string(1, d)) … Read more
public class Run { public static void main(String[] args) { String string = “I love stack overflow very much”; //replacing all newline and and then making tokens String[] words = string.replaceAll(“\\s”, “”).split(“(?<=\\G.{8})”); for (String st : words) { if (st.length() == 8) { // if length of the string is 8, just print the string … Read more
Sounds like you are looking for the repr() function: >>> s=”hello” >>> print repr(s) ‘hello’ solved Printing a string with the parentheses attched [closed]
Some Code char s[10]; snprintf(s, 10, “%05d”, 100); Which results in s contains “00100” 0 solved C: How to extend variable-length strings to set length [closed]
You could explode the string into an array by spaces, sort it and implode it back into a single string. Something like that: $string = “Lorem ipsum dolor sit amet consectetur adipiscing elit quisque facilisis tincidunt finibus aliquam id tempor elit ut in massa quis nisi dapibus tempus class aptent taciti sociosqu ad litora torquent … Read more
Move the dictionaries in dicts.py and create a class in template.py to return required template.You can create as many templates as you want in templates.py. dicts.py teams = {…} nouns = {…} article_words = {…} template.py from grammer import getArticle import random class Template(): def __init__(self,**kwargs): self.__dict__.update(kwargs) # must define other variables like article which … Read more
You can count the length of the string using function len. str can contain all chars and letters. Try the following code: word = input(“Waiting for input: “) print(“Found “+str(len(word))+” letters!”) Testing it: Waiting for input: hello Found 5 letters! Testing it with numbers and other chars: Waiting for input: hello123!@# Found 11 letters! 2 … Read more
This is a example program to get what you asked for… hope it helps public static void main(String[] args) { ArrayList<String []> a = new ArrayList<>(); String b[] = {“not here”,”not here2″}; String c[] = {“not here3″,”i’m here”}; a.add(b); a.add(c); for (String[] array : a) {// This loop is used to iterate through the arraylist … Read more
== compares references not the content To compare strings you need to use String#equals: .equals(); //If you consider the case .equalsIgnoreCase(); //If you not consider the case 0 solved What’s wrong with == operator on java string [duplicate]
Simple, type safe solution: enum Grade : Double { case A = 20.0 case B = 17.5 case C = 15.0 case D = 12.5 case E = 10.0 case F = 0.0 } extension Grade : Comparable { static func <(lhs: Grade, rhs: Grade) -> Bool { return lhs.rawValue < rhs.rawValue } } let … Read more
You can’t apply the ++ operator to a string, but you can implement this logic yourself. I’d go over the string from its end and handle each character individually until I hit a character that can just be incremented simply: public static String increment(String s) { StringBuilder sb = new StringBuilder(s); boolean done = false; … Read more
Given a non-empty list of strings of the same length, how do I create a list of lists of the letters at each position in the string without using zip? [closed] solved Given a non-empty list of strings of the same length, how do I create a list of lists of the letters at each … Read more
You just need backslash to escape: System.out.println(“\”” + s + “\” ” + GM); Output: “Juan” GOOD MORNING 1 solved how to separate string with special character in Java
Create two variables: std::string maxVal = fn; std::replace(maxVal, ‘X’, ‘9’); std::string minVal = fn; std::replace(minVal, ‘X’, ‘0’); Now you can loop with for (auto i = std::stoi(minVal), j = std::stoi(maxVal); i <= j; ++i) { codes.push_back(i); } The whole Code #include <algorithm> #include <iostream> #include <list> std::list<unsigned> stringToCode(std::string fn) { std::string maxVal = fn; std::replace(std::begin(maxVal), … Read more