As commented, it would be a lot simpler if you put the old and new ID values in a CSV file like this: “OldID”,”NewID” “12345”,”98765″ “23456”,”87654″ “34567”,”76543″ Then, something like below should work: # read this CSV to get an array of PSObjects $ids = Import-CSV -Path ‘D:\ReplaceId.csv’ # build a lookup table from the … Read more
MVC 5 With Tinymce Editor Contain Words “FIND”, “SERVICES” and some more around 8 more letter “ERR_CONNECTION_RESET” solved MVC 5 With Tinymce Editor Contain Words “FIND”, “SERVICES” and some more around 8 more letter “ERR_CONNECTION_RESET”
test=”qwertyuiopasdfghjklzxcvbnm” def changestring(string): for x in ‘aeiou’: string = string.replace(x, ‘*’) return string changestring(test) ‘qw*rty***p*sdfghjklzxcvbnm’ Is this what you are trying to do? 5 solved Why can’t I return the modified str_func function back to the main function?
s/(\d{1,3}\.\d{1,3})\.233(\.\d{1,3})/$1.234$2/ Will do what you want in PCRE 5 solved Swap multiple parts of an IP using a Perl REGEX [duplicate]
If I understand your question, you could use String.replace(CharSequence, CharSequence) like String str=”abcd”; String rep=”cd”; String nv = “kj”; str = str.replace(rep, nv); // <– old, new System.out.println(str); Output is (the requested) abkj 1 solved Replace String variable with exact string
You may try something like this: var dictionary= { “My Classes”:”My Levels”, “My Class”:”My Level”, “college”:”university” }; $(“body *”).each( function(){ for( var ptrn in dictionary){ $(this).text( $(this).text().replace(new RegExp(ptrn ,”g”), dictionary[ptrn] ) ); } }); solved Use jQuery to find and replace multiple words on the page [duplicate]
Based on your update on what bid_data contains: Do: int(bid_data[6].split(‘:’)[1].strip()) # returns an integer Explanation: The Python string method strip() removes excess whitespace from both ends of a string (without arguments) Original below: Below is based on using the input you gave, [‘Quantity Required’, ‘ 1’], to get the output of 1 If the input … Read more
Running sed -i on the same file multiple times is a horrible antipattern. Just do all the substitutions in the same sed script. You need to escape many more metacharacters than you currently do. See Escape a string for a sed replace pattern for some details. Probably that’s the reason many of your substitutions don’t … Read more
You can do that by passing an array as first argument: $res = str_replace(array(‘ ‘, ‘-‘, ‘,’), ”, $str); You can test it here at phpfiddle.org. str_replace() PHP’s function let you choose if the three parameters will be a single value or an array. 0 solved How can I use an array in str_replace() function?
Simple. Iterate over all strings inside List and then check if myString contains that or not. If yes, then replace it. foreach (string item in lst) { if (myString.Contains(item)) { myString = myString.Replace(item, string.Format(“$${0}$$”, item)); } } Also you can do same with LINQ: lst.Where(item=> myString.Contains(item)).ToList() .ForEach(item => myString = myString.Replace(item, string.Format(“$${0}$$”, item))); You can … Read more
Use replace() of String example to demonstrate using String.replace(), and this does not cover your entire Story! public class Test { public static void main(String[] args) { String story = “Hello, I am strHost and I will be accompanied today by strHost1 and strHost2. As we walk through the mansion today, feel free to ask … Read more
Ok I figured it out. It was kind of dumb. I am creating the JS in a string in Perl, and I neglected to escape the \ in the regex. It should have been: oldname.replace(/\\d+/, index); Simply because it was in a heredoc. solved jQuery-UI Sortable and string replace issue [closed]
if you alltime wants to show 1st and last 3 letters and in between some * than you can do it by sub-string and string concat method $str = “hello this is my password”; echo substr($str,0,3).”******”.substr($str,(strlen($str))-3,3); 1 solved How can I hide/replace a part of a string in PHP? [duplicate]
You should not redeclare the variable twice but only modify its value: for (int i = 0; i < Model.Items.Count; i++) { string SelectedEvent = “event selected”; if (i > 1) { SelectedEvent = “event”; } // here you can use the SelectedEventVariable // its value will be “event selected” on the first and second … Read more