[ad_1] string oldValue= “iif([PricingTKt_US]>0,1-([F221-B01]/iif([PricingTKt_US]=0,1, [PricingTKt_US])),0)”; PricingTKt_US Capital K. oldValue=oldValue.Replace(“[PricingTkt_US]”,”[F123]”) PricingTkt_US Small k [ad_2] solved C# String Replacement not working [closed]
[ad_1] Try library(sp) S@coords[,’roadtype’][S@coords[,’jointcount’]!=1] <- NA S # SpatialPoints: # jointcount roadtype #[1,] 1 3 #[2,] 4 NA #[3,] 3 NA #[4,] 1 1 #[5,] 1 4 data jointcount = c(1,4,3,1,1) roadtype = c(3,2,5,1,4) S <- SpatialPoints(data.frame(jointcount,roadtype)) [ad_2] solved Replace Values in a column wiht NA if values from another column are not 1 [closed]
[ad_1] Based on the conditions you mentioned you can do something like below. Find the word count and then check is home available in the string and then find the index of the house . So then you can check does that index match to last index of the word array (count($wordArray)) – 1) $string1 … Read more
[ad_1] import os parent_folder_path=”somepath/parent_folder” for eachFile in os.listdir(parent_folder_path): if eachFile.endswith(‘.xml’): newfilePath = parent_folder_path+”https://stackoverflow.com/”+eachFile file = open(newfilePath, ‘r’) xml = file.read() file.close() xml = xml.replace(‘thing to replace’, ‘with content’) file = open(newfilePath, ‘w’) file.write(str(xml)) file.close() Hope this is what you are looking for. 3 [ad_2] solved multiple search and replace in python
[ad_1] This regex String a = “Want to Start (A) Programming and (B) Designing”; String b = a.replaceAll(“\\(“, “\n\\(“); System.out.println(b); results in Want to Start (A) Programming and (B) Designing Just escape the brackets with \\ and you’re fine. Edit: more specific, like mentioned below a.replaceAll(“(\\([AB]\\))”, “\n$1”); to match only (A) and (B) or a.replaceAll(“(\\(\\w\\))”, … Read more
[ad_1] [*] Provisos and assumptions: OP mentions needing to process multiple files; for this answer I’m going to focus on a single file; OP can start another question if issues arise with a multi-file solution OP mentions wanting to replace some strings but it’s not clear (to me) if the original file is to be … Read more
[ad_1] Make sure to use replaceAll(). Also you could put all of the terms and replacements in an array. Like so: String text = “ALTER DATABASE, ALTER TABLE, ALTER VIEW, CREATE DATABASE, CREATE PROCEDURE, CREATE SCHEMA, CREATE TABLE”; String[] terms = {ALTER DATABASE, ALTER TABLE, ALTER VIEW, CREATE DATABASE, CREATE PROCEDURE, CREATE SCHEMA, CREATE TABLE}; … Read more
[ad_1] try this return new FaultEntity() { Nr = token[0]==”0″?” “:token[0], … }; for an integer value int data = 10102; string st = data.ToString(); var con = st.Replace(‘0’, ‘ ‘); 5 [ad_2] solved C# How to replace 0 (zero) with space
[ad_1] var ele = $(“div.description”); //Let ele be target element ele.html(ele.html().replace(/smile/gi,”think”)); //Replace the word in string, // then put it back in. .replace: MDN Demo: http://jsfiddle.net/DerekL/FdyEH/ 0 [ad_2] solved Search Text and Replace with JavaScript
[ad_1] Note: \ is escape character in objective c. NSString *s = @”This is Testing Mode and we are testing just Details of this Ladies’ Market place”; NSString *r = [s stringByReplacingOccurrencesOfString:@”‘” withString:@”\\'”]; 0 [ad_2] solved Replace occurrences of NSString with `’` to `\’`
[ad_1] Use this: String replaced = yourString.replaceAll(“[^\\w\\xAE\\xA9~. -]”, “_”); In Java, \w matches all ASCII letters, numbers and underscore A9 and AE are the hex codes for copyright and registered trademark 1 [ad_2] solved Java String replace Regular Expression
[ad_1] mutate is used to operate on data column-wise. If you want to do this rowwise one way in base R would be to use apply with margin as 1. gapFill_data <- data gapFill_data[] <- t(apply(data, 1, function(x) replace(x, x == 0, min(x[x > 0], na.rm = TRUE)))) gapFill_data # a b c d #1 … Read more
[ad_1] Your pattern matches multiple positions. One before a character (including a character) and one right after. You can test it here. If you include a start string ancor it will work to match anything (even empty strings) and replace with Test ^.* [ad_2] solved Replace every value in a pandas dataframe series [duplicate]
[ad_1] You should assign result of replacement: var res = variable. Replace(“\\”, “https://stackoverflow.com/”); // you need “\\” because “\” is escape symbol. or var res = variable.Replace(@”\”, “https://stackoverflow.com/”); 3 [ad_2] solved Replace all blackslashes with forward slash [duplicate]
[ad_1] Using Python 3: import argparse from sys import exit from os.path import getsize # collect command line arguments parser = argparse.ArgumentParser() parser.add_argument(‘-p’, ‘–parameter’, required=True, type=str) parser.add_argument(‘-f’, ‘–file’, required=True, type=str) args = parser.parse_args() # check if file is empty if getsize(args.file) == 0: print(‘Error: %s is empty’ % args.file) exit(1) # collect all lines first … Read more