simple using replaceAll() using ^\\d+|\\d+$ regex that looks for digits in the beginning and ending of the line. System.out.println(“1adfds23dfdsf121”.replaceAll(“^\\d+|\\d+$”, “”)); output: adfds23dfdsf EDIT Regex explanation: ^ Start of line \d+ Any digit (one or more times) | OR \d+ Any digit (one or more times) $ End of line 3 solved How to remove numbers … Read more
This one should be the way: #(\w+)(?:[, .]|$) # matches # literally \w is a word with at least one letter (?:) is non-capturing group [, .]|$ is set of ending characters including the end of line $ For more information check out Regex101. In Java don’t forget to escape with double \\: String str … Read more
You may wonder how it works. I’ll try to explain how it should be done by various methods. We’ll start first with how regex works and how it is used. Regex – Regular expression In computing, a regular expression (abbreviated regex or regexp) is a sequence of characters that forms a search pattern, mainly for … Read more
Try: gsub(“^[^\\-]+\\-“, “”, “0266-VN22.5P-AC”) 10 solved Remove anything before first hypen [closed]
As Marty says, it all depends on which language you are using. You could do it in JavaScript, like so: var myString = “i have a example link:- https://www.google.co.in/search?q=web+service+urls&ie=utf-8&oe=utf-8&aq=t&rls=org.mozilla:en-US:official&client=firefox-a&channel=sb&gfe_rd=cr&ei=ex5iU-6CLMeW8QezvoCgAg i need a regex to extact that full url from text string. thanks!”; var myRegexp = /(http|ftp|https):\/\/[\w-]+(\.[\w-]+)+([\w.,@?^=%&:\/~+#-]*[\w@?^=%&\/~+#-])?/ var match = myRegexp.exec(myString); alert(match[0]); Here’s a demo I … Read more
Returning code from server is terrible awful. Anyways, this code I give you do some steps: removes new lines and multispaces into one length space from input. finds words by pattern where word starts with if and ends with digits. Adds them to array. prepares pattern with user chosen options combining into similar to (Q4a.NAOK==\”7\” … Read more
If, and only if, there are no nested <span>-tags, you can search for /(<span\b[^>]*>[\s\S]*?<\/span>)|(\b(?:foo|bar)(?:\s+(?:foo|bar))*)/g and replace it with the function function matchEvaluator(_, span, word) { if (span) return span; return ‘<span class=”widget”>’ + word + ‘</span>’; } the part (<span\b[^>]*>[\s\S]*?<\/span>) searches for the span element. That’s the part, where no nested <span>-element is allowed. The … Read more
by using preg_split: $str=”This is some string <select> this is another string <select var1> another string which can contain special characters <select var2> another variable string <select var1,var2>”; $arr = preg_split(‘/\<.*?\>/’,$str); print_r($arr); solved PHP RegEx pattern for repeating within the string [duplicate]
You could use replaceAll to do the job without regex : val name: String = “cust_id” val newName: String = name.replaceAll(“_”,” “) println(newName) solved Scala: How to replace all consecutive underscore with a single space?
Basic regular expression /^[+-]\d+\.\d+$/ Explanation: ^ Match start of string [+-] Match either plus or minus \d+ Match one or more numbers of digits \. Match a period, the \ escapes it since it means any character \d+ Match one or more numbers of digits $ Match end of string 1 solved JavaScript – Regular … Read more
(\S+)\.| will match and capture any number (one or more) of non-space characters, followed by a dot character. (\S+) | will match and capture any number (one or more) of non-space characters, followed by a space character (assuming the regular expression isn’t modified with a /x flag). In both cases, these constructs appear to be … Read more
Use the replace menu by pressing Ctrl+H, and make sure regular expressions are enabled. Then, Find (^.*\/).* and Replace $1: https://regex101.com/r/lJ4lF9/12 Alternatively, Find (?m)(^.*\/).* and Replace $1: https://regex101.com/r/lJ4lF9/13 Explanation: Within a capture group, Find the start of the string (^) followed by anything any number of times (.*) until the last “https://stackoverflow.com/”, then anything any … Read more
To split on any whitespace (including newlines), you’d use /\s/ with split: var theArray = theString.split(/\s+/); \s means “spaces” (e.g., whitespace — including newlines), and + means “one or more“. To trim whitespace from the beginning and end of the string first, on any modern browser you can use String#trim: var theArray = theString.trim().split(/\s+/); If you … Read more
^(\d{5})\D{0,3}(\d{4})$ remove the second ^.See demo. https://regex101.com/r/hV6rA2/3 0 solved Why does this regex not match as expect?
Here’s a different approach that handles nulls and does not risk altering any data. It uses a with clause to break down the data by the delimiters, ending up with splitting on the commas. ASSUMPTION: Steps have already been taken to ensure that the data has already been scrubbed of the delimiter characters (commas and … Read more