Using the built-in csv library to iterate over each row’s values will do the trick: import csv with open(‘data.csv’) as csvfile: csvin = csv.DictReader(csvfile) for row in csvin: if row[‘col2:’] == “true” and row[‘col3:’] == “false”: print(row[‘col1:’]) Output result: 1 0 solved How can i read a csv based on data in other columns? [closed]
random.shuffle is your friend, according to the docs random.shuffle(x[, random]) . Shuffle the sequence x in place. import random #Convert string to list of chars li = list(‘ABDEB’) for i in range(5): #Shuffle the list, the last shuffled list is shuffled every time random.shuffle(li) #Convert list to string again and print print(”.join(li)) Output might look … Read more
Is this what you are looking for? b = [[j for i in a for j in i]] 1 solved Lists in Python – Each array in different row [duplicate]
Probably the closest short of looping and building a string, is something using pprint.pformat, such as: >>> from pprint import pformat >>> my_dct = dict( k1=1, k3=3, k2=2,) >>> print(‘my_dct = {{\n {}\n}}’.format(pformat(my_dct, width=1)[1:-1])) my_dct = { ‘k1’: 1, ‘k2’: 2, ‘k3’: 3 } solved write() file by inserting dict in specific key order and … Read more
You miss the lines if grade != -1: numbers.append(grade) after grade = int(grade). This adds the grade to the list numbers. Review Use PEP8 (you can use pep8online.com) to check your code For unnamed input, I prefer “Largest is %i, smallest is %i” % (max(numbers), min(numbers)) You can use sum to sum up integers in … Read more
You can get the last two digits using the remainder operator, then use the digits as key of sorted: a = [311, 409, 305, 104, 301, 204, 101, 306, 313, 202, 303, 410, 401, 105, 407, 408] result = sorted(a, key=lambda x: (x % 100, x)) print(result) Output [101, 301, 401, 202, 303, 104, 204, … Read more
Hey bud I only have so much time a day to spend on this but I worked out a little better framwework for you to play with, try using elements in here working with it and modifying it, the skeleton of it should help you get all your goals accomplished with this certain code. I’ll … Read more
There is no error but nothing is printed, but if I print inside the while loop then it is printed multiple times. How do I fix this? [closed] solved There is no error but nothing is printed, but if I print inside the while loop then it is printed multiple times. How do I fix … Read more
It sounds like you mean this. Some kind of iterative function closing in on a value? #!/usr/bin/env python3 c = 1 d = 1 b = 1 while True: a = 3 * b + c new_b = (a – d) / 5 if b – new_b <= 0.25: break b = new_b print(a, new_b) … Read more
As for your firs question: yes one can make a Python program without using classes or functions at all: all satements are executed in theorder they are encountered 2) you certainly are mixing some concepts there, but generally “yes” – one could stop a loop running in another method if running in parallell to that … Read more
that’s because the self variable has to be explicitely given to methods in python. As you write it, are you expecting python to read your mind so it guesses that self shall be something from a class your function is not related at all with? So to have it bound you need: add self to … Read more
You should init hours_result outside of the outer for loop, here it’s set to [] for each med. 0 solved Creating multidimensional list of medicine dosage times [closed]
You almost certainly want to replace your specific variables for each nation with a data structure (such as a dictionary) that uses the nation’s name as a key. So, rather than referring to USA_REGION_DATA you’d look up REGION_DATA[“USA”]. This is extensible to any number of nations, as you can simply add new values to the … Read more
Try using the “step size” argument to range or xrange: fd = open(dFile) lineas = fd.readlines() fd.close() for i in xrange(0, len(lineas), 6): print “CA:”+lineas[i]+”Q:”+lineas[i+1]+”A1:”+lineas[i+2]+”A2:”+lineas[i+3]+”A3:”+lineas[i+4]+”A4:”+lineas[i+5]; 0 solved How can I increase the i in a for?
You can nest zips: studentName = [“kelly”,”Micheal”,”Agatha”,”Chris”,”frank”,”matthew”] subject = [“math”,”phy”,”chem”] math = [34,45,78,79,60,36] phy = [57,98,67,90,56,60] chem = [67,86,35,98,50,67] output = {name: dict(zip(subject, scores)) for name, scores in zip(studentName, zip(math, phy, chem))} print(output) # {‘kelly’: {‘math’: 34, ‘phy’: 57, ‘chem’: 67}, # ‘Micheal’: {‘math’: 45, ‘phy’: 98, ‘chem’: 86}, # ‘Agatha’: {‘math’: 78, ‘phy’: 67, … Read more