[ad_1] so you only need op. in a GUI window instead of console ? create a window ,add a label and button using tkinter(basic GUI programming). basic tutorial for GUI prog. l = Label(root, textvariable = var) var will be from your backend code 2 [ad_2] solved How to put output of python code in … Read more
[ad_1] As it has been answered in Adam Rosenfield’s solution a while ago you may try to use an algoritm similar to this one below: int i; do { i = 5 * (rand5() – 1) + rand5(); // i is now uniformly random between 1 and 25 } while(i > 21); // i is … Read more
[ad_1] Just check if each line contains the text you are looking for. # Assuming the input file is called “input.txt” with open(‘input.txt’, ‘r’) as fin: # Read all the lines buff = iter(fin.readlines()) # For the output file do the following with open(‘output.txt’, ‘w’) as fout: # Iterate over every line for line in … Read more
[ad_1] Try this.. list1.append((i for i in list2 if not i in list1).next()) 0 [ad_2] solved compare two lists of strings and remove duplicates python
[ad_1] What’s wrong with creating an instance of the class and throwing it in a list? entity_list = [] for i in range(10000000): entity_list.append(Entity()) [ad_2] solved Pygame, spawning an infinite number of enemies? [closed]
[ad_1] You can get all of the indices whose value is x using a list comprehension: indices = [i for i, elem in enumerate(word) if elem == x] So you would have: >>> word = [“p”, “y”, “t”, “h”, “o”, “n”] status = [“_”, “_”, “_”, “_”, “_”, “_”] >>> >>> word [‘p’, ‘y’, ‘t’, … Read more
[ad_1] Found the issue, the problem was that because i was using extract() its output is a list, so i had a list within a list ( with only one element ) and the request wasn’t calling the url, changed it to a extract_first() and now it works. HierarchyItem[“hierarchy_url”] = lvl3.css(“a::attr(href)”).extract_first() [ad_2] solved Scrapy crawler … Read more
[ad_1] Your imports didn’t work that well over here, but that might be a configuration issue on my side. I think the scraper below does what you’re searching for: import scrapy class YelpSpider(scrapy.Spider): name=”yelp_spider” allowed_domains=[“yelp.com”] headers=[‘venuename’,’services’,’address’,’phone’,’location’] def __init__(self): self.start_urls = [‘https://www.yelp.com/search?find_desc=&find_loc=Springfield%2C+IL&ns=1’] def start_requests(self): requests = [] for item in self.start_urls: requests.append(scrapy.Request(url=item, headers={‘Referer’:’http://www.google.com/’})) return requests def … Read more
[ad_1] sum([i ** 2 for i in range(initial, initial + terms)]) or sum(map(lambda x: x ** 2, range(initial, initial + terms))) both will work as the same way. 2 [ad_2] solved Python for in range()
[ad_1] element is an index, not an element from myList. I would rename your current element variable to something like index and then add element = myList[index] at the top of your while loop: def splitList2(myList, option): nList = [] index = 0 while index < len(myList): element = myList[index] if option == 0: if … Read more
[ad_1] Make sure your code is exactly as it is now in the question (including the edit by @Haidro) The code, as you pasted it in the question, suggests your indentation was something like this: def my_function(): ”’ docstring ”’ code_intended_for_my_function() #my_function() This would cause code_intended_for_my_function to be executed. This is “valid” because the docstring … Read more
[ad_1] May be you want this: import re def rna_strand_count(test_string,sub_string): test_string = test_string.replace(‘ ‘,”).upper() sub_string = sub_string.replace(‘ ‘,”).upper() first = sub_string[0] second = sub_string[1:] return {sub_string:len(re.findall(r'{0}(?={1})’.format(first,second),test_string))} print rna_strand_count(‘AAAA’,’AA’) 1 [ad_2] solved How to create a strand count? [closed]
[ad_1] I found a method Tix.Checklist.close(entrypath) which is already included in the Module. [ad_2] solved Tix Checklist Python 2.7
[ad_1] Python’s sort() has the optional argument key. You can use a lambda function as the key like so: numbers = [1, 9, 35, 12, 13, 21, 10] numbers.sort(key=lambda i: i % 5) print(numbers) A quick explanation of what’s going on here: A lambda function is a function that is defined in-line and isn’t named. … Read more
[ad_1] Should be just: print ‘\n’.join([str(factorial(x)) for x in range(0, 6)]) 1 [ad_2] solved Printing every item on a new line in Python [duplicate]