This is basically the same as x = 42 print(x) print(x) print(x) A variables value only changes when you assign it: x = 42 print(x) x = 45 print(x) If you want a new random value, you need to call the function again: l = [1, 2, 3, 4, 5] x = random.choice(l) print(x) x … Read more
I suggest you use the method: imgstring.replace(“\n”, ” “) Alternatively, if you know inbetween which words you want to remove the Newline, you can use regular expressions to find your place where to replace the newline. A third way of doing this: You can turn the string into a list like so: thisisanexample = “Hello … Read more
You iterate over the list by using for elem in testList, which yields elements of the list and not their indices. >>> b = [1, 3, -4, 5, 5, 3, 2, 1, 4, 8, 9] >>> for i in b: print i, 1 3 -4 5 5 3 2 1 4 8 9 # Whereas … Read more
Prebuilt wheels of PyAudio are currently available for Python 2.7 and 3.4-3.6. If you don’t want to use Python 3.6 and want to install PyAudio in 3.7 you have to compile and install PortAudio and PyAudio from sources. See the instructions at http://portaudio.com/docs/v19-doxydocs/tutorial_start.html https://smaudet.wordpress.com/2014/01/26/building-pyaudio-on-windows-7-x64-using-the-free-msvc-toolchains/ solved pip install pyaudio error cl.exe failed
It would work by putting players into a dict: class Character(object): def __init__(self): self.NAME = ” self.life = 50 players = [“red”,”green”,”blue”,”yellow”] dict_players = {} for player in players: dict_players[player] = Character() However, printing would only work if you create a __str__ method for your class. solved How to use element of list as object … Read more
This is because you scrape it manually, the page shows the first 20 members and loads (by the use of a AJAX call) more members dynamically if you scroll down. This behaviour does not happen when you perform a http request in python. As Arkanosis and Odi already suggested, use the Twitter API to make … Read more
print(result(20,20)) this only prints the result of 20+20 and does not save the result of the op into “result”, “result” is the name of the function. if you want to save the return value, answer = result(20,20) print answer if answer == 40: print (“we made it”) else: print (“Nooope”) take note that print result … Read more
If your addresses are always on the end of a line, then anchor on that: ip_at_end = re.compile(r'(?:[0-9]{1,3}\.){3}[0-9]{1,3}$’, re.MULTILINE) This regular expression only matches dotted quads (4 sets of digits with dots in between) at the end of a line. Demo: >>> import re >>> ip_at_end = re.compile(r'(?:[0-9]{1,3}\.){3}[0-9]{1,3}$’, re.MULTILINE) >>> example=””‘\ … Only addresses on … Read more
def input_guess(guess): …. if guess_num == real_num: print ‘Congratulations, blablabla!’ new_game() else: print ‘You guessed: ‘, guess_num,’.’, print ‘You have’, remainding_guess_times, ‘guesses left.’, if guess_num > real_num: print ‘blablabla’ else: print ‘blablabla’ solved Python – print in an if,elif, else statement
Assuming you don’t care what the file names are, you could write each batch of messages to a new temp file, thus: import tempfile texts = some_function_grabbing_text() while texts: with tempfile.TemporaryFile() as fp: fp.write(texts) texts = some_function_grabbing_text() solved How to save data in multiple files on python
Why not use a dictionary for that? This way you could add and remove values in/from your dictionary just as you wanted. my_dict = { ‘var1’: 0, ‘var2’: 0, … } You can delete by doing my_dict.pop(‘var1’) if you need the value back or del my_dict[‘var1’] otherwise and add items with my_dict[‘var3’] = 0. 2 … Read more
since you just want code it sounds like from operator import itemgetter sorted(map(itemgetter(1,-1),lists),key=itemgetter(-1)) heres some code that should do what you want … a teacher may want an explanation however… just fair warning solved Python: Sorting and printing lists within lists [closed]
You can use itertools.groupby for this: >>> s = “aaaXXXbbbXXXcccXdddXXXXXeXf” >>> import itertools >>> sum(e == ‘X’ for e, g in itertools.groupby(s)) 5 This groups the elements in the iterable — if no key-function is given, it just groups equal elements. Then, you just use sum to count the elements where the key is ‘X’. … Read more
Use the Counter. from collections import Counter A = [[1,2], [2,1], [3,1], [1,2]] print Counter(tuple(i) for i in A) >>> Counter({(1, 2): 2, (3, 1): 1, (2, 1): 1}) 1 solved Getting a count of list elements [closed]
This somewhat depends on the context, but it effectively means “the element of the variable ‘filename’ at the fourth position from the end.” So, if filename is a string with the value of ‘Test string.’ then filename[-4] will be ‘i’. In this particular case, the expression would evaluate to False, because “i” is not “B”. … Read more