I don’t know exactly what you were going for, but this should fix most of it: print(‘You have ‘ + turns + ‘ more guesses’) no need to use str for stuff like this and don’t use + outside the parenthesis of print() This assumes your turns variable is a string, but if it is … Read more
shouldn’t it be something like this? import urllib import argparse def download_web_image(url): IMAGE = url.rsplit(“https://stackoverflow.com/”,1)[1] urllib.urlretrieve(url, IMAGE) parser = argparse.ArgumentParser() parser.add_argument(“num1”) parser.add_argument(“num2”) parser.add_argument(“num3”) args = parser.parse_args() num3 = args.num3 if not num3: for num3 in range(01,50): download_web_image(“https://www.example.com/{num1}/{num2}/{num3}.jpg”.format(num1=args.num1, num2=args.num2, num3=num3)) else: download_web_image(“https://www.example.com/{num1}/{num2}/{num3}.jpg”.format(num1=args.num1, num2=args.num2, num3=num3)) your complete code is (sorry) a mess.. first you have to define … Read more
a = range(1,20) Your program is creating a range of numbers between 1 and 19 (ranges go to one less than the max number you specify) like [1, 2, 3, 4, …, 19] total = 0 Your program is initializing the variable total to equal 0 for i in a: You start looping through the … Read more
Can you try the following: req_keys = [‘col1’, ‘col2’, ‘col3’, ‘col4’] all_list = [incoming[i] for i in req_keys] all_list = [i for i in all_list if i] print(‘1’.join(all_list)) Example: incoming = {} incoming[‘col1’] = ‘a’ incoming[‘col2’] = None incoming[‘col3’] = ‘c’ incoming[‘col4’] = None Output: a1c Another Example: incoming = {} incoming[‘col1’] = ‘a’ incoming[‘col2’] … Read more
So the thing is, Python does not have the same ternary operator. condition?true:false => true if condition else false To implement the line: return(isalpha(ch) ? accvs[ch & 30] : 20) in python, you have to do the following: return (accvs[ord(ch) & 30] if ch.isalpha() else ’20’) solved Trying to change or interpret the C code … Read more
Try this one with the help of regex. In [105]: import re In [106]: m = re.findall(‘\${(.+?)}’, string) In [107]: m Out[107]: [‘data1’, ‘data2’, ‘data3’] 7 solved Pattern matching and extracting it in the string occurrences
Dedent the last line, start(). The interpreter runs the upper level of the script, but the indentation makes that line part of the function score(). 1 solved Rock Paper Scissor Python [closed]
I’ll give you a hint since this looks like a h/w assignment. if you check the graphics you posted, for computing (n)th number you’re just adding a new row to the (n-1)th figure at the bottom with n new dots. starting with 1 -> 1 2 -> 1+2 = 3 3 -> 3+3 = 6 … Read more
count was defined as a string. Is this what you wanted def concat_list(string): count = “” for i in string: count += i return count or you can use def concat_list(string) return ”.join(string) 3 solved Concatenating items in a list? [duplicate]
You can use the on_message event to catch every message and do what you like with it. This is better than waiting for a message and executing code as this is faster. The downside is the channel must be hard-coded or use a global variable. Or, you could recreate the whole command in the function … Read more
Check this out. List Comprehension import numpy as np import pandas as pd df = pd.read_csv(‘census.csv’) data = [‘SUMLEV’,’STNAME’, ‘CTYNAME’, ‘CENSUS2010POP’] df=df[data] adf = df[df[‘SUMLEV’]==50] adf.set_index(‘STNAME’, inplace=True) states = np.array(adf.index.unique()) vlist=[adf.loc[states[i]][‘CENSUS2010POP’].sort_values(ascending =False).head(3).sum() for i in range(0,7)] 3 solved how can I loop to get the list named vlist?
You can try one of the 2 alternatives below. df.groupby(‘country’)[‘edition’].nunique().gt(1).sum() or (df.groupby(‘country’)[‘edition’].nunique()>(1)).sum() 1 solved how many countries have organised more than one edition of olympic games? using python pandas [closed]
From the str.find() method documentation: Return -1 if sub is not found. So the first if condition tests if string1 is found in x; if it is, a value other than -1 would be returned. The second if condition tests if two strings are not present in x (because only then -1 is returned for … Read more
In Python 3.2 and higher, representing a container with all integers from 1 to a million is correctly done with range: >>> positive_nums_to_1M = range(1, 1000001) >>> 1 in positive_nums_to_1M True >>> 1000000 in positive_nums_to_1M True >>> 0 in positive_nums_to_1M False It’s extremely efficient; the numbers in the range aren’t actually generated, instead the membership … Read more
from collections import OrderedDict cars = OrderedDict([(1, ‘Camaro’), (2, ‘SS Sedan’), (3, ‘M3 Sedan’), (4, ‘GLE Coupé’)]) print(‘Help Rick P. choose a car to drive.\n’) print(‘\n’.join([str(key) + ‘ ‘ + val for key, val in cars.items()]) + ‘\n’) def choice_car(invalid = False): if invalid: choice = int(input(‘Invalid car. Try again…\n’)) else: choice = int(input(‘Input the … Read more