The problem is that two instances of the variable X are created in such a set-up: one in a.py and another in b.py. The problem also occurs in this example that reduces it to the essence — it is not related to creating threads: Problem in most simple form File a.py: X = “original value” … Read more
With given format, you can use dateutil.parser.parse to handle it. Here’s some code: d = “2017-10-23T03:36:23.337+02:00” time = dateutil.parser.parse(d) print(time.strftime(“%d/%m/%y %H/%M/%S”)) The output is: 23/10/17 03/36/23 4 solved user friendly date format using python
Assuming the json data is stored in json_text in python, you can do import json json.loads(json_text).get(‘bpi’).get(‘USD’).get(‘rate’) If the data is critical for you, you should check for errors. Also, making the currency configurable might be a good idea. solved Extract and Display a Value from a JSON Array
A simple way is to simply print each string in the returned whois: host=”stackoverflow.com” whois = pythonwhois.net.get_whois_raw(host) for item in whois: print item This would output something like this: Domain Name: STACKOVERFLOW.COM Registrar WHOIS Server: whois.name.com Registrar URL: http://www.name.com Updated Date: 2014-05-09T17:51:17-06:00 Creation Date: 2003-12-26T19:18:07-07:00 Registrar Registration Expiration Date: 2015-12-26T19:18:07-07:00 Registrar: Name.com, Inc. Registrar IANA … Read more
Introduction Python is a powerful programming language that allows you to iterate over a list in a variety of ways. Iterating over a list is a common task in programming, and Python provides several methods for doing so. In this article, we will discuss how to iterate over a list in Python using various methods … Read more
This looks like a json object but doesn’t have [] around it to make it an actual list. You should be able to convert it into a Python native list of dictionaries and navigate it: import json recipe = json.loads(‘[‘ + your_text + ‘]’) steps = [obj[“text”] for obj in recipe if obj.get(“@type”) == “HowToStep”] … Read more
I figured it out. string = ‘123456789’ splitted = [] prev = 0 while True: n = random.randint(1,3) splitted.append(string[prev:prev+n]) prev = prev + n if prev >= len(string)-1: break print splitted 0 solved Split string by n when n is random
This article will discuss how to split a string by a random number. Splitting a string is a common task in programming, and it can be done in many different ways. However, when the number used to split the string is random, it can be a bit more challenging. This article will provide an overview … Read more
There are many different approaches to designing a suitable regular expression which depend on the range of possible inputs you are likely to encounter. The following would solve your exact question but could fail given different styled input. You need to provide more details, but this would be a start. re_content = re.search(“aid\: \”([0-9]*?)\”,\W*cmt_id = … Read more
Introduction If you are a newbie to Python and need help with regex, you have come to the right place. Regex (or regular expressions) is a powerful tool for manipulating text and can be used to search, edit, and manipulate text. This post will provide an introduction to regex and provide some helpful resources to … Read more