It’s more straightforward than you think: def getCardinalDirection(angle): directions = [‘↑ North’, ‘↗ North East’, ‘→ East’, ‘↘ South East’, ‘↓ South’, ‘↙ South West’, ‘← West’, ‘↖ North West’] return directions[round(angle / 45) % 8] # round() is a built-in function Example output: >>> getCardinalDirection(50) ‘↗ North East’ >>> getCardinalDirection(220) ‘↙ South West’ >>> … Read more
I think you should develop more on your fundamentals, and try out your own code before asking a question here. I guess what you are trying to achieve can be done like this. import json with open(“example.json”, “r”) as f: json_content = json.load(f) message = json_content[“message”] variable = “var” print(message.format(variable=variable)) # prints # this is … Read more
Because your On[-1] and tempList are the same object. And this is how it works with same objects: >>> x=[1,2,3] >>> y=x >>> y.append(10) >>> x [1, 2, 3, 10] >>> y [1, 2, 3, 10] >>> 4 solved Can Someone Explain What Just Happened (Python) [closed]
Don’t use regular expressions to parse HTML. Use BeautifulSoup >>> from BeautifulSoup import BeautifulSoup >>> ht=”<html><head><title>foo</title></head><body><p>whatever: <img src=”https://stackoverflow.com/questions/5878079/foo/img.png” height=”111″ width=”22″ /></p><ul><li><img src=”foo/img2.png” height=”32″ width=”44″ /></li></ul></body></html>” >>> soup = BeautifulSoup(ht) >>> soup <html><head><title>foo</title></head><body><p>whatever: <img src=”https://stackoverflow.com/questions/5878079/foo/img.png” height=”111″ width=”22″ /></p><ul><li><img src=”foo/img2.png” height=”32″ width=”44″ /></li></ul></body></html> >>> soup.findAll(‘img’) [<img src=”https://stackoverflow.com/questions/5878079/foo/img.png” height=”111″ width=”22″ />, <img src=”foo/img2.png” height=”32″ width=”44″ />] >>> for … Read more
You do it exactly the same way as with a curve. If you have a function with 3 parameters and fit it to three points, you’ll get an exact solution with the curve going through all 3 points (it boils down to solving 3 equations with 3 unknowns): import numpy as np from scipy.optimize import … Read more
This solution can handle all sorts of strings, not only numeric characters. s1 = ‘ABC0123091274723507156XYZ’ # without 8 s2 = ‘ABC0123091274723507156XYZ8′ len(set(“”.join(re.findall(r'([\d])’, s1)))) == 10 # False len(set(“”.join(re.findall(r'([\d])’, s2)))) == 10 # True How it works: Find all digits in the string with regex findall. Join all matches to one string and get unique characters … Read more
To change a global variable, you have to declare them global or they will be considered a local variable. Example: lives = 6 def change(): global lives lives = 0 1 solved How can you reset variables to their original value in python?
Try: dice = [1, 3, 4, 1] newval=”” for i in range(len(dice)): if dice[i] == 1: newval = dice[1:i] print(newval) 1 solved convert javascript to python : looping for in python [closed]
First, make two lists from your database. Something like: cursor = con.cursor() cursor.execute(“SELECT * FROM traffic”) #Retrieves data from SQL rows = cursor.fetchall() Month = list() Traffic = list() for row in rows: Month.append(row[‘Month’]) # guesswork – what does a row look like? Traffic.append(row[‘Traffic’]) Then, now you have two python lists, you can make a … Read more
>>> list1 = [‘1234′,’3456′,’2345′,’5543′,’1344′,’5679′,’6433′,’3243′,’0089’] >>> print(‘,’.join([“‘{0}'”.format(s) for s in list1])) ‘1234’,’3456′,’2345′,’5543′,’1344′,’5679′,’6433′,’3243′,’0089′ 1 solved Coverting a python list into string with comma separated in efficient way [closed]
As far as I can see your horizontal movement and collision detection work correctly. I enabled the vertical movement again and had to fix only a few things. Wall had to be changed to hits[0] and the y-velocity had to be set to 0 after touching a wall. def collide_with_walls(self, dir): if dir == ‘x’: … Read more
This is the simplest solution: list(zip(test2, test1)) 0 solved Python 3 – Printing the result of 2 lists [duplicate]
string.replace won’t work, since it does not affect the original value. >>> test = “hallo” >>> test.replace(“a”, ” “) ‘h llo’ >>> test ‘hallo’ Instead you need to access the list via the indexes: for row in ArrayMulti: for index in range(len(row)): row[index] = “a” If you provide a more precise question and add the … Read more
import itertools for acom in itertools.combinations(‘ABCD’,2): print acom 8 solved Set operations without using data type Set() [duplicate]
The row_string = “” in the outer loop creates a new, empty string every time the outer loop runs. So when the inner loop starts to run, the row_string is an empty string. Now each time the inner loop runs, something gets added (appended) to that empty string, namely the value of product casted into … Read more