If you want to use a range, then you need to call the function: for j in range(row): range is not part of the Python syntax, it is just another built-in object type. 1 solved Syntax error in a for loop in python [closed]
return print(char) This will first print the value of char (as in print(char)) and then try to return the return value of the print function. But since the print function always returns None—it only prints the value, it does not return it—your function will always return None causing the error when trying to concatenate None … Read more
I think you should be using name_choice here instead of name if name == “Sam”: print (“Your name is Sam”) What is the name variable meant for anyway? A good tip when something like this happens is to print the things you are comparing right before the if eg print (“name ==”, name) if name … Read more
You need to use named arguments to use their name in the template: “…{name}….”.format(name=name, quest=quest, color=color) If you use positional arguments, then you need to use index in template: “…{0}…”.format(name, quest, color) Documentation: https://docs.python.org/2/library/string.html#formatstrings solved KeyError in String Formatting of Raw Input
Multiple conditional statements in Python can be done as follows: if condition1: statement elif condition2: statement elif condition2: statement else: statement Or if you wanted nested conditional statements: if condition1: if condition2: if condition3: statement else: statement elif condition4: if condition5: statement else: statement (This is just one example of some nested conditional statements) 0 … Read more
There is only a very small error in your code, from what I can see. The last if statement, which includes your “Game Over” string, is indented incorrectly. Move it left one block: else: print “You missed my battleship!” board[guess_row][guess_col] = “X” if turn == 3: print “Game Over” # Print (turn + 1) here! … Read more
You can use the sorted function with the key parameter to look at the 2nd item, and reverse set to True to sort in descending order. >>> sorted(data_list, key = lambda i : i[1], reverse = True) [[‘Jimmy’, [8]], [‘Reece’, [8]], [‘Zerg’, [5]], [‘Bob’, [4]]] 2 solved How to sort this list by the highest … Read more
#!python2 # Epoch time needs to be converted to a human readable format. # Also, epoch time uses 10 digits, yours has 13, the last 3 are milliseconds import datetime, time epoch_time = 1520912901432 # truncate last 3 digits because they’re milliseconds epoch_time = str(epoch_time)[0: 10] # print timestamp without milliseconds print datetime.datetime.fromtimestamp(float(epoch_time)).strftime(‘%m/%d/%Y — %H:%M:%S’) … Read more
Python’s list probably already has everything you want. If you want some additional functionality like limiting max number of objects you should subclass it or wrap around it with another class. 1 solved Implementing stack in python by using lists as stacks [closed]
In python, when you import a library, it is expected to be utilized in the code blocks. Hence, as it obviously states, you may have imported these but have not used all of them. Besides that being the obvious warning, your imports should have been import numpy as np NOT bumpy. And remove the unnecessary … Read more
You can simply use the csv module from the standard library: import csv with open(‘__.csv’, ‘r’, newline=””) as f: reader = csv.reader(f) _ , *header = next(reader) d = {} for k, *row in reader: d[k] = dict(zip(header, row)) print(d) {‘reviews’: {‘JOURNAL_IMPACT_FACTOR’: 27.324, ‘IMPACT_FACTOR_LABEL’: ‘Highest’, ‘IMPACT_FACTOR_WEIGHT’: 37.62548387}, ‘hairdoos’: {‘JOURNAL_IMPACT_FACTOR’: 40.0, ‘IMPACT_FACTOR_LABEL’: ‘middle’, ‘IMPACT_FACTOR_WEIGHT’: 50.0}, ‘skidoos’: … Read more
Indentation is essential in Python; it replaces curly braces, semi-colons, etc. in C-like syntax. Consider this code snippet, for example: def f(x): if x == 0: print(“x is zero”) print(“where am i?”) If it weren’t for indentation, we would have no way of indicating what code block the second print statement belongs to. Is it … Read more
import csv # function to process data def process_data(data): for item in data: marks = int(item[2]) mclass=”incorrect data entry try again” if marks == 0: mclass = “10.9” elif marks >= 0 and marks <= 100: mclass = “10.{}”.format(10 – int(item[2][0])) yield ‘”{}”,”{}”,{},{}’.format(item[0],item[1],item[2],mclass) # read data to memory data = [] with open(“Maths_Mark.txt”, “r”) as … Read more
The fundamental issue is that you’re creating multiple JSON strings (json_data = (json.dumps(response, indent=2))) and then adding them to an array (json_arr.append(json_data)), and then converting that array to JSON (json.dump(json_arr,outline)). So the result is a JSON array of strings (containing JSON). You don’t want to create a string before adding to the array, just include … Read more
You can turn a string into code by using pythons eval function, but this is dangerous and generally considered bad style, See this: https://stackoverflow.com/a/661128/3838691. If user can input the string, they could input something like import subprocess; subprocess.check_call([‘rm’, ‘-rf’, ‘*’], shell=True). So be sure that you build in reasonable security into this. You can define … Read more