[ad_1] You need to pass argument to your constructor. s1 = Square(1) # will call Square.__init__(self, 1) s2 = Square(2) # will call Square.__init__(self, 2) It’s not a big problem. Update I rewrite your class: import math class Square(): def __init__(self, length): #return an instance of this class with ‘length’ as the default length. self.length … Read more
[ad_1] Just create lists: somelist = [p1, p2] You probably want to append those to another data structure initialized outside of your loop: somelargerlist = [] for presumed_loop_variable in presumed_loop_not_shown: p1 = … p2 = … somelist = [p1, p2] somelargerlist.append(somelist) 17 [ad_2] solved putting float numbers in lists [closed]
[ad_1] Yes, you can do this recursively, if all you have is lists and dictionaries, then that is pretty trivial. Test for the object type, and for containers, recurse: def unwrap_data(obj): if isinstance(obj, dict): if ‘data’ in obj: obj = obj[‘data’] return {key: unwrap_data(value) for key, value in obj.items()} if isinstance(obj, list): return [unwrap_data(value) for … Read more
[ad_1] Some of your lines in scores.txt don’t have a comma. You can check for those : if len(x) == 1 : #there is no comma continue #ignore line and go to the next one This code would ignore the lines without a comma. Place it just after computing x = line.split(‘,’) . Same if … Read more
[ad_1] You don’t want to use the function random.choice in your if statement. Save the random name as a variable and check it. import random random_choice = [‘Noob’, ‘Average’, ‘Pro’, ‘Expert’] name = input(‘What is your gamername? ‘) random_name = random.choice(random_choice) print(name, ‘is a’, random_name, ‘Gamer’) if random_name == ‘Noob’: print(‘Im afraid there is nothing … Read more
[ad_1] You missed a + symbol: regex = ‘<span id=”yfs_184_’+symbolslist[i]'”>(.+?)</span>’ ^ | here————————————— 2 [ad_2] solved there is an error in your program invalid syntax python 2.7.15
[ad_1] IDLE’s console does not support ANSI escape sequences, or any other form of escapes for coloring your output. You can learn how to talk to IDLE’s console directly instead of just treating it like normal stdout and printing to it (which is how it does things like color-coding your syntax), but that’s pretty complicated. … Read more
[ad_1] nested[1] and nested[2] have no effect whatsoever on the time taken to perform operations on nested[0]. An object has no knowledge of what containers it might be referenced in or what other objects might be in the container with it. List operations take the same amount of time regardless of what objects are being … Read more
[ad_1] Maybe you can consider using random.sample like so. >>> import random >>> p = 2*[‘a’] + 3*[‘b’] + 4*[‘c’] + 5*[‘d’] >>> random.sample(p, 3) [‘b’, ‘b’, ‘a’] From the docs, random.sample returns a k length list of unique elements chosen from the population sequence or set. It is used for random sampling without replacement. … Read more
[ad_1] from collections import defaultdict my_word=”apple” d = defaultdict(list) for a,b in zip(my_word,my_word[1:]): d[a].append(b) maybe?… collections.Counter might be usefull as well 0 [ad_2] solved Creating a dictionary based on a word [closed]
[ad_1] It’s not the correct one, it’s just one of many possible ways to edit your .py files and work on Python projects. There are many other IDEs around, and some developers just use their favorite text editors with Python plugins Unlike Mathematica, Maple and MATLAB, you’re not really bound to any particular development environment … Read more
[ad_1] This is a very weird way to handle data. I would use a nested dicts: exampleDictionary = {‘thing on ground’: {‘backpack’: {‘tea’: ‘Earl Grey’}}} print exampleDictionary[‘thing on ground’] print exampleDictionary[‘thing on ground’][‘backpack’] print exampleDictionary[‘thing on ground’][‘backpack’][‘tea’] Outputs: {‘backpack’: {‘tea’: ‘Earl Grey’}} {‘tea’: ‘Earl Grey’} Earl Grey 2 [ad_2] solved Python. Converting string into directory … Read more
[ad_1] Try this, >>> import datetime >>> datetime.datetime.now().strftime(‘%d-%m-%Y %H:%M:%S’) ’03-08-2019 12:43:16′ If you max_startdate is string, >>> max_startdate=”2019-08-03 01:08:58.155000″ >>> max_startdate.split(‘.’)[0] ‘2019-08-03 01:08:58’ 3 [ad_2] solved How i can convert ISO time format to yyyy-mm-dd hh:mm:ss using python [closed]
[ad_1] You can say: tax2 = int( input(“How Much Will You Tax Per Person In Dollars? “) ) If you’re sure the input won’t contain decimals. If you’re not sure, and want to keep the decimal value, you could use: tax2 = float( input(“How Much Will You Tax Per Person In Dollars? “) ) Or … Read more
[ad_1] This works: import re s=””‘customer is given as per below customer are given not priority below given given below customer below customer information given customer is given not as per below”’ matches = re.findall(‘customer \S+ given \S+\s\S+ below’, s) for match in matches: print(match) 14 [ad_2] solved Regular expression in python string [closed]