[ad_1] You can create a REST API in your Flask app and consume it with your React Native frontend. This also allows you to interact with your app from any frontend. 0 [ad_2] solved How to use SQLAlchemy Database with React Native?
[ad_1] Try: import random class player: def __init__(self, name): self.name = name self.score = random.randint(1,6) print(self.name, self.score) player_1 = player(“Richard”) player_2 = player(“Bob”) winner=”” if player_1.score > player_2.score: winner = player_1.score print(winner) elif player_2.score> player_1.score: winner = player_2.score print(winner) else: print(“Tie.”) Output: 7 [ad_2] solved Why does this code not output the winner variable?
[ad_1] while True: #@ 1 vowels = 0 #@ 2 consonants = 0 word = raw_input(“>>Enter a word: “).lower() #@ 3 if word != “stop”: #@ 4 for letter in word: #@5 if letter in [“a”, “e”, “i”, “o”, “u”]: vowels += 1 else: consonants += 1 print “Vowels: “, vowels print “Consonants: “, consonants … Read more
[ad_1] A little-known fact about the Python native pickle format is that you can happily concatenate them into a file. That is, simply open a file in append mode and pickle.dump() your dictionary into that file. If you want to be extra fancy, you could do something like timestamped files: def ingest_data(data_dict): filename=”%s.pickles” % date.strftime(‘%Y-%m-%d_%H’) … Read more
[ad_1] Your problem appears to be only with displaying the results. When selecting from a list, you can either select a certain index, e.g.: print movies_list[0] or a range, e.g.: print movies_list[0:3] print movies_list[3:-1] or you can print the entire list: print movies_list You can’t use commas in the square brackets for lists. [ad_2] solved … Read more
[ad_1] Answering this specifically would be difficult without knowing the specifics of your node implementation, and as this is almost certainly a homework problem wouldn’t be sporting anyway. What you want to do is go through each element of the list, and compare it to the Min you have. If it’s higher, then just go … Read more
[ad_1] You can do it with min and zip quite easy: l1 = [1,2,3,4,5,6] l2 = [10,20,5,8,30,25] l3 = zip(l2,l1) print(min(l3)) Output: (5, 3) Comment As mention in the comment by @sshashank124 it is important that the first list is the list you want to find the minimum. In this case it would be l2 … Read more
[ad_1] A simple way to do it is to iterate over the string, that will give you each letter separately: alphabet = “abcdefghijklmnopqrstuvwxyz” for letter in alphabet: print(“a” + letter) [ad_2] solved Adding first character of a string to each of the other characters [closed]
[ad_1] The first = in the second line is wrong. This should work: dict1[‘W’] = [‘Spring’] Note however that this way, you are setting dict1[‘W’] to a list containing ‘Spring’, not to the string “Spring” itself. [ad_2] solved Why python showing can’t assign to literal in dictionary? [closed]
[ad_1] .any(1) is the same as .any(axis=1), which means look row-wise instead of per column. With this sample dataframe: x1 x2 x3 0 1 1 0 1 0 0 0 2 1 0 0 See the different outcomes: import pandas as pd df = pd.read_csv(‘bool.csv’) print(df.any()) >>> x1 True x2 True x3 False dtype: bool … Read more
[ad_1] It seems like you need to instantiate AgentCOne before calling c_bar on it because c_bar is not a static method (and will take the first argument as self). c = AgentCOne.c_bar(alpha, beta, delta) # should be c = AgentCOne().c_bar(alpha, beta, delta) [ad_2] solved How can I prevent self from eating one of my test … Read more
[ad_1] yes months = range(1, 13) if it’s python3 then: months = list(range(1,13)) [ad_2] solved Append a range of numbers in a List in Python, as 1 Line of Code
[ad_1] Doing it the first way severely hampers the re-usability of your function. Simple Example: What if I wanted to see the outcome from of your function when y=3 when x is any of the numbers in [2, 4, 6]? With the first example, you’d need: def f(): return x + y results=[] y = … Read more
[ad_1] Yes you can do that but it would be better if you make the Males and Females into different classes and just inherit from the Human class. class Human: def __init__(self, height, weight): self.height = height self.weight = weight class Male(Human): def __init__(self, name): Human.__init__(self, height, weight) # This will inherit every attribute of … Read more
[ad_1] The only thing I could think of was to iterate over all polygons, and then loop over all the other polygons to find intersections. (Which means the algorithm has a quadratic run time complexity.) Inefficient, but it gets the job done. result = [] for i, shape in enumerate(polys): intersected_shapes = [poly for poly … Read more