Yes you can. This question is a duplicate to Is it possible to show an One2many field in a kanban view in Odoo? but here is a link to a module from Serpent Consulting which will be able to do what you are looking for. https://apps.openerp.com/apps/modules/8.0/web_one2many_kanban/ Here is a little more info. <kanban> <field name=”one2manyFieldname”/> … Read more
How to write a python program that takes a number from the users and prints the divisors of that number and then print how many divisors were there? [closed] solved How to write a python program that takes a number from the users and prints the divisors of that number and then print how many … Read more
Yes, I agree that Beautiful Soup is a good approach. Here is some Python code which uses the Beautiful Soup library to extract the intraday price from the IVV fund page: import requests from bs4 import BeautifulSoup r = requests.get(“https://www.marketwatch.com/investing/fund/ivv”) html = r.text soup = BeautifulSoup(html, “html.parser”) if soup.h1.string == “Pardon Our Interruption…”: print(“They detected … Read more
= is an assignment statement, you appear to be confusing this with a ==, the equality comparison operator. The statements are entirely different: self.name = name assigns the value referenced by the local variable name to the attribute name on the object referenced by self. It sets an attribute on the newly created instance, from … Read more
Convert back and forth between strings and ints, make use of sum(). >>> def foo(n): n = str(n) if len(n) == 1: return int(n) return foo(sum(int(c) for c in n)) >>> foo(1969) 7 >>> def foo(n): n = str(n) if len(n) == 1: return int(n) return foo(sum(int(c) for c in n)) 2 solved RECURSIVE function … Read more
all you need to do is on the line output_file = open(file_name+”.ecg”, “w”) replace it with output_file = open(args.new_filename, ‘w’) solved Allow User to Name New File [closed]
Would this help? totalReTries = 10 acquiredValue = None PROMPT_MESSAGE = “Please enter the valid value: ” typeOfInteredData = float rangeOfData = range(10, 20) for currentRetry in range(1, totalReTries): print “Attempt %d of %d” % (currentRetry, totalReTries) try: acquiredValue = input(PROMPT_MESSAGE) except ValueError: print(“Incorrect data format. Please try again.”) continue if type(acquiredValue) != typeOfInteredData: print … Read more
You can append all the values at the second place (number b) in a list for a particular group (say, 789). Then just iterate over the list using nested loops and you can get all the moves you want. Hope this is what you want. Code: for i in range(1,118): for j in range(1,118): count=0 … Read more
I feel like we’ve given the search for pre-existing solutions its due diligence. Given that “<=” is assignment in some languages (e.g., Verilog) we can quite intuitively introduce: value_struct_instance<<=’field’, value as the Pythonic form of value_struct_instance.field = value Here is an updated example for instructive purposes: # Python doesn’t support copy-on-assignment, so we must use … Read more
Your item =…. line, as it stands, just associates a new object with the name item in the function’s namespace. There is no reason why this operation would change the content of the list object from which the previous value of item was extracted. Here is a listing that changes a list in-place: import random … Read more
Well the loop seems to be this one (at the end of the code): for i,j in itertools.combinations([a,b,c],2): all_diffs=alldiffs(i,j) total=count_total(i,j) zero=count_zero(all_diffs) total=np.array(total) union=map(sub,total,zero) zero=np.array(zero).tolist() union=np.array(union).tolist() union=[list(x) for x in union] sim=[[float(aaa) / bbb for (aaa, bbb) in itertools.izip(aa, bb)] \ for (aa, bb) in itertools.izip(zero, union)] sim_comb=sum(sim,[]) sum_of_sim=sum(sim_comb) number_sum=len(sim_comb) ave=sum_of_sim/number_sum one_ave=1-ave print one_ave One possible … Read more
Try this: If you want cvs file then you finish the line print(df) and use df.to_csv(“prod.csv”) I have written in code to get csv file import requests from bs4 import BeautifulSoup import pandas as pd headers = {‘User-Agent’: ‘Mozilla/5.0’} temp=[] for page in range(1, 20): response = requests.get(“https://www.avbuyer.com/aircraft/private-jets/page-{page}”.format(page=page),headers=headers,) soup = BeautifulSoup(response.content, ‘html.parser’) postings = soup.find_all(‘div’, … Read more
You have to enumerate your array to change the value at a specific index. for i, row in enumerate(arr2): for j, cell in enumerate(row): if cell == ‘#’: arr2[i][j] = ‘A’ 0 solved How do I replace a specific string in a 2d array?
Well, comparing your methods, it became obvious your final operation for calculating pi was incorrect. Replace pi = (val + x) * (four/(long double)n); with these two lines: val = val * (long double)2.0; pi = (val + x) * ((long double)2.0/(long double)n); Compiling and running gives: 3.14159265241 Which I believe is the output you’re … Read more
I would take a dynamic-programming approach: def fewest_items_closest_sum_with_repetition(items, goal): “”” Given an array of items where each item is 0 < item <= goal and each item can be used 0 to many times Find the highest achievable sum <= goal Return any shortest (fewest items) sequence which adds to that sum. “”” assert goal … Read more