EDIT The conclusion from the discussion in the comments is it’s a bug in Canopy IDE. The code you’re showing us is not the code you’re running. Your output is this: Available Letters: abcdefghijklmnopqrstuwxyz. Which is supposed to be printed by this (note the dot added on the end): print “Available Letters: ” + getAvailableLetters(lettersGuessed) … Read more
Here is easy sample code to understand: def odd_square(number): if number == 0: return 0 elif number % 2 == 1: return number*number else: return (number – 1)*(number – 1) square = odd_square(int(input(“Enter number to square: “))) print(“square is: “,square) you need to convert number to integer as input() returns string. TypeError: odd_square() takes 0 … Read more
What you are trying to do is called time series prediction (given data at time t-n, t-(n+1) … t-1: predict the state at time t) and is generally a task for a recurrent neural network. Here is the great blog post by Andrej Karpathy about the topic that you should have a look at. About … Read more
Your code def leap(year): if year % 4 == 0: if year % 100 == 0: if year % 400 == 0: return True else: return False print(leap(1992)) Let’s break it down for 1992. year = 1992. 1992 % 4 = 0. True. The code moves to next if statement. 1992 % 100 = 92(False). … Read more
I would do it like this: >>> fst = {‘A’: 5, ‘B’: 6, ‘C’: 8} >>> snd = {‘A’: 4, ‘B’: 9, ‘E’: 2} >>> out = {k: fst[k] + snd[k] for k in fst.keys() & snd.keys()} >>> out.update({k: fst[k] if k in fst else snd[k] for k in fst.keys() ^ snd.keys()}) >>> out {‘A’: … Read more
To mention a user you have to define it beforehand. You do this as follows: user = message.mentions[0] To mention the user you can either use f-strings or format. Based on the code above here is an example: @client.event # Or whatever you use async def on_message(message): user = message.mentions[0] if message.content.startswith(‘!best’): await message.channel.send(“Hello, {}”.format(user.mention)) … Read more
There are a couple of problems with your code. 1) The condition if input in shape: You never defined a variable “input”. Furthermore, I’m not real sure why you are checking a condition here anyways. If you’re trying to verify that shape is either a rectangle or square consider this code instead: if shape in … Read more
Assuming the keys (here, prompt) of both dictionaries are the same, or at least for every key in the answers dictionary, there is a matching response prompt, then you can count them like so count = 0 for prompt, response in responses.items(): if response == answers.get(prompt, None): count += 1 return count 1 solved Compare … Read more
use list comprehension in python l = [3, 11, 4, 9, 1, 23, 5, 11] indexes = [index for index in range(len(l)) if l[index] == 11] output: [1, 7] use numpy for finding the matching indices. import numpy as np l = [3, 11, 4, 9, 1, 23, 5, 11] np_array = np.array(l) item_index = … Read more
You can implement a custom dict wrapper (either a subclass of dict or something that contains a dict) and implement __getattr__ (or __getattribute__) to return data from the dict. class DictObject(object): def __init__(self, data): self.mydict = data def __getattr__(self, attr): if attr in self.mydict: return self.mydict[attr] return super(self, DictObject).__getattr__(attr) solved Access dict via dict.key
It converts the number of microseconds since time code 00:00:00,000 into hours:minutes:seconds,milliseconds. The milliseconds are truncated, not rounded. 2 solved Can someone explain what this python code does?
Remove id feature, also check and remove any features which you think add no value to prediction (any other features like id) or features with unique values. Also check if there is any class imbalance (how many samples of each class are present in data, is there proper balance among the classes?). Then try applying … Read more
In general case one would parse and write the BDF files with something like the pyNastran. However in this specific case using your approach is not that wrong; though your regular expressions are wrong, though the principle works here. Notice also, you need to use raw strings or escape \ in the paths; the use … Read more
You error is with python syntax: Code resolved for x in geocode[0][‘address_components’]: print(x) if ‘administrative_area_level_1’ in x[‘types’] : print(x[‘long_name’]) 1 solved Reverse geocoding with Python/GoogleMaps API: How to parse response
If that’s really all you want: words = output.split(‘ ‘, 1) if words[0] == ‘search’ and words[1] in Terms: print(“win”) 5 solved How can I make this code not use a list or a ton of conditional statements? [closed]