[ad_1] You can use datetime to perform the necessary calculations. In this example, the target time is parsed using strptime but the date is not supplied so the time part is correct but the date part is wrong. The first three fields (year, month, day) are then replaced with today’s date to produce a datetime … Read more
[ad_1] You need to create a function and then return the output of the addition. A function which takes two arguments. def addition(number1, number2): return number1 + number2 number1 and number2 are the 2 arguments. Since you already have 2 numbers in your list you can pass them like this. print(addition(*randomlist)) The * unpacks the … Read more
[ad_1] Python uses short-circuiting in logical conditions – in simple words if it determines that there is enough info so that the whole condition is True or False it won’t continue executing the rest of the code in the condition statement – so in your case not all code you intended got executed. A simple … Read more
[ad_1] You could use Python f-strings. print(f'{int(seconds / 60):02} mins {int(seconds % 60):02} seconds’) [ad_2] solved How do I convert 62 seconds into string 01 mins 02 secs [duplicate]
[ad_1] You need to do it this way, if i am correct to assume this is your purpose: petname = [‘Zophie’, ‘Pooka’, ‘Fat-tail’] print (‘What is your pets name?’) name = input() if name not in petname: print (‘Your pet is not in the list’) else: print (‘Your pet is in the list’) [ad_2] solved … Read more
[ad_1] So basically instead of adding the values on the return just [(x, y) for x in [2,3,4] for y in [2,4,5] if x+y==7] I expect this will give you the desired output you asked for. [ad_2] solved How to get tuple of numbers that fulfill a condition? [closed]
[ad_1] So I have check and it seem stuck at the second while loop. So let’s go step by step. You set m=0, as long as m <= 36 it holds true, stepping in if and only if m % 6 == 0 this is true, if so do some code, then increment m by … Read more
[ad_1] Start from adding DatTim column (of type DateTime), taking source data from Date and Time: df[‘DatTim’] = pd.to_datetime(df.Date + ‘ ‘ + df.Time) Then, assuming that ID is an “ordinary” column (not the index), you should call: groupby on DatTim column with 5 min frequency. To each group apply drop_duplicates, with subset including only … Read more
[ad_1] Your code is using Python’s list comprehension to create a list from another list based on the condition. See more about list comprehensions here: https://www.programiz.com/python-programming/list-comprehension The [1] is accessing the item at index 1 (2nd item) of your sorted list. As for .join, each line in the sorted list is being printed out with … Read more
[ad_1] Your glob isn’t correct. You should add a /* to the end of your path to select all files (or directories) in your path, and then check if they are files with os.path.isfile. Something like: from os.path import isfile files=filter(isfile,glob.glob(‘%s/*’%path)) You also have an issue with the actual opening. When your with statement ends, … Read more
[ad_1] The program works as intended. You define global_variable_x = x and give it the name global_variable, but in fact it’s a local variable. The easiest way to be able to keep the data persistent is to modify x or to use classes and write it to a class variable. To give you some more … Read more
[ad_1] Your function takes 2 iterables and counts the number of times, by index, the number from one iterable is greater than the other. It then does the same operation with lists in the opposite order. It’s far easier to show an example: def solve(a, b): return map(lambda t: sum([x > y for x, y … Read more
[ad_1] Thank you i was searching about something like that s=input(‘Enter S’) e=input(‘Enter E’) A=[] for x in range (s,e): A.append(x) if len(A)==3: print(A[0],A[1],A[2]) del A[0:3] Sorry i was not helpful in describe what i want [ad_2] solved Create a numeric string using three variables
[ad_1] you can do that as follows: d = {“coord”: {“lon”: -71.06, “lat”: 42.36}, “weather”: [{“id”: 500, “main”: “Rain”, “description”: “light rain”, “icon”: “10n”}], “base”: “stations”, “main”: {“temp”: 1.69, “feels_like”: -1.22, “temp_min”: 0, “temp_max”: 3.33, “pressure”: 1013, “humidity”: 94}, “visibility”: 16093, “wind”: { “speed”: 1.5, “deg”: 230}, “rain”: {“1h”: 0.25}, “clouds”: {“all”: 90}, “dt”: 1582094044, … Read more
[ad_1] That’s because in your second code you’re re-assigning r back to the empty string ”. Thus you only get the final character multiplied 3 times (which for Mississippi is i). [ad_2] solved Why am I getting two diferent outputs with my python code? [closed]