1> Why can’t i remove from tkinter import* from the last_function file.. cause anyway it’s got that on the top of the file that’s calling it right.Why do i get an error saying IntVar() not defined The Python “import” follows the same scoping rules as the rest of the Python language. By “import” at the … Read more
Algorithm input = [2,5,1,4,7,3,1,2,3] output = [[]] for idx,val in enumerate(input): if idx > 0 and input[idx-1] > input[idx]: output.append([val]) else: output[-1].append(val) print output Output is [[2, 5], [1, 4, 7], [3], [1, 2, 3]] Explanation of the algorithm in words: Create an output list with an empty sublist. Enumerate over the input list. If … Read more
Taking your second question: is this possible? Of course it is. Both PHP and python are turing complete, and both can take console input. 1 solved Convert Python calculator to PHP [closed]
//This code is for explanation quiz = str(input(“would you like to answer some questions \n choose y/n”)) quiz = quiz.lower() while quiz != ‘y’ and quiz != ‘n’: //here you are using != that will result false this logic works fine with ! //while quiz == ‘y’ or quiz == ‘n’: //will work for or … Read more
IIUC, given array = [[[0,0,1,0],[0,0,0,1],[1,0,0,0],[0,1,0,0]], [[0,1,0],[1,0,0],[0,0,1],[0,0,1]], [[0],[1],[0],[1]], [[1],[1],[0],[1]]] Do import numpy as np >>> np.array(array).T array([[list([0, 0, 1, 0]), list([0, 1, 0]), list([0]), list([1])], [list([0, 0, 0, 1]), list([1, 0, 0]), list([1]), list([1])], [list([1, 0, 0, 0]), list([0, 0, 1]), list([0]), list([0])], [list([0, 1, 0, 0]), list([0, 0, 1]), list([1]), list([1])]], 2 solved Reshaping a … Read more
It is behaving just the way it should. It’s just that how you print the query. from sqlalchemy.dialects import postgresql query = statement.compile(dialect=postgresql.dialect(),compile_kwargs={“literal_binds”: True}) print(query) # will print the compiled query statement againt the dialect. 1 solved How to print the ACTUAL SQLAlchemy query to troubleshoot: SQLAlchemy filter statement replaces filter critieria with %(column_name_1)s
def main(): # I’m assuming you can get this far… lines = [ ‘1,some stuff 1’, ‘2,some stuff 2,more stuff’, ‘2,some stuff 4,candy,bacon’, ‘3,some stuff 3,this,is,horrible…’ ] # Something to hold your parsed data data = {} # Iterate over each line of your file for line in lines: # Split the data apart on … Read more
What you need is a while loop since you don’t know how many times you need to go round. (your for loop goes round a fixed number of times) prob = 1 classsize = 1 while prob > 0.1: prob = prob * (365 – classsize) / 365 classsize += 1 print(classsize) output: 41 1 … Read more
You can try this in one line : with open(“file.txt”) as f: print([i.strip().split(‘,’) for i in f]) 2 solved How do you read a textfile into an array python
Code: #Input l = [2011,2010,2012,2013,2014,2015,2016,2017,2018,2020,2021,2022,2023] # Enter year yr = int(input(‘Enter year :’)) #Here I am creating new list by deducting the input year #like 2011-2008 list elemnt will be 3 list ex: [3,2,4..] minus = [abs(i-yr) for i in l] #Lastly to find the near year, by searching the min of minus list l[minus.index(min(minus))] … Read more
If you have the memory to create a set of all tuples from one list then this is the most efficient way. Convert one list to a set of all its tuples and then iterate over the other list. This runs in O(n) time and space complexity. L1 = [8, 80, 53, 70, 90, 24, … Read more
Hello, I have a query in mysql bench that works fine for every “reference” , but when using the same query in python returns different results [closed] solved Hello, I have a query in mysql bench that works fine for every “reference” , but when using the same query in python returns different results [closed]
well what the comments said and change it like the following too : id = [1, 2, 3, 4, 5, 6] name = [‘sarah’, ‘john’, ‘mark’, ‘james’, ‘jack’] userid = int(input(‘enter user ID: ‘)) if userid in id: ind = id.index(userid) #notice this statement is inside the if and not outside print(name[ind]) else: print(“wrong id”) … Read more
I hope I’ve understood your question right. If you want to subtract each value from x[<indexes_for_x>] then you can do: x = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10] indexes_for_x = [0, 1, 2, 3] for v in indexes_for_x: print(f”y_at_index_{v} = {[w – x[v] for w in x]}”) Prints: y_at_index_0 = [0, … Read more
This will do what you want: In [2]: user_data[“watched”].append(movie) In [3]: user_data Out[3]: {‘watched’: [{‘title’: ‘Title A’, ‘genre’: ‘Horror’, ‘rating’: 3.5}]} Note that accessing a dictionary returns the value associated with the given key, so user_data[“watched”] gives us the list object associated with that key “watched”. Since we have a list, we can use the … Read more