[ad_1] I’m considering you have a string answer stored in the variable c and you want to access a list with the respective name. With this objective, you can use the python function eval(). From the python docs (here) you have that: eval(expression[, globals[, locals]]) The expression argument is parsed and evaluated as a Python … Read more
[ad_1] items() contains tuples, key-value pairs: >>> spam.items() dict_items([(‘name’, ‘Zophie’), (‘age’, 7)]) Your key is not such a tuple. It may be contained in one of the tuples, but in does not test for containment recursively. Either test for the correct key-value tuple: >>> (‘name’, ‘Zophie’) in spam.items() True or if you can’t get access … Read more
[ad_1] It was already said that the delimiter is inserted between each element not added to each element. However you can easily create a new list with the correctly added bear, for example: >>> lst = [‘brown’, ‘polar’, ‘grizzly’, ‘sun’, ‘kodiak’] >>> newlst = [item + ‘ bear’ for item in lst] >>> print(‘\n’.join(newlst)) brown … Read more
[ad_1] You don’t need goto. Period. Just learn to use Python properly. for i in range(1,10) : print i if i == 9 : print “find 9” break Applied to your actual code, the solution is almost the same: for char in chars : while True: if sem.acquire : filename += char t = threading.Thread(target=get200, … Read more
[ad_1] Your error message: mechanize._form.ControlNotFoundError: no control matching name ‘password’ Try reading it. Then look at the page you are trying to code against. There is no form field with the name “password” on that form. 2 [ad_2] solved brute force script python and mechanize
[ad_1] count = int(input()) values = [int(input()) for _ in range(count)] for v in values: # alternatively, print(” “.join(str(v) for v in values)) print(v) 4 [ad_2] solved how to insert numbers in a list c++ style using python [duplicate]
[ad_1] Fastest (least execution time) approach to get max/min of an array of int without inbuilt functions except range() and len() [closed] [ad_2] solved Fastest (least execution time) approach to get max/min of an array of int without inbuilt functions except range() and len() [closed]
[ad_1] You can create a helper function to dynamically populate the values in a dict object with the necessary structure: from __future__ import annotations def build_api_request(names: list[str], first: str, last: str, email: str, mobile_no: str, country_code: str | int): return { “list_name”: ‘,’.join(names), “subscriptions”: [ {“first_name”: first, “last_name”: last, “email”: email, “mobile”: {“number”: mobile_no, “country_code”: … Read more
[ad_1] list.reverse operates in place. That means that it almost certainly does something like this under the hood: for i in range(len(self) // 2): j = len(self) – 1 – i self[i], self[j] = self[j], self[i] The actual method is implemented in C, so of course it will be much more verbose, especially in the … Read more
[ad_1] Very simple Use the str.split() function transform your alphabet soup, then split the single elements further by directly accessing them. For example: text=””‘ A1 A10 A10 B14 C1 C14 C14 C8 ”’ for t in text.split(): print( {t[0]: t[1:]} ) prints: {‘A’: ‘1’} {‘A’: ’10’} {‘A’: ’10’} {‘B’: ’14’} {‘C’: ‘1’} {‘C’: ’14’} {‘C’: … Read more
[ad_1] if v < e: v = e can be read: “If v is less than e, make v the value of e.” As above you should put a new line to make it read easier: if v < e: v = e [ad_2] solved Python : What is the purpose of a colon in … Read more
[ad_1] I have searched for code translators and can find no comprehensible answer. I need to know what this bit of python codes means [ad_2] solved I have searched for code translators and can find no comprehensible answer. I need to know what this bit of python codes means
[ad_1] First you should do is to properly define type of the graph, because unlike Python you have to specify types in Swift in declaration: var graph: [String: [String: Int]] // Dictionary(hash table) with keys of type String and values of type Dictionary<String, Int> Then you should initialize graph with some initial value, because in … Read more
[ad_1] str = “IV_04.03.2019-10-56-45_example_c584536f-ab26-40ce-b5b6-386f755ba747_1.csv” s1= str.split(“_”)[2] s2= str.split(“_”)[3] print (s1) print (s2) output: example c584536f-ab26-40ce-b5b6-386f755ba747 3 [ad_2] solved How to get string between two underscores? [closed]
[ad_1] Here is a simple, but not most efficient way. you can achieve that by two step: convert list to set, to remove the duplicate number. use heap to find nlargest and nsmallest in set def difference(list1): set1 = set(list1) return heapq.nlargest(2, set1)[1] – heapq.nsmallest(2, set1)[1] Here is a one pass way, more efficient way, … Read more