I’m considering you have a string answer stored in the variable c and you want to access a list with the respective name. With this objective, you can use the python function eval(). From the python docs (here) you have that: eval(expression[, globals[, locals]]) The expression argument is parsed and evaluated as a Python expression … Read more
items() contains tuples, key-value pairs: >>> spam.items() dict_items([(‘name’, ‘Zophie’), (‘age’, 7)]) Your key is not such a tuple. It may be contained in one of the tuples, but in does not test for containment recursively. Either test for the correct key-value tuple: >>> (‘name’, ‘Zophie’) in spam.items() True or if you can’t get access to … Read more
It was already said that the delimiter is inserted between each element not added to each element. However you can easily create a new list with the correctly added bear, for example: >>> lst = [‘brown’, ‘polar’, ‘grizzly’, ‘sun’, ‘kodiak’] >>> newlst = [item + ‘ bear’ for item in lst] >>> print(‘\n’.join(newlst)) brown bear … Read more
You don’t need goto. Period. Just learn to use Python properly. for i in range(1,10) : print i if i == 9 : print “find 9” break Applied to your actual code, the solution is almost the same: for char in chars : while True: if sem.acquire : filename += char t = threading.Thread(target=get200, args=(root … Read more
Your error message: mechanize._form.ControlNotFoundError: no control matching name ‘password’ Try reading it. Then look at the page you are trying to code against. There is no form field with the name “password” on that form. 2 solved brute force script python and mechanize
count = int(input()) values = [int(input()) for _ in range(count)] for v in values: # alternatively, print(” “.join(str(v) for v in values)) print(v) 4 solved how to insert numbers in a list c++ style using python [duplicate]
Fastest (least execution time) approach to get max/min of an array of int without inbuilt functions except range() and len() [closed] solved Fastest (least execution time) approach to get max/min of an array of int without inbuilt functions except range() and len() [closed]
You can create a helper function to dynamically populate the values in a dict object with the necessary structure: from __future__ import annotations def build_api_request(names: list[str], first: str, last: str, email: str, mobile_no: str, country_code: str | int): return { “list_name”: ‘,’.join(names), “subscriptions”: [ {“first_name”: first, “last_name”: last, “email”: email, “mobile”: {“number”: mobile_no, “country_code”: str(country_code)}} … Read more
list.reverse operates in place. That means that it almost certainly does something like this under the hood: for i in range(len(self) // 2): j = len(self) – 1 – i self[i], self[j] = self[j], self[i] The actual method is implemented in C, so of course it will be much more verbose, especially in the swapping … Read more
Very simple Use the str.split() function transform your alphabet soup, then split the single elements further by directly accessing them. For example: text=””‘ A1 A10 A10 B14 C1 C14 C14 C8 ”’ for t in text.split(): print( {t[0]: t[1:]} ) prints: {‘A’: ‘1’} {‘A’: ’10’} {‘A’: ’10’} {‘B’: ’14’} {‘C’: ‘1’} {‘C’: ’14’} {‘C’: ’14’} … Read more
if v < e: v = e can be read: “If v is less than e, make v the value of e.” As above you should put a new line to make it read easier: if v < e: v = e solved Python : What is the purpose of a colon in an if … Read more
I have searched for code translators and can find no comprehensible answer. I need to know what this bit of python codes means solved I have searched for code translators and can find no comprehensible answer. I need to know what this bit of python codes means
First you should do is to properly define type of the graph, because unlike Python you have to specify types in Swift in declaration: var graph: [String: [String: Int]] // Dictionary(hash table) with keys of type String and values of type Dictionary<String, Int> Then you should initialize graph with some initial value, because in Swift … Read more
str = “IV_04.03.2019-10-56-45_example_c584536f-ab26-40ce-b5b6-386f755ba747_1.csv” s1= str.split(“_”)[2] s2= str.split(“_”)[3] print (s1) print (s2) output: example c584536f-ab26-40ce-b5b6-386f755ba747 3 solved How to get string between two underscores? [closed]
Here is a simple, but not most efficient way. you can achieve that by two step: convert list to set, to remove the duplicate number. use heap to find nlargest and nsmallest in set def difference(list1): set1 = set(list1) return heapq.nlargest(2, set1)[1] – heapq.nsmallest(2, set1)[1] Here is a one pass way, more efficient way, use … Read more