The following program should do as you asked. There are several lines that are commented out with the # character. You may uncomment those lines if you wish to see the value of the variable referenced in the call to the debug function. Please take time to study the code so that you understand how … Read more
You can’t just concatenate an operator to a couple of numbers and expect it to be evaluated. You could use eval to evaluate the final string. answer = eval(str(randomnumberforq) + operator[randomoperator] + str(randomnumberforq)) A better way to accomplish what you’re attempting is to use the functions found in the operator module. By assigning the functions … Read more
How about using some flags to track where you are in the checking process and some variables to hold historical info? This is not super elegant code but it is fairly simple to understand I think and fairly robust for the use case you gave. My code cross = [7,5,8,0,0,0,0,2,5,8,0,0,0,0,8,7,9,3,0,0,0,3,2,1,4,5,0,0,0,7,5] foundstart = False foundend = … Read more
This is a bad idea, but: def handle_nameerror(list_to_set, *varnames): for i in varnames: try: list_to_set.append(globals()[i]) except NameError: list_to_set.append(None) will work. 2 solved How to use NameError to define a variable in Python
One should neither type int nor index and wonder why it isn’t working. Sigh. Typo, never was a init to begin with. Now everything works. solved Python custom __init__ not called when imported
from reportlab.pdfgen import canvas from reportlab.lib.pagesizes import A4 c=canvas.Canvas(“Background”,pagesize=A4) c.setFillColorRGB(1,0,0) c.rect(5,5,652,792,fill=1) c.setTitle(“Background”) c.showPage() c.save() solved How to set a pdf background color? [closed]
You can try creating a dictionary from columns [‘CheckStringHere’,’AssociatedValue1′] and replace values from StringToCheck column: d = dict(df[[‘CheckStringHere’,’AssociatedValue1′]].to_numpy()) df[‘FromNumber’] = df[‘StringToCheck’].replace(d) #or df[‘FromNumber’] = df[‘StringToCheck’].map(d).fillna(df[‘FromNumber’]) print(df) StringToCheck FromNumber ToNumber CheckStringHere AssociatedValue1 \ 0 10T 56 AAA_ER 1 125T 16 FGGR_DBC 2 10T 56 3 125T 16 AssociatedValue2 0 1 2 58 3 24 2 solved … Read more
from socket import * s = socket() s.connect((‘example.com’, 80)) s.send(‘GET / HTTP/1.1\r\n\r\n’) print s.recv(8192) ? Or: http://docs.python.org/2/library/urllib2.html import urllib2 f = urllib2.urlopen(‘http://www.python.org/’) print f.read(100) The first option might need more header items, for instance: from socket import * s = socket() s.connect((‘example.com’, 80)) s.send(‘GET / HTTP/1.1\r\nHost: example.com\r\nUser-Agent: MyScript\r\n\r\n’) print s.recv(8192) Also, the first solution which … Read more
You might want to read Read ints from file in python It is even more straightforward from that question. I have not checked the following code but something along the spirit of fin = open(“hi.bmp”, “rb”) out = open(“values.txt”,”rw”) value = struct.unpack(‘i’, fin.read(4))[0] out.write(“%d\n” % value) # just loop over the 2 last lines out.close() … Read more
The number of possible routes through a tree is 2**rows. The number of possible routes to a given node is given by the binomial expansion. You can grow the possible routes from the head of the tree quite simply, at each node there are only two possible next moves, their indexes in the list are … Read more
user_key = user_id.key() But why is your head spinning? What are you actually trying to accomplish? 0 solved Deriving Key() from get_by_id()
All you need is python here and selenium here. Windows 7 or another system: To install selenium, extract tr.gz file, cd into the directory and then python setup.py install. Or you could use pip like this: pip install -U selenium Specifically for linux, use $ sudo apt-get install python-pip $ sudo pip install selenium Installing … Read more
I think you have mixed up index numbers with keys. Dictionaries are formed like such: {key: value} data.keys() will return a list of keys. In your case: data.keys() [0,1,2] From there, you can call the first item, which is 0 (First item in a list is 0, and then progresses by one). data.keys()[0] 0 If … Read more
The problem is that you are over-writing the value of namelist and scorelist with each pass through the loop. You need to add each item to a list. Adding a sequential list of items to a list is usually done with list.append() or a list comprehension. Read the documentation, or do some tutorials? To actually … Read more
print(“\n”.join([i if i != p.sub(“”, i) else “%fix_me%” for i in open(“tt.txt”).readlines()]).replace(“%fix_me%\n”, “”) Updated to reflect comments on comprehension mistake..: print(“\n”.join([i for i in open(“tt.txt”).readlines() if i != p.sub(“”, i)])) 2 solved reading files in python using minimum lines of code