This can be done conveniently by using the appropriate representation for your fractional hours, namely a timedelta. If the input is of datatype string, convert to float first. Ex: from datetime import datetime, timedelta for td in [8.25, 17.75]: # add the duration as timedelta to an arbitrary date to get a time object: print((datetime(2020,1,1) … Read more
Update This version adds all already seen words to the exclude set: exclude = set(‘why kid is upset’.split()) list_of_strings = [‘why my kid is upset’, ‘why beautiful kid is upset’, ‘why my 15 years old kid is upset’, ‘why my kid is always upset’] res = [] for item in list_of_strings: words = item.split() res.append(‘ … Read more
Solution: val_A = [] val_B = [] val_A.append(A1) val_B.append(B1) for i in range(5): val_A.append(val_B[-1] * Z2) val_B.append(val_A[-1] * Z1) Demo: (On a simple test case, to show that it works) # Manual Z1 = 2 Z2 = 3 A1 = 5 B1 = 7 A2 = B1*Z2 B2 = A2*Z1 A3 = B2*Z2 B3 = … Read more
I’d do it this way: result = [] reader = [‘sdsd-sdds’, ‘asaad’, ‘deded – wdswd’, ‘123’ ] str_1 = ‘deded -‘ for x in reader: if str_1 in x: result.append(reader[reader.index(x) + 1]) print(result) If you want to stop after finding the first one you should use a break after finding a value: result = [] … Read more
self.tracks seems to be an (n,2) list. The outer loop takes each of these values, turns them two by two into integers x and y, then performs a function/method cv2.circle with an object mask and several other parameters. container[-1] indicates that you want the value of the last index of container. The values of the … Read more
Replace last main() with main(game) and make this small changes, remember to read the python tutorials, good luck! import random import math game = int(input(“How many problems do you want?\n”)) num_1 = random.randint(1,10) num_2 = random.randint(1,10) def main(game): random.seed() count = 0 correct = 0 result = 0 #Here we initialized result to 0 while … Read more
You could use split etc. but it’s not very robust: >>> s.str[2:-2].str.split(“‘,\s*'”, expand=True).add_prefix(‘rep’) rep0 … rep2 1 f, they have everything i am looking for. … q, i always find what I am looking for 2 easy to navigate … easy to use, very convenient [2 rows x 3 columns] The robust way to do … Read more
From the documentation: Indentation is rejected as inconsistent if a source file mixes tabs and spaces in a way that makes the meaning dependent on the worth of a tab in spaces; a TabError is raised in that case. You state the body of the with statement is indented with 3 tabs. If that is … Read more
Have a look at the sci-kit learn documentation for Multinomial NB. It clearly specifies the structure of the input data while trainig model.fit() must match the structure of the input data while testing or scoring model.predict(). This means that you cannot use the same model for different dataset. The only way this is possible is … Read more
Assuming the keys (here, prompt) of both dictionaries are the same, or at least for every key in the answers dictionary, there is a matching response prompt, then you can count them like so count = 0 for prompt, response in responses.items(): if response == answers.get(prompt, None): count += 1 return count 1 solved Compare … Read more
You can create a separate method: for task in self.tasks: task = randomTask() … def randomTask(): while True: num1 = random.randint(0, 10) num2 = random.randint(0, 10) if num1 + num2 <= 10: break return “{} + {} =”.format(num1, num2) solved I can’t make this in to a for loop
you can try following implimentation from django.utils.deprecation import MiddlewareMixin class DisplayMarketing(MiddlewareMixin): def process_request(self, request): try: request.session[‘marketing_message’]=MarketingMessage.objects.all()[0].message except: request.session[‘marketing_message’]=False solved TypeError: DisplayMarketingMessage() takes no arguments how to fix it
Damn, a quick google search finds: def convert_si_to_number(x): total_stars = 0 x = x.replace(‘€’, ”) if ‘k’ in x: if len(x) > 1: total_stars = float(x.replace(‘k’, ”)) * 1000 # convert k to a thousand elif ‘M’ in x: if len(x) > 1: total_stars = float(x.replace(‘M’, ”)) * 1000000 # convert M to a million … Read more
you could do this string.replace(“,”, “?,”) print(string) would output in: ‘the?, quick?, brown?, fox?, jumps?, over?, the?, lazy?, dog’ solved how do I insert a question mark before every comma in a string python? [closed]
How to write a python program that takes a number from the users and prints the divisors of that number and then print how many divisors were there? [closed] solved How to write a python program that takes a number from the users and prints the divisors of that number and then print how many … Read more