[ad_1] Can be extracted with a simple regular expression, as long as the text file is in the same format as the Python log output you posted (Returns all of them): import re file=””.join([i for i in open(“yourfileinthesamefolder.txt”)]) serials=re.findall(“u’serial_number’: u'(.+)'”,file) print(serials) I suggest reading up on how to use regular expressions in Python: Regular Expression … Read more
[ad_1] There is a function called list to do this directly.This can convert any string into list of characters. list(‘01101’) will return [‘0’, ‘1’, ‘1’, ‘0’, ‘1’] One more way is a=”01101″ a_list=[] for item in a: a_list.append(item) print(a_list) 5 [ad_2] solved a=’01101′ this has to be converted to [‘0′,’1′,’1′,’0′,’1’] ?? IN PYTHON [duplicate]
[ad_1] Take a look at this example: from tkinter import * root = Tk() def run(): global rep if var.get() == 1: print(‘Hey’) rep = root.after(1000,run) #run the function every 2 second, if checked. else: root.after_cancel(rep) #cancel if the checkbutton is unchecked. def step(): print(‘This is being printed in between the other loop’) var = … Read more
[ad_1] Is that what you want? INPUT_COUNT = 8 FIRST_INPUTS = [] SECOND_INPUTS = [] for _ in range(INPUT_COUNT): result = input().split() try: FIRST_INPUTS.append(float(result[0])) SECOND_INPUTS.append(float(result[1])) except IndexError: pass [ad_2] solved Extracting user input in 2 different arrays
[ad_1] You have already answered your own question. When a new blog item is posted, simply locate the five most recent posts (including the one that was just posted) and delete (or mark as hidden) all other posts. I find it would make more sense to simply not allow access to older blog posts and … Read more
[ad_1] Your error occurs if you acces a list/string behind its data. You are removing things and access for i in range(len(data)): … data[i] += “,” + data[i + 1] If i ranges from 0 to len(data)-1 and you access data[i+1] you are outside of your data on your last i! Do not ever modify … Read more
[ad_1] Read user input. Repeat for that many number of times – get items from dictionary using get attribute which handles KeyError itself: dic = {‘Hello’: ‘Salam’, ‘Goodbye’: ‘Khodafez’, ‘Say’: ‘Goftan’, ‘We’: ‘Ma’, ‘You’: ‘Shoma’} n = int(input()) for _ in range(n): print(dic.get(input(), ‘Wrong Input’)) EDIT: dic = {‘Hello’: ‘Salam’, ‘Goodbye’: ‘Khodafez’, ‘Say’: ‘Goftan’, ‘We’: … Read more
[ad_1] Perhaps the closest thing in Python to this Javascript array behavior is a dictionary. It’s a hashed mapping. defaultdict is a dictionary that implements a default value. In [1]: from collections import defaultdict In [2]: arr = defaultdict(bool) Insert a couple of True elements: In [3]: arr[10] = True In [4]: arr Out[4]: defaultdict(bool, … Read more
[ad_1] The first output shows a comma because without it, 1 being the only element, (1) would be just a integer (parentheses are wrapping the expression 1), (1,) is shown to differentiate tuples and simple parentheses. in the second one, no trailing comma is needed to differentiate tuples, since there are more than one element. … Read more
[ad_1] In the future, provide some code to show what you have attempted. I have expanded on Fabix answer. The following code gets the Youtube link, song name, and artist for all 20 pages on the source website. from bs4 import BeautifulSoup import requests master_url=”https://www.last.fm/tag/rock/tracks?page={}” headers = { “User-Agent”: “Mozilla/5.0 (iPhone; CPU iPhone OS 5_1 … Read more
[ad_1] Keeping it simple, you could do something like this: reading = 0 notReading = 0 for book in bookLogger: if book[‘Process’] == ‘Reading’: reading += 1 elif book[‘Process’] == ‘Not Reading’: notReading += 1 print(f’Reading: {reading}’) print(f’Not Reading: {notReading}’) Alternatively, you could also use python’s list comprehension: reading = sum(1 for book in bookLogger … Read more
[ad_1] Before you can use a module, you need to import it. Add import functools at the top of your script. 0 [ad_2] solved I have a problem with the functools.reduce() built-in function [closed]
[ad_1] Define r outside the Checkdiv function and in the function use r variable as a global variable with global keyword; global r and then r=int(n % d). so that other code blocks will be able to see the r variable too. r = 0 def Checkdiv(n, d): global r r = int(n % d) … Read more
[ad_1] One way would be to read each line of the file into a list. Then find the index of the first list item to remove and the last list item to remove and use del[first:last+1] to remove those, then use list.insert() to put in the new rows starting at first. [ad_2] solved Deleting lines … Read more
[ad_1] The problem with your code is simple. When count equals 3, you want to add a newline after printing out the last digit, otherwise the next set of 4 numbers will be printed on the same line. So, in summary, this is what you do: if count == 3: print(i) count = 0 One … Read more