def deleteVal (my_dict, key_val, val): if len(my_dict.get(key_val, “1”))>1: try: my_dict[key_val].remove(val) except ValueError: pass else: my_dict.pop(key_val, None) 9 solved Removing a dictionary key value having multiple value [closed]
. def isPrime(N): i = 2 while i**2 <= N: if N % i == 0: return False i+=1 return True for i in range(3, 21 + 1): if isPrime(i): print(i, ‘is prime’) else: print(i, ‘is not a prime number’) First of all, create a function for determining whether or not a given number is … Read more
you have to specify dtype to get the expected behavior, else it will choose minimum size, i think it is choosing chararray and you are trying add numbers/strings. either use astype or numpy.array(data, dtype=””) to set dtype, look at the syntax of numpy.arry below numpy.array(object, dtype=None, copy=True, order=”K”, subok=False, ndmin=0) set dtype to string/integer/float whatever … Read more
Create a while loop like this. def run() clear() #check_win() should return true if there is a winner or false if not while(check_win()==False): #if there is nobody win, continue this loop if turn == 0: # X’s move runX() turn = 1 # the next turn will be O’s elif turn == 1: # O’s … Read more
What is length? length does not exist, but Node.length does. The reason return(1+length(self.next)) doesn’t work is because you’re calling length(), not Node.length(). Instead, try this: return(1+LinkedList.length(self.next)) Or this (my preference): return(1+self.next.length()) solved Why isn’t length(self.next) a valid expression in python? [closed]
Assuming envois is a socket, you will not receive more than the amount you specify. From the docs socket.recv(bufsize[, flags]) Receive data from the socket. The return value is a bytes object representing the data received. The maximum amount of data to be received at once is specified by bufsize. You should be able to … Read more
Well, technically, you’re right in that the piano variable is local. However, it still points to the same internal reference as pizza. This is what’s happening behind the scene: You allocate a new list of values, and a variable named pizza is created so you can refer to it: pizza -> [ 1 , 2 … Read more
I think you are going overkill on this and over complicating your task. First pass your list to test1, then you pass that result into test2 and take 2 choice‘s from that value and return them, both functions only need to receive one argument from random import choice def test1(x): return x def test2(x): a … Read more
From the exception it seems that you have tried to call my_wallet.checkBalance passing self as parameter. Try to do my_wallet.checkBalance() instead of my_wallet.checkBalance(self) self parameter is passed automatically to class methods in python 11 solved Don’t understand this “NameError: name ‘self’ is not defined” error [closed]
One simple way to accomplish this is to simply store lists in a list of lists as such num_lists = int(input(‘How many lists?’)) lists = [[] for i in range(num_lists)] Then each list can be accessed by an index (for example list1 = lists[0]). 1 solved Python – Create a certain “number” of lists from … Read more
You may want to look into python’s list comprehension. arr = [int(arr_temp) for arr_temp in input().strip().split(‘ ‘)] Let me answer this with an example, suppose you input : 1 3 4 29 12 -2 0 the input function reads this as a string The strip function eliminates whitespace from both ends of the string, The … Read more
Whenever you have Python code that is: Recalling The Same Function So That If The User Does Not Chose One Of The Other Statements Then They Can Try Again Rather Than The Program To Stop Working, you are almost always better off replacing the recursive call with a loop. In this case the recursion is … Read more
This issue was only present in the PyPI distribution of PyPDF2==2.3.0 for a couple of hours. It was fixed with release 2.3.1. See #1011 for more details I’m the maintainer of PyPDF2. I’m sorry I caused some headaches. You can update PyPDF2 via: pip install PyPDF2 –upgrade solved No module named ‘PyPDF2._codecs’, even after already … Read more
So there are two things: The assignment of s should be either with escaped back-slashes or as a raw string. I prefer the latter: s = r”C:\x\xxx\temp\downloads\test_dir\sql\my-ee.sql” you should use the search method instead of match to be content with a partial match. Then, you can use \\\\ in the regular expression, or – as … Read more
You’re returning early in the loop, you need to build up a string and return that. Either just return a joint string or build it up “”.join(chr(ord(s)+4) for s in pas) def cip(pas): ret_val = “” for i in pas: asci = ord(i) encryption = asci + 4 ret_val += chr(encryption) return ret_val solved It … Read more