void setvalores(int vi, int fu, int ve) { velocidad = &ve; vida = &vi; fuerza = &fu; }; The pointers to vi, fu, and ve get invalidated when the function returns. You’re not seeing addresses being printed, but simply garbage. Your entire design doesn’t and shouldn’t need to use pointers though. 8 solved Pointer will … Read more
Why is unmarshaling into a pointer variable not possible? It is possible. In fact, it’s required. Unmarshaling to a non-pointer is not possible. json: Unmarshal(nil *main.configuration) This error isn’t saying you can’t unmarshal to a pointer, it’s saying you can’t unmarshal to a nil pointer. The pointer must point to a valid (probably zero-value) variable. … Read more
you are passing reference to orig. you should use ‘orig.bigIntVector’ BigInt::BigInt(BigInt const& orig) : isPositive(orig.isPositive) , base(orig.base) , skip(orig.skip) { this->bigIntVector = new BigIntVector(*(orig.bigIntVector)); } should use *(orig.bigIntVector) 10 solved Copy Constructor Issue C++: “0xC0000005: Access violation writing location 0x00000000.”
list is one of the many classes provided by the Standard Library. It behaves like any other class type: int : integer int* : pointer to integer Observer : Observer instance Observer* : pointer to Observer instance list<Observer> : list of Observers list<Observer*>* : pointer to list of pointers to Observers solved Difference between list* … Read more
Passing an int by pointer: void fun (int* p) ; void fun (int* p) { *p += 1 ; // Add 1 to the value pointed by p. } Passing an int by reference: void fun (int& p) ; void fun (int& p) { p += 1 ; // Add 1 to p. } 3 … Read more
TL;DR *p equals c Explanation Hi, first take a look at how to format a question on stack overflow. You should write your code directly in the question. So your question is about the understanding of these lines: char c,*p; p = &c *p = ‘Z’ printf(“%c”, c) // ‘Z’ First you’re declaring two different … Read more
You might want to learn how these objects are laid out in memory: int array[][3] = { {1,2,3}, {4,5,6}, {7,8,9} }; int *p_array = (int *) array; This creates an object array of type int[][3] in memory (in this case stack) physically laid out in a hypothetical (16-bit word size) architecture as: array 0x8000: 0x0001 … Read more
If you want to print the pointer variable, you have to use the * before the variable name. Use the below printf statement it will work. printf(“OFPORT VAL = %lld\n”,*ofport_request); 4 solved How to resolve this pointer issue?
If we ignore errors, you can read the numbers in one at a time, and form a string for the first line of output. Forming the string will involve appending a reversed copy to the original. Once the string is formed, you can output that string for the first line. Then replace the first number … Read more
No, but it gives similar behaviour. So what you have created is a pointer to an array of vectors. So you will end up with this: adj[0] = [] adj[1] = [] … adj[number_nodes] = [] and doing a push_back is a legitimate way to add to the vectors: adj[0].push_back(some_num) –> adj[0] = [some_num] But … Read more
Whats wrong with this program in C? It terminates. I am having difficulty in understanding read input string in pointer of pointers [closed] solved Whats wrong with this program in C? It terminates. I am having difficulty in understanding read input string in pointer of pointers [closed]
I do not judge your algorithm or C conventions, friends who comment on your problem are totally right. But if you still do it in this way you can use this approach. #include <stdio.h> #include <string.h> void removeFirstAndLastChar(char* string) { memmove(string,string+1,strlen(string)); string[strlen(string)-1]=0; } int main(void) { char title[] = “ABC”; removeFirstAndLastChar(title); printf(“%s”, title); // Expected … Read more
First of all, in code you have provided I do not see operator +, so compiler is absolutely right. The second point I do not understand is *(clsOriginalToCopy + lngIndex) expression… What your operator + should return? Pointer? Why not reference (considering your operator =)? Try to redesign your class, perhaps operator + is not … Read more
this keyword is used to reference current instance of given class, for example: class A { public: void setName(std::string name) { // if you would use name variable directly it // will refer to the function parameter, //hence to refer the field of the class you need to use this this->name = name; } private: … Read more
WHere does your string point to? Nowhere! That’s why you have segmentation fault. You have to either allocate variable on stack as array or define it as pointer and later allocate memory using malloc. When using malloc, don’t forget to include “stdlib.h” Either do this: char str[6]; strcpy(str,”C-DAC”); or char *str=malloc(sizeof(*str) * 6); strcpy(str,”C-DAC”); solved … Read more