In short: primitive types and “Primitive wrappers (Integer, Long, Short, Double, Float, Character, Byte, Boolean)” can not be altered via reference. Check http://en.wikipedia.org/wiki/Immutable_object for Details 5 solved Pass by Ref Java. Integer ins’t modified, Collection is modified, Why? [duplicate]
The ampersand (&) in a declaration declares a reference type, not a pointer. The ampersand (&) in an expression is the address of operator, which yields a pointer. Just because the same token is used in the language for two different things does not mean they are related things. Unfortunately, especially for learners. 0 solved … Read more
It is already 2, as Array/Collections (to be precise any .NET Class/reference type) are passed by reference by default. In fact the reference variable is passed by value, but behaves as if passed by reference. Why -> Consider var arr = new ArrayList(); The above statement first creates an ArrayList object and a reference is … Read more
I finally found the solution to my problems, and am posting this for anyone who would need some clarification: First, as David pointed out, simply treating the referenced argument as a pointer and assigning it the array’s address does not work. You have to copy the entire array contents into the referenced array. Easily fixed. … Read more
I do not judge your algorithm or C conventions, friends who comment on your problem are totally right. But if you still do it in this way you can use this approach. #include <stdio.h> #include <string.h> void removeFirstAndLastChar(char* string) { memmove(string,string+1,strlen(string)); string[strlen(string)-1]=0; } int main(void) { char title[] = “ABC”; removeFirstAndLastChar(title); printf(“%s”, title); // Expected … Read more
I’m not going to answer with a complete solution (and you are free to improve your question so you get better answers later), but regarding the question title, here are some hints. Your declaration char displaymenu(int num1, int num2); and your definition char displaymenu(int &num1 = num1, int &num2 = num2) should have the same … Read more
settype() hasn’t been deprecated. Passing by reference at call time has been deprecated. You probably just want to remove the ampersand from in front of the first parameter to your settype() call. That would be easier to tell for sure if you actually posted your code… See the manual for more information on references in … Read more
Introduction Java is a popular programming language used by developers around the world. One of the most common questions asked about Java is whether it is a “pass-by-reference” or “pass-by-value” language. This article will explain the difference between the two and provide an answer to the question. It will also discuss the implications of the … Read more
Is Java “pass-by-reference” or “pass-by-value”? solved Is Java “pass-by-reference” or “pass-by-value”?