Just maintain a field in database which saves the last file upload date and time and if the uploads reach to the limit of 5 then before uploading file check that last file upload time. If the difference between last file upload time and current time is greater than 2 minutes then allow the file … Read more
You have to choose between the two – either show the image or save it to directory. You cant do both. imagejpeg($gd_object); //shows the image, requires content-type to be image/jpeg imagejpeg($gd_object, $filepath); //saves the image, to $filepath You can try to save the image and then redirect the use to the image if you want … Read more
So this is very crude, but it is one way you can do what you are trying to do: <table> <?php while($row=mysql_fetch_array($check2)) { ?> <tr> <td><?php echo $row[‘wTitle’]; ?></td> <td>Click to edit</td> </tr> <tr> <td style=”text-align:right;”><?php echo $row[‘wContent’]; ?></td> </tr> <tr> <td colspan=”2″ height=”202″> </td> </tr> <tr> <td colspan=”2″> <form action=”view.php” method=”post”> <input type=”submit” name=”submit” value=”edit” … Read more
The first point to keep in mind that the code must be object oriented as possible. Should be understood that must be validated both the client side and the server side. You have to know that in addition to receiving the data with expected values, still may not be safe for use in queries to … Read more
Assuming you’re going to Oracle, just set up the statement, parse, and execute. There’s no need to do any binding because you have no bind variables. This is adapted from the PHP documentation of oci_parse: $conn = oci_connect(your username, your password, your database); $stid = oci_parse($conn, ‘UPDATE tableName SET columnName = seq_test_id.NEXTVAL’); oci_execute($stid); 4 solved … Read more
You could try something like this to generate “different” page using one file only(example.com/title.php) Loop through your database to get all data while creating a <a> for each of them: foreach ($retrieveResult as $result) { echo ‘<a href=”https://stackoverflow.com/questions/44427393/example.com/title.php?name=”.$result[“title’].'”>’.$result[‘title’].'</a>’; } This will generate something like this: <a href=”https://stackoverflow.com/questions/44427393/example.com/title.php?name=titleA”>titleA</a> <a href=”example.com/title.php?name=titleB”>titleB</a> <a href=”example.com/title.php?name=titleC”>titleC</a> <a href=”example.com/title.php?name=titleD”>titleD</a> To get … Read more
On form action page $next_value = $_POST[‘fildvalue’]; $tags .=’,’.$next_value; header(‘location:url’) ; solved Change value in php [closed]
make sure to do proper escapes on anything that needs escaping. So escape OS/2 to OS\/2 7.0 to 7\.0 etc. . / ? * etc etc are all special to preg, so you should not use them in your pattern unless you escape them or when you want to use their “special powers” UPDATE: Had … Read more
var rand = 3; // somehow get the random number from server via ajax $(‘img’).attr(‘src’, ’empty’); $(‘img’).eq(rand).attr(‘src’, ‘full’); solved How i can change images after click on button and php script ended? [closed]
The tablename is given in the query after connection is established solved Where do we give the table-name?
The action attribute of the form tag directs the browser to where you want to send your form data. To direct the browser to a PHP script, just change the action attribute in your code to the PHP script you’d like to send your data to. <form action=”my_php_file.php”> solved Using HTML forms with a PHP … Read more
There are many ways to get XML from a URL – perhaps the simplest is using simplexml_load_file : $xml = simplexml_load_file($url); print_r($xml); Where obviously $url is your URL. You can add the username and password into the URL like http://username:password@url/ Or you could use cURL and then simplexml_load_string to parse the results: $ch = curl_init(); … Read more
This line is missing a comma: $Query .= “banner_images=””.$banner_images.”””; should be $Query .= “banner_images=””.$banner_images.””,”; As a sidenote, you are vulnerable to sql injection with your code, you might want to use prepared statements or at least mysql_real_escape_string 3 solved Radio Button not working [closed]
It’s better to return early. Nested if elses make conditionals even worse! Simplified (no elses) Example //nested (without return) if ($a == 1) { if ($a == 2) { if ($a > 2) { } } } //return early if ($a == 1) { return 1; } if ($a == 2) { return 2; } … Read more
You lost track of all needed ‘ and additionally forgot to quote username value. So instead of $result = mysql_query(“update Users set lat=”$lat”,lon=’$lng’ where username=$_SESSION[‘username’]”); do this in more clean manner: $result = mysql_query( “update Users set lat=”$lat”,lon=’$lng’ where username=”” . $_SESSION[“username’] . “‘”); or even better: $query = sprintf(“update Users set lat=”%s”,lon=’%s’ where username=%s”), … Read more