[Solved] Xml Parsing in Visual Studio 2015

You need to check oras like this string doc = @”<Absolventi nume=”Ace Timisoara”> <id>7</id> <oras>Timisoara</oras> </Absolventi>”; XmlDocument xDoc = new XmlDocument(); xDoc.LoadXml(doc); foreach (XmlNode node in xDoc.ChildNodes) { Console.WriteLine(node.Attributes[“nume”].Value); Console.WriteLine(node[“id”].InnerText); Console.WriteLine(node[“oras”].InnerText); } Test here 1 solved Xml Parsing in Visual Studio 2015

[Solved] Parse string in Powershell and create a table

I have to admit this is a bit excesive use of .replace() but there isn’t much to work with: $mystring= ” S: Title = test S: Title = test2 S: Title = test3 S: Title = test4 TE: 2019-01-19T00:00:00Z TE: 2019-01-20T00:00:00Z TE: 2019-01-22T00:00:00Z TE: 2019-01-23T00:00:00Z ” $MyString.trim().replace(” S: Title = “,”,”).replace(“T00:00:00Z TE: “,”,”).replace(“TE: “,””).replace(“S: Title … Read more

[Solved] parse R.java class

Use getIdentifier() int id = getResources().getIdentifier(“abs__home”, “string”, getPackageName()); if the name (abs__home) does not exits inside the resources, you will get 0 1 solved parse R.java class

[Solved] Android : parse a JSONArray

Here is your code to parse data, private void parseData(){ try { JSONArray jsonArray=new JSONArray(response); JSONObject jsonObject=jsonArray.getJSONObject(0); JSONArray jsonArrayNid=jsonObject.getJSONArray(“nid”); JSONArray jsonArrayUid=jsonObject.getJSONArray(“uid”); JSONArray jsonArrayField_image=jsonObject.getJSONArray(“field_image”); for(int i=0;i<jsonArrayNid.length();i++){ JSONObject jsonObjectNid=jsonArrayNid.getJSONObject(i); String value=jsonObjectNid.getString(“value”); //here you get your nid value } for(int i=0;i<jsonArrayUid.length();i++){ JSONObject jsonObjectUid=jsonArrayUid.getJSONObject(i); String target_id=jsonObjectUid.getString(“target_id”); //here you get your uid target_id value String url=jsonObjectUid.getString(“url”); //here you get your … Read more

[Solved] sed parsing xml file1 index file2

the awk line should work for u: awk ‘FNR==NR{if(NR%2)i=$0;else a[i]=$0;next;}{if($0 in a){print; print a[$0]}else print}’ file2 file1 EDIT here I see no EXTRA lines. see the test. (maybe your example data format is not same as your real data.). however I have shown the way, how to do it. you can change the awk oneliner … Read more

[Solved] Removing Tags from a file parsed in C

#include <stdio.h> #include <stdlib.h> #include <string.h> char *getfield(char **sp){ char *left; //point to < char *right;//point to > if((left = strchr(*sp, ‘<‘)) == NULL) return NULL; if((right = strchr(left, ‘>’)) == NULL) return NULL; size_t len = right – left;//if len == 1, tag is nothing(<>) char *tag = malloc(len); memcpy(tag, left + 1, len … Read more

[Solved] How to Merge CSV Files in PHP, Line by Line

Try this php code (gets the lines with file()).: <?php $csv1 = file(‘csv1.csv’, FILE_IGNORE_NEW_LINES | FILE_SKIP_EMPTY_LINES); $csv2 = file(‘csv2.csv’, FILE_IGNORE_NEW_LINES | FILE_SKIP_EMPTY_LINES); $csv3 = file(‘csv3.csv’, FILE_IGNORE_NEW_LINES | FILE_SKIP_EMPTY_LINES); $lines = max(count($csv1), count($csv2), count($csv3)); $finalcsv = array(); for($i=0; $i<$lines; $i++) { if(isset($csv1[$i])) $finalcsv[] = $csv1[$i]; if(isset($csv2[$i])) $finalcsv[] = $csv2[$i]; if(isset($csv3[$i])) $finalcsv[] = $csv3[$i]; } file_put_contents(‘final_data.csv’, implode(PHP_EOL, … Read more

[Solved] Finding the modules where changes were checked with svn

Three separate tasks: call svn properly to create the log parse the log Write the parsed values somewhere 1. import subprocess as sp svn_url = “svn://repo-path.com/project” revisions = [12345, 12346] revision_clargs = [“-r%i” % revision for revision in revisions] popen = sp.Popen([“svn”, “log”, “-v”] + revision_clargs + [svn_url],stdout=sp.PIPE,stderr=sp.PIPE) out,err = popen.communicate() 2. input_ = “”” … Read more

[Solved] Parsing a char inside an if c#

There are some issues with your code. First, you do an assignment operation and not equality (single = vs ==) Secondly, if you have a string and want to check if one of his characters is space, you could do: string myString = “This is a string”; foreach (var c in myString) { if (c … Read more

[Solved] Regex for this date format?

Split the task into 3 parts. First, a number in the range of 1-31 (tutorial), then a list of possible values for the month, and then two numbers. \b([1-9]|[12][0-9]|3[01])-(Jan|Feb|Mar|Apr|May|Jun|Jul|Aug|Sep|Oct|Nov|Dec)-(\d{2})\b Regex101 Demo 3 solved Regex for this date format?